I have a few physics questions?
Which of the following would have more momentum? Choose one answer. a. 45-kg leopard running 60 km/h b. 250-kg wildebeest running 20 km/h c. 50-kg cheetah running 90 km/h d. 150-kg lion running 48 km/h An egg is dropped from a height of one meter. Explain the concept of impulse and explain how the impulse of the egg can be changed so that it won’t break? Short Answer. What is the potential energy of a 500-N rock sitting 100 meters high atop a cliff in the Grand Canyon? Show all work and include formula(s) and units. Short Answer. What is the gravitational force between the earth and the moon if the distance to the moon is 3.85 x 108 m? The mass of Earth is 5.98 x 1024 kg and the mass of the moon is 7.36 x 1022 kg. Choose one answer. a. 1.98 x 1020 N b. 7.64 x 1028 N c. 2.97 x 1030 N d. 1.26 x 1039 N If an object moves twice as close to the Earth, it’s weight would Choose one answer. a. decrease by a factor of 2. b. decrease by a factor of 4. c. increase by a factor of 2. d. increase by a factor of 4. Which of the following is not a source of potential energy? Choose one answer. a. a stretched rubber band b. a hamburger c. a wind-up toy that has been wound d. a ball sitting on the ground A 1,000 kg car sitting at a red light is hit from behind by a 1,200 kg car moving at 20 m/s. The two cars lock bumpers and continue to move forward. What is the velocity of the cars after the collision? Choose one answer. a. 1.1 m/s b. 9.1 m/s c. 10.9 m/s d. 20 m/s
Physics Question - (Linear Momentum & Collisions)?
Problem Solving 7.68 Soccer player 1 has a mass of 45 kg and moves to the right with a speed of 1.4 m/s. Soccer player 2 has a mass of 32 kg and moves to the left with a speed of 2.1 m/s. What is the magnitude of the total momentum of the two players? I've tried this problem a few times a few different ways and it keeps telling me that my answer is incorrect. So I have absolutely no idea how to do this problem. I thought that you would have found the momentum for both of the players and then added them together, but I guess that is wrong. So can someone help me with this problem? Also, in a previous question dealing with the momentum I entered the units wrong so please include the correct way to input the units please! Thank you to everyone for your help! :D
Conservation of Momentum Physics question?
A 5580 kg open train car is rolling on frictionless rails at 23.1 m/s when it starts pouring rain. A few minutes later, the car's speed is 19.3 m/s . Assume that the train car is rolling to the right (positive direction) before the rain begins. the momentum of the car before the rain is pi = 1.29×105 kg⋅m/s What mass of water has collected in the car? Please explain
(easy) Physics momentum question?
long complicated equations are not very useful. Use common sense and a few basic equations. impulse is change in momentum. a) initial momentum P = mV = 22*10 = 220 kgm/s final momentum P = 22*8 = 176 change in momentum (assuming the velocity is in the same direction) ∆P = 220 – 176 = 44 kgm/s b) final momentum = 176 in opposite direction change in momentum ∆P = 220 + 176 = 396 kgm/s .
Physics momentum problem help?
A 79.0 kg rider sitting on a 6.6 kg bike is riding along at 9.9 m/s in the positive direction. The rider drags a foot on the ground and slows down to 6.0 m/s still in the positive direction. a)What is the change in momentum of the rider and bike? b)What is the impulse delivered by the ground to the rider's foot? c)What force is acting on the bike and rider if slowing down took 14.2 seconds? d)And, how far did the bike and rider travel during these 14.2 seconds?
Please help me with physics momentum question 10 pts?
Your first 3 questions can all be answered with the same explanation. The impulse momentum theorem: ∆p = F * ∆t (change in momentum equals force times change in time) In all three of your questions there is some object moving and it is brought to a stop (velocity of zero). for the dashboard, your head is moving and then comes to a stop, for mountain climbers, if they fall the rope brings them to a halt, same thing when you jump and fall you stop when you hit the ground. So rearrange the equation: F = ∆p / ∆t ∆p is constant because it has some momentum, and then when it stops it has zero momentum, so the change in momentum is the same regardless of if the dashboard is padded (for example). However, if the time is larger then the force will be smaller. That's because you will be dividing ∆p by a bigger number. So to make the force smaller we need to change the momentum over a longer period of time. That should explain your first 3 questions, the padded dashboard make it take longer to stop, same thing with nylon ropes (which will stretch and apply the force over a long period of time), and again, same thing with your knees, they bend as you land. you could say that the force is "spread out" over time, so it's not a sudden impact but sort of eases to a halt. I'm sure your common sense would be able to tell you that a padded dashboard is safer than a solid wall in a head on collision lol... but now you know exactly why, and that reason is time. For your last question. No firing a bullet that is that heavy is pointless. Because we assume that the force applied to the bullet by the gunpowder is the same regardless of mass, so look at the equation: F = m*a divide the force by a bullet of small mass and you'll get a larger acceleration. Then divide the force by the bullet with enormous mass and you'll get a very small acceleration. The bullet in question would probably travel a few feet before hitting the ground... if that.
I have a few questions about momentum and work in relation to physics. Help?
1) Work = (force x distance), so if you double force, you double the work. Likewise, if you double the distance, work doubles. So, doubling both = 4 x the work done. 2) Distance = (v^2/2a) will show this. The acceleration in each case will be identical. I choose 0.1km/sec^2 acceleration. (100^2/0.2) = 50,000. (50^2/0.2) = 12,500. Those are just rough examples, but will serve to ilustrate the distance needed to stop from double the speed = 4 x greater. 3) Will decrease, as the mass (and the velocity) of the aircraft will be less. It loses momemtum. It is less the mass of the bullets fired, and the velocity is lessened by the reaction force to firing forwards. Momentum = (mass x velocity).
A physics problem on change in momentum?
This problem was on an exam I took a few weeks back. I got the right answer then, but I can no longer get it for some reason and it's driving me crazy. A 1200 kg automobile headed east at 40 m/s collides with a 9000 kg truck headed west at 30 m/s. If they stick together, what is the change in momentum of the truck in the collision? The answer is 74,000 kg * m/s, East Any help figuring this out would be greatly appreciated!
Momentum Physics Problem?? Help plz!!?
I am stumped on this problem. It's from an online hw and I've already used 3/7 attempts and I don't wanna lose anymore points. Idk, i thought you just plug it in to the formulas but i guess im using the wrong ones or idk. Please help me. It's New Years Eve and I'm stuck doing this work because my teachers think that we have no lives so it's necessary to give us work. Thank you! All help is appreciated greatly! :) 007 (part 1 of 4) 1.0 points Calculate the momentum for a 0.1 kg rifle bullet traveling 400 m/s. Answer in units of kg · m/s 008 (part 2 of 4) 1.0 points What momentum does a 1300 kg automobile traveling 0.3 m/s (a few miles per hour) have? Answer in units of kg · m/s 009 (part 3 of 4) 1.0 points What momentum does a 70 kg person running 11 m/s (a fast sprint) have? Answer in units of kg · m/s 010 (part 4 of 4) 1.0 points What momentum does a 17000 kg truck traveling 0.02 m/s (a slow roll) have? Answer in units of kg · m/s