How to get something off my roof?
spray it off with a hose
Physics: How to find distance and time an object falls?!?!?!?
First of all think of the hammer sliding down the roof. It has a constant velocity of 3.7m/s, but this is measured along the roof surface which is at an angle of 29° with the horizontal. Now you have to know that the hammer has a horizontal component of velocity as well as a vertical component of velocity. You resolve the hammer velocity into a vertical and horizontal velocity component 1. Vertical velocity component = 3.70*sin 29° = 1.794m/s 2. Horizontal velocity component = 3.7*cos 29° = 3.236m/s Question a) use the equation s = ut + ½*a*t² 35 = 1.794t + ½*9.81*t² 4.905t² + 1.794t - 35 = 0 t = 2.49 seconds (ignore -2.86) Question b) The hammer is in the air for 2.49 seconds. Its horizontal velocity is 3.236m/s Horizontal distance traveled = 2.49*3.236 = 8.06m
If I leave an object drop in a moving vehicle, why won't it land at a more backwards point, since while it was dropping the vehicle kept on moving?
This is a problem of reference frames! While the car is travelling at 100km/h, the object you drop is also travelling at 100km/h as the car has accelerated you, and the object you are going to drop to the same speed. Ie. you, the object, and the cars interior are all at rest in the reference frame of the car. Therefore if you drop the object, it has no translational velocity in your reference frame, and appears to fall straight down. If you were to cut out the side of the car, and observe this experiment standing still on the reference frame of the Earth, it would appear that the object would translate in the direction of the car, but would still land exactly below where you dropped it on the floor of the car. Now if you were to drop the object while accelerating the vehicle the object would land at a more backwards point. This is because after the object has been dropped, the car can no longer exert a force to accelerate the object along with the car. The object will experience no acceleration, whereas the car will feel acceleration. This will cause the object to no longer be at rest in the reference frame of the car, and it will travel with some accelerating velocity until it hits the ground of the car at some position back from where it was dropped.
What are the small objects on the roof for in Colorado? Is it something to do with snow/ice?
If you are talking about what are usually a double row of things that stick six inches or so then they are to keep the ice and snow from sliding off the roof in a sheet and hurting or killing someone. Snow and ice are heavy and will seriously hurt someone if a big chunk landed on a person.
Piles of snow on slippery roofs can become dangerous projectiles as they melt. Consider a chunk of snow at the
ridge of a roof with a pitch of 30°. (a) What is the minimum value of the coefficient of static friction that will keep the snow from sliding down? (b) As the snow begins to melt, the coefficient of static friction decreases and the snow eventually slips. Assuming that the distance from the chunk to the edge of the roof is 5.2 m and the coefficient of kinetic friction is 0.20, calculate the speed of the snow chunk when it slides off the roof. m/s (c) If the edge of the roof is 10.0 m above ground, what is the speed of the snow when it hits the ground? m/s
Physics Homework: Angle when object falls off sphere?
Hello everyone, I'm having a little problem with this physics question. So the question asks for the angle with the vertical at which an object that is sliding (frictionless) off a sphere leaves the surface of the sphere. I did some physics and got 48.19 degrees, which is correct. However I'm having trouble with the second part of the question. The question asks why the angle is 48.19 degrees and not 45 degrees. I really need the answer ASAP, it counts for a lot of points. It says to answer the question mathematically or through words. Thanks so much in advance
Piles of snow on slippery roofs can become dangerous projectiles as they melt. Consider a chunk of snow at the?
Piles of snow on slippery roofs can become dangerous projectiles as they melt. Consider a chunk of snow at the ridge of a roof with a pitch of 34°. (a) What is the minimum value of the coefficient of static friction that will keep the snow from sliding down? (b) As the snow begins to melt, the coefficient of static friction decreases and the snow eventually slips. Assuming that the distance from the chunk to the edge of the roof is 5.0 m and the coefficient of kinetic friction is 0.20, calculate the speed of the snow chunk when it slides off the roof. (c) If the edge of the roof is 8.0 m above ground, what is the speed of the snow when it hits the ground? I can't get part c, though for part a and b, i got a).67 b)6.17
If ice fell off the roof and damaged my vehicle, who pays?
Was it your roof? Most homeowners policies will cover things of that nature as long as they are within the homeowners control. If you slip and fall on someone’s sidewalk because they have not maintained properly such as a snow or ice storm, typically they are held liable. But a homeowner typically does not have the ability to mediately clean their roof of any snow or ice, so this may fall underneath of the “Acts of God” clause.However, usually anything involved with a vehicle, goes on vehicle insurance.I will assume it’s not your roof, so I would ask the homeowner if their policy covers that. If you can find out who their insurance provider is, you might be able to see if they are covered, however if they are a friend, they may not be when you are through.If it’s your roof, just talk to your agent to find out how they would like to proceed especially if the damage is significant. Standby to pay your deductible and watch your rates go up if this is your circumstance