Break even point for precalculus :/ please help?
C(x) = 5.5√x +10000 R(x) = 3.29x So when you set R=C 3.29x = 5.5√x +10000 3.29x -5.5√x -10000 = 0 Think of this as a quadratic in √x, since x = (√x)^2 Thus √x = [ -b ±√(b^2-4ac) ] / 2a = [ -(-5.5) ±√((-5.5)^2-4(3.29)(-10,000)) ] / 2(3.29) = [ 5.5 ±√((5.5)^2 +131600) ] / 6.58 = [ 5.5 ±√131630.25 ] / 6.58 = [ 5.5 ±√131630.25 ] / 6.58 = [ 5.5 ± 362.8 ] / 6.58 = 368.3/6.58 or -357.3/6.58 = 55.97 or -54.3 The -ve solution is probably extraneous so we discard it. => x = (√x)^2 = (55.97)^2 = 3133 units
Pre-Calculus Help: Maximizing Profit and Breaking Even?
x unit of awareness will generate Revenue 5x Total cost for x units 50+(.1+,2+...+.1x)= =50+.1(x+1)x/2 =50+.05(x+1)x function Profit P(x)=5x-[50+.05(x+1)x] P(x)=-.05x^2+4.95x-50 to find break even solve .05x^2-4.95x+50=0 for whole numbers multiply by 20 x^2-99x+1000=0 x=(99+sqrt(5801))/2 x=(99-sqrt(5801))/2 two break even x~88 x~12 max profit, for P(x)=-.05x^2+4.95x-50 when x=(88+12)/2=50 vertex of parabola is at (x1+x2)/2
Help with a revenue function problem? (find the number of units sold x that produces a maximum revenue?)?
The revenue function in terms of the number of units sold ,x, is given as R=280x - 0.1x^2 where R is the total revenue in dollars. Find the number of units sold x that produces a maximum revenue? x= What is the maximum revenue?
How do I calculate a final grade with percentages?
MethodFinal Grade = (Grade 1 x 60%) + (Grade 2 x 40%)Short ExamplesQ1. What is the Final Grade if Grade 1 is 95 and Grade 2 is 70?A1: Final Grade = (95 x 60%) + (70 x 40%) = 57 + 28 = 85Q2. What is the Final Grade if Grade 1 is 55 and Grade 2 is 43?A2: Final Grade = (55 x 60%) + (43 x 40%) = 33 + 17.2 = 50.2Long ExamplesQ1. What is the Final Grade if Grade 1 is 95 and Grade 2 is 70?M1: Final Grade = (Grade 1 x 60%) + (Grade 2 x 40%) = (95 x 60%) + (70 x 40%) = (95 x 60/100) + (70 x 40/100) = (5700/100) + (2800/100) = (57) + (28) = 85A1. Final Grade = 85Q2. What is the Final Grade if Grade 1 is 55 and Grade 2 is 43?M2: Final Grade = (Grade 1 x 60%) + (Grade 2 x 40%) = (55 x 60%) + (43 x 40%) = (55 x 60/100) + (43 x 40/100) = (3300/100) + (5020/100) = (33) + (50.2) = 50.2A2. Final Grade = 50.2
I am very weak in maths. How can I develop it?
