Algebra word problem help?
s is the amount of sweatshirts and t is the amount of tshirts 2.50s + 1.50t = 1200 2.50s = 1200 - 1.50t s = (1200 - 1.50t)/2.50 s = 480 - 3/5t s can't be negative so: 0.6t <= 480 t <= 800 s must be an integer so 5 must divide into 3t (so that 3/5t is an integer). So 3t must be a multiple of 5. So for 3 values: 3t = 5, 10, 15 t = 5/3, 10/3, 15/3 Woops t has to an integer too so 3t must be a multiple of 3 as well. So we have to find the common multiples of 5 and 3: 3t = 15, 30, 45 t = 5, 10, 15 Substituting back into our orginal equation: s = 480 - 3/5t t=5, s = 480 - 3/5(5) = 480 -3 = 477 t=10, s = 480 -3/5(10) = 474 t=15, s = 480 -3/5(15) = 471 Basically you choose any number you want for t as long as it's a multiple of 5 or t=0 and less than 800. Our three amounts of sweatshirts and tshirts are: 477 sweatshirts, 5 tshirts 474 sweatshirts, 10 tshirts 471 sweatshirts, 15 tshirts
Word Problem help in Algebra I?
Distance = Rate X Time D = RT Since we have two different rates and two different times, but the distance is going to be the same, we're going to end up with an equation like this RT of the bus = RT of the car but R and T are going to be different on each side. Little bit confusing? Maybe. R of the bus = 30 mph T of the bus is what we're looking for, so we'll just call it T R of the car = 45 mph T of the car = 15 minutes less than T of the bus Notice that the rate uses hours and the time uses minutes. We have to have them the same. 15 minutes is 1/4 of an hour, so to put that in hours it's .25 which makes T of the car T-.25, since T is the time of the bus. 30T = 45(T-.25) 30T = 45T - 11.25 -15T = -11.25 T = .75 Remember we made it in hours, so that's .75 hours, which is 3/4 hours, or 45 minutes. That is how long it took the bus. Since the bus left at 11:45, add 45 minutes to that and the car caught it at 12:30 --- For Ellen and Kate, again the Distance is the same. Ellen's T is 15 minutes less than Kate's. So if Ellen is T, then Kate is T+.25 (the speeds are in mph again) 12T= 9 (T+ .25) 12T = 9T + 2.25 3T = 2.25 T = .75 So it took Kate 45 minutes to get to the library. They left at 3:00 pm so she got there at 3:45 pm
HELP!!! word problem!!?
okay i really need help idk how to solve this problem because i'm really bad at word problems because my teacher that i have can't teach for crap hahah sorry but its the truth. okay here's the word problem: At a state fair, each ride costs $1.50. On average, 50 people per hour take rides. For each 25-cent increase in the cost of rides, the number of people taking rides drops by 5 per hour. Find the cost of each ride at the fair to obtain maximum income from the rides
Need help with Halloween Logic word problem?
Okay so I need help with this word problem, goes like this: Six children were excited with Halloween a few days away. Bobby and the others all had different costumes and they were all anxious to go out to play trick or treat. Mrs. Jones was going to chaperon her own child and five of the neighbors' children, including the child whose last name is Post. From the following clues, determine the first and last names of each child, the age of each child and the costume worn by each. 1. The oldest girl is 7. Mary is 2 years older than the Jones girl buy younger than her own brother Richard. 2. Only one child is 7 and no child is older than 7. 3. Mary's brother wore the devil's costume. 4. John is 1 year younger than Mary and 3 years younger than Jane. 5. The Kerns girl, who is not Jane, wore the princess costume. 6. Richard is not the Hartt boy and he did not wear the witch costume. 7. The Wiley boy was not Frankenstein or the bunny. 8. The witch was older than the bunny and younger than Frankenstein. If anyone can figure this out and post it that'd be amazing, thanks!
Algebra 1 word problem please help!?
In a scale model of a sailboat a figure 8 inches tall represents an object that is 6 feet tall. How tall should the model boat be if the boat is 38 feet tall? I need all the layers/steps. PLEASE HELP
Algebra 2 word problem?
Haha, okay. So her balance has to maintain at least 500$. This means the end of the problem will be: ≥500 Now, knowing that the rent is 750 I must subtract that from 3800 to get 3050. That 3050 describes how much Jan has left to spend on anything. For 'anything' we will you the variable x. X could be clothes, shoes, ect. Your ending equation will be 3050 - x ≥ 500 Hope that helps -S ;D
Math help needed linear systems word problem?
Ok, so i have had all this homework because ive been sick the last few days, and this is the only thing I don't get out of all my math homework and I have a test tomorrow, I dont want to postpone my test because I already missed another one from being sick that I still have to do. So, its a word problem that needs 2 equations because its a linear system. I dont need the solution just the 2 equations, thanks. A play-off football game between the Eskimos and Stampeders drew 36 500 fans. Depending on the seat location, the ticket prices were $35 and $20. The total REVENUE from the ticket sales was $940 000. So once again, please I just need the 2 equations to create a linear system, no solution needed. Also if you can please show me how you made the 2 equations, thanks!
How do I solve this mathematical word problem?
If you examine 400 deer and find 30 tags, then if you examine 800 deer you'd expect to find 60 tags. You asked for an 'estimate', which I interpret to be a BOTEC (back of the envelope calculation), an effective strategy by itself for many situations, and a powerful strategy for 'checking your answer' if you do the math explicitly. Without doing any further 'math', a good estimate would be 'somewhat more than 800', or about 1,000. Note: The BOTEC agrees with the other explicit answers provided. Do not expect a BOTEC to be accurate within 5-10%, but it can serve as a reality check very quickly and easily. Try this one: Pencil and paper, no Google, no calculator; you have 60 seconds. The Empire State Building is 102 stories tall. You are given a container of nickels that reach from the ground to the roof in a single stack. You are in a room with 1 sq-ft floor tiles and a 20-ft ceiling. Can you stack all the nickels on a single floor tile? How high will the stack be?
Help with Algebra word problems!!! 10 pts for best answer!!!!?
Ok, I've been working really hard on this packet of word problems and there is four that I can not figure out. I need help finding how you would set these up as an equation, using one or two variables. My own parents are having trouble helping me. 1. The length of the sides of a triangle are in the ratio of 5 to 12 to 13. The perimete of the triangle is 90 cm. Find the length of each side. 2. The measures of a triangle are given by consecutive integers, each indicating a number of inches. If the perimeter is 6 feet, find the length of each side. 3. In Paul's bank, there are $2.60 in pennies, nickels, and dimes. IN all there are 45 coins. If there is twice as many nickels as pennies, find the number of each kind of coin. 4.A newsboy notices that he has four times as many dimes as quarters. IF his dimes and quarters total $1.95, how much of each coin does he have? NOTE: I only need to know how you would set these up as an algebraic equation. I can find the answer once i get the equation.