How do I solve this nonlinear systems of equation problem?
Following up on Michael Jørgensen's answer:You substitute the second equation (y= f(x)) in the first, resulting in a quadratic equation for x, which has explicit roots. You then verify if the roots are such that both x and y lie in [-1,1]. When you have found such roots, you find alpha and beta using arcsin(x) and arccos(y).
How do I solve this nonlinear system of equations problem?
x^2-4x-y=4 x^2+y=2Add the two equations:2x^2-4x=6x^2-2x = 3x^2-2x-3=0x^2-3x+x-3=0x(x+1)-3(x+1)=0(x-3)(x+1) = 0x1 = 3, x2 = -1Then we can use x to find y:x1^2+y1 = 29+y1 = 2y1 = -7x2^2+y2=21+y2=2y2=1Final solutions:(3,-7) and (-1,1)
Nonlinear system word problem ::(( help!!?
i cnt figure out this word problem could someone pls show me how to do it?? i can find the answer but i need the work. This is it: A bird is flying upwards such that its height in feet after t seconds is given by h = 4t. At the instant the bird passes the height of a ball being held out of a window, the ball is thrown upward with an initial velocity of 80 feet per second. The height in feet of the ball after t seconds is given by h = -16t2 + 80t. Find the time it takes for the ball and the bird to reach the same height
Solve this nonlinear systems of equations?
Are you sure about that first equation? It reduces to 13x^2 - 3xy = 15 The solutions you give work in the second equation, but the first I get 4 * (2)^2 - 3 * 2 * 1/3 + 9 * (2)^2 16 - 2 + 36 50 So that's not working. Anyway, here's how it would be solved. 3y = 5 - 2x 13x^2 - x(3y) = 15 13x^2 - x(5 - 2x) = 15 13x^2 - 5x + 2x^2 = 15 15x^2 - 5x - 15 = 0 5(3x^2 - x - 3) = 0 x = (1 +/- sqrt((-1)^2 - 4 * 3 * -3)) / (2 * 3) x = (1 +/- sqrt(1 + 36)) / 6 x = (1 +/- sqrt(37)) / 6 So, yea, I think there's a typo, but that's how you would solve it. Come to think of it, it looks like you meant to type 4x^2 - 3xy + 9y^2 = 15 If so 4x^2 - x(3y) + (3y)^2 = 15 4x^2 - x(5 - 2x) + (5 - 2x)^2 = 15 4x^2 - 5x + 2x^2 + 25 - 20x + 4x^2 = 15 10x^2 - 25x + 10 = 0 5(2x^2 - 5x + 2) = 0 x = (5 +/- sqrt((-5)^2 - 4 * 2 * 2)) / (2 * 2) x = (5 +/- sqrt(25 - 16)) / 4 x = (5 +/- sqrt(9)) / 4 x = (5 +/- 3) / 4 x = 8/4 or 2/4 x = 2 or 1/2 2(2) + 3y = 5 4 + 3y = 5 3y = 1 y = 1/3 (2, 1/3) 2(1/2) + 3y = 5 1 + 3y = 5 3y = 4 y = 4/3 (1/2,4/3)
Is it possible to solve a nonlinear equation system (no approximation) using a direct method (non iterative)?
Is it possible to solve a nonlinear equation system (no approximation) using a direct method (non iterative)?Yes! The simplest example is the famous solution[1] to a quadratic equation:[math]\quad ax^2+bx+c=0\Rightarrow x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}[/math]Footnotes[1] Quadratic formula
Anyone good with nonlinear and linear word problems with angles?
Start by putting the question into mahematical terms. so for example 1st angle is x, 2nd angle is y, 3rd angle is z Then have the fomulas: x + y = z + 104 y - z = 3x x + y + z = 180 (always true for a triangle) You can then solve, as you have 3 equations and 3 unknowns. eq1 - eq 3: -z = z + 104 - 180 => z = 38 degrees eg 1 - eq 2: x + z = z + 104 - 3x => x = 26 degrees eq 3: y = 180 - x - y => y = 116 degrees
Give all the solutions to the nonlinear system, including those with nonreal complex components.?
Use the second equation to isolate x in the first equation. 3x^2+2*(x+1)^2=14 3x^2+2x^2+4x+2=14 Solve the above for x (both solutions) and then use the second equation to solve for y (both solutions!)