Physics Pendulum Question

Physics pendulum question?

A 100g mass is attached to a 1.0m long string, thereby forming a pendulum. The mass is pulled 4.0 degrees to one side and released. How long does it take for the pendulum to reach 8.0 degrees on the
opposite side?

Any help would be greatly appreciated!

Physics pendulum question?

I don't understand why is the answer for this question T/10.
A pendulum swings backwards and forward passing through G, the middle point of the oscillation. The first time the pendulum passes through G, the stopwatch is started. The 21st time the pendulum passes through G, the stopwatch is stopped. The reading is T. What is the period of the pendulum?

Physics Pendulum Question?

A pendulum undergoing simple harmonic motion has an amplitude of 0.130 m and a period of 8.50 s. How long will it take the pendulum to go from x = 0 cm to x = 8.12 cm?

Physics question. Pendulum?

This is a fun problem

This is a Energy problem at heart
Intial PE of the pendulum = m*g*h

h = L - L*cos(theta)
theta = asin(15/L)

At the bottom of the swing, all the PE is transferred into KE
KE = 1/2m*v^2

m*g*h = 1/2*m*v^2

v = sqrt(2*g*h)

Now, here's the tricky part

The arc length of the pendulum from the top of the path to the bottom of the path:
Arc = L*theta (remember to use radians)

We don't know the acceleration of the bob or the time it takes to reach the bottom
acceleration:
from vf^2 = vi^2 + 2*a*d
a = vf^2/(2*Arc)

time:
from vf = vi +a*t
t = vf/a = 2*arc/vf

That is the time it takes to go from the top of the swing to the bottom. However, that is only 1/4 of the distance needed to travel

ttotal time = t*4 = 8*arc/vf

Pendulum question physics?

A) T = Frsin(theta)
T = [(mass)(acceleration)](distance between weight and pivot)sin(angle between lever and applied force)
T = [(3)(9.8)](2)sin(5)
T = 5.13 N m
Torque = 5.13 Newton meters

B) You use the same equation:
T = Frsin(theta)
T = [(mass)(acceleration)](distance between weight and pivot)sin(angle between lever and applied force)
T = [(3)(9.8)](2)sin(15)
T = 15.22 N m
Torque = 15.22 Newton meters

Hope this helped.

Physics question about pendulums?

Viewed edge-on the string forms the hypotenuse of a triangle with the adjacent side located where the string hanging at rest would be. The opposite side has length equal to the radius of the base of the cone. The angle subtended by the string while swinging with the position where hanging is :

sinθ = opposite / hypotenuse
θ = tan⁻¹(0.30m / 1.0m)
θ = 17.5°

From Newton's 2nd law, the forces acting vertically are :

ΣF = 0 = Tcosθ - mg

Solving for T :

T = mg / cosθ
= (0.600kg)(9.80m/s²) / cos17.5°
= 6.17N

Pendulum clock physics question?

Help i keep on trying this but i can't get it:

A grandfather clock can be approximated as a simple pendulum of length 1.20 m and keeps accurate time at a location where g = 9.83 m/s^2. In a location where g = 9.78 m/s^2, what must be the new length of the pendulum, such that the clock continues to keep accurate time?

Physics Question-Oscillation of a Pendulum??????

You need to use the equation f=1/T (frequency = 1/Period)

So to find the period the formula becomes T =1/f

In the case of your example it is T=1/8 = 0.125

So the answer is 0.125 seconds.

Hope that makes sense.

Good luck

PHYSICS - PENDULUM question. Please help me ^o^?

An astronaut swings a pendulum on the moon, which has a length of 1 m and oscillation period of 4.916 seconds. Calculate the acceleration due to gravity on the moon. By what factor is the earth's gravity stronger? Calculate ge/gm.

Thank you so much!