Organic Chemistry Questions - Sn1, Sn2, E1?
Radical halogenation of your starting alkane would NOT be a practical synthesis of 2-chloro-3-ethylpentane since it would be only 1 of several products formed. A practical synthesis is one that produces only the desired product or a easily separable mixture that predominates in the formation of the desired product. Radical halogenation would not do either of these. Instead, either you've listed the incorrect starting material or your synthesis will involve a rather elaborate set of conditions. For the latter, you can perform an methine oxidation (hydroxylation after work-up) with ozone on 3-ethylpentane to get 3-hydroxy-3-ethylpentane, which can be eliminated in acid, and, finally, chlorinated in HCl (chlorine adds to the least substituted carbon)... Hope this helps!!!
Crazy hard organic chem question!?
Hey, thanks to all those that help with info ;) Here is the image needed to solve this problem: http://i435.photobucket.com/albums/qq78/... let me know if the link doesnt work Well, here is the question: The most important way to make alkenes is through base-promoted 1,2-elimination (sometimes called β-elimination). (a) When 3-bromo-2,2-dimethylbutane is heated with dilute solution of sodium ethoxide in ethanol or with ethanol alone, reaction follows first-order kinetics; along with substitution, there also occurs elimination to yield alkenes I and II (illustrated below). Propose a likely mechanism for the reaction which these alkenes are formed under these conditions. (b) When the same halide is allowed to react with a concentrated solution of sodium ethoxide in ethanol, reaction follows second-order kinetics; again elimination accompanies substitution, this time to yield, not alkenes I and II, but alkene III. Propose a likely mechanism or mechanisms for the elimination taking place under these conditions. (c) What substitution product or products would you expect in each case? Draw and name these substitution product or products. I know its hard to do this in this particular forum... Any info to any parts greatly appreciated!!! Thanks
Organic Chem lab question?
PLEASE EXPLAIN A mixture of phenol (PhOH) and benzoic acid (PhCOOH) was partitioned between diethyl ether and 5% aqueous NaOH. The top layer was discarded; the bottom layer was acidified with 5% aqueous HCl and extracted with ether. Combined ethereal extracts were evaporated. What will be the composition of the residue after evaporation? A. Pure phenol B. Pure benzoic acid C. Mixture of both phenol and benzoic acid D. It will be no residue after evaporation E. There is not enough data to solve this problem
ORGANIC CHEM QUESTION?
explain why tlc is not suitable for use with compounds that have boiling points below about 150C (760torr), and whyt should the spot not be immersed in the solvent in the developing chamber ?
A few Organic Chemistry Questions?
lol...these questions are easy (5 minutes to answer) but typing structural formulas in this format is difficult (>one hour!). . 1, Not sure I understand the question. but... Functional groups determine the properties and reactions of organic cmpnds to a large extent. Eg, 'heavy' atoms such as Cl tend to increase boiling point; hydrophilic groups such as OH can increase sol in water. Alcohols can be esterified by acids, whereas ethers cannot ROH + R*COOH-->R*COOR ROR** + R*COOH...no reaction Amines form salts, whereas nitro cmpnds cannot RNH3 + HCl-->RNH3.HCl RNO2 + HCl...no reaction (Is this what teach wants?...you find more examples.) 2. (X is for Cl, to avoid confusion with C) CH2=CH-CHX2... CH2=CX-CH2X... CHX=CH-CH2X CX2=CH-CH3... CHX=CX-CH3 CH2 CHX-CHX CH2 CH2-CX2 These are triangular...draw bonds connecting all carbons...bot will not allow better depiction. 3. X is acetic acid CH3COOH Y is methyl formate HCOOCH3 X solidifies sl below RT(if pure), Y boils sl above RT X is neutralized by a base (eg titrating w NaOH), Y is neutral 4. CH2=CHCH2CH2CH2CH3 1-hexene CH3CH=CHCH2CH2CH3 2-hexene CH3CH2CH=CHCH2CH3 3-hexene (CH2)6...draw as a ring... cyclohexane (note -ane, not -ene) Hope this is not simply an easy way to get your homework done...at least study the answers to learn something...you're on your own in a test remember.
Qualitative Organic Chem Question.?
Common sense dictates that crystallization of a compound can only occur if the compound that you're trying to crystallize is a crystalline solid. Crystalline solids are generally polar molecules that can freely interact with neighboring molecules to form a lattice (a uniform, geometric distribution of like molecules). Keep this in mind while I answer your question. 1) ethanol vs octanol - Ethanol is a better crystallization solvent because of two main factors. First, octanol is much more lipophilic than ethanol. This means that octanol likes lipids more than ethanol. And since lipids are not crystalline solids but, rather, waxy solids at best, octanol is the poorer solvent of the two to use for crystallization. Ethanol, on the other hand, is the better alcohol to use in crystallization because it is better at dissolving polar compounds that are less lipophilic and more crystalline in nature. Reason #2: 1-octanol, with a bp of 195 degrees C, is much more difficult to remove than ethanol when drying a cyrstalline solid. 2) hexane over pentane - These two solvents are very similar. The only thing I can think of is bp. Heptane is the shortest chain length hydrocarbon that is a liquid at room temp. It has a boiling point of 36.1 degrees C. Hexane has a bp almost twice that amount, 69 degrees C. And since the best crystallization technique requires that a the solution evaporate slowly, a higher bp than 36 degrees is preferred. 3) water over methanol - Water is innocuous in every way. It's not toxic, not expensive (relatively speaking), and easy to remove by drying in a vacuum oven or even in an open air environment. Any time that water can be used as a solvent for anything, it is the preferred choice. Hope this helps!!!
How many questions are asked from Organic Chemistry in the NEET?
10
How do I solve organic chemistry questions on NEET?
First of all your concepts for organic chemistry should be crystal clear …..go through d NCERT first nd learn all d name reactions there are around 28–29 name reactions memorize all of them….then go for d reagents and tests that which compound gives which test …ex- NaHCO3 IS THE TEST FOR CARBOXYLIC ACID .: LiAlH4 is a strong reducing reagent. So whenever it is given as reagent, you can just reduce the reactant to obtain the product. Same goes with other reagents too, like KMnO4, NaBH4 etc.While forming products keep these things in mind : Aromaticity, Ring Expansion and Contraction, Methyl and Hydride shift.ND when u are done with this solve previous year questions or u can solve any of the question banks or modules..STILL there is a lot off time so go through d chapters nd don’t get PANIC .!!HOPE IT HELPSBEST OF LUCK..!
Can someone help me with a General / Organic Chem question regarding Osmosis?
Here is the question. I am not entirely sure what to do here.... help would be greatly appreciated.... Thank you ;-) Two compartments are separated by a semipermeable osmotic membrane thought which only water molecules can pass. Compartment A contains a 0.3 M KCl solution, and compartment B contains a 0.2 M Na3PO4 solution. Predict from which compartment the water will flow to the other compartment. If you could provide a brief explanation, I would greatly appreciate it. Thank you, again.