I'm very weak in Maths, or I don't know whether it's something that I, myself developed over the years. From my 7th grade, I started loosing interest in Maths since my teacher wasn't that good and she only appreciated students who did well and insulted us very badly. From that year, I just gave up my hopes on Maths and considered it as a shitty subject and pretended like I didn't care when I was really really very sad on getting very low marks in Maths when I was an excellent student in the class and scored more than 91% in other subjects, Maths always bought me down when it came to ranks. I was so depressed, I started hating Maths, and it became a nightmare for me. The day before the exam, all I remember doing was crying, crying and crying. I couldn't bear the tension it gave me. It still does. I suffer from anxiety even though I'm young; and no one is allowed to put so much pressure on me because it's trouble. Whatsoever, I still have chills and I failed in this year examination and writing a retest on Monday, and this time, I just googled whether there's anything I could do to score better in Maths, and that's when I read this interesting article and found out that I'm not alone. Because this is exactly like my story. I'm weak, I always get the just-pass marks, my brother is a top-scorer who is hopefully cracking a AIIMS soon and has 95% marks in his 12th grade and all, and I left a group tuition cause I was insulted and then joined a tuition where I used to be the only student, and I'm continuing that, but the thing I failed to keep is being regular. I'm never regular to the tuition because I hate maths firstly and I'm a lazy girl who spends her weekend by watching new movies, with drinks and chips and popcorn and stuff and going out every weekend for shopping with my family or friends, or going to stay at cousin's or mom's or spending quality time with my best friends or my best-friends-cum-family my cousins..Okay! I've told too much. I hate maths. No, I hated it. Not anymore. I'm going to pretend like I love it and work hard. I've got 5 days from now, that's like huge time to cover 6 lessons and then practice extra questions and sums. Well then! Let's see how I'll score and whether the hardwork will pay off! Fingers crossed! Maths!! HERE I COME BROTHER.
How is 10th ICSE board percentage calculated?
The procedure for calculating 10th I.C.SE. board examination percentage is pretty simple.You might be shocked to know that physics, chemistry and biology have the least weightage in percentage.So, I should first tell you that you all are studying only 6 subjects and they are —MathematicsComputer/ P.ed. ( Optinal subject )Hindi ( Regional language)Science ( Physics + Chemistry + Biology)English ( Language + Literature)Social Science ( History/ Civics + Geography )So all these six subjects have 100 marks overall out of which you will give 80 marks examination and 20 marks will be given by the school based on internal assessment and projects ( except for computer in which examination will be of 100 marks ).In science, your physics, chemistry and biology marks are added up and then divided by 3 to get science marks. Same is done in social science and english and in these both subjects and added and divided by 2.Then the best five subjects are selected, which means that the subject with the least marks is not taken into consideration.Then the marks of best five subjects are added and then divided by 500 and then multiplied by 100.Brief summy —Select the best 5 five subjects then use the following formula to calculate your percentage where ‘S’ is the sum of marks of your best 5 subject.Percentage =( S/500 ) × 100 %Thanks for reading my answer and if you liked it please let me know in the comments section and don’t forget to upvote it.Edit : I forgot to mention that English is compulsorily added and from the rest five subjects, best four are taken.
A ball is thrown vertically upwards. What is the final velocity and acceleration at the maximum height?
This is physics at its most “common sense” form!You just need to think about you throwing a ball in the air. When you throw a ball, it’s only logical that at some point it stops and then comes back down to you. So, the velocity at the maximum height(the point where it turns around) is zero!Now, the acceleration is a bit more tricky but quite easy too! Which is the force that tries to bring the ball back to you*? Well, it’s the force that tries to keep you on the ground; it’s dear old gravity! But, does it change depending on where the ball is located? No. And we know that the gravitational acceleration is approximately 9.8 m/s^2 and, as I said, it’s constant. So, at maximum height, and at any height, the acceleration of the ball is equal to the gravitational acceleration!I honestly think that you should have thought about this much harder before you posted it as a question in Quora; this is the way to build intuition. You first start from simple, intuitive things and build onward from them to things that are a bit unintuitive at first. Cheers!*In my answer, I am not considering any force from the air around the ball, of course.
A market analyst working for a small-appliance manufacturer finds that if the firm produces and sells x blenders annually..?
A market analyst working for a small-appliance manufacturer finds that if the firm produces and sells x blenders annually, the total profit (in dollars) is: P(x)= 8x+0.3x^2- 0.0013x^3-392 A) When just a few blenders are manufactured, the firm loses money (profit is negative) (for example p(10)= -293.3, so the firm loses 283.30 if it produces and sells only 10 blenders) Approximately how many blenders must the firm produce to break even? B) Does profit increase indefinitely as more blenders are produced and sold? If not, what is the largest possible profit the firm could have?