What is the best free tool to use to verify emails?
There are lots of free email validation tools out there, but they have limitations. Some allow only for a one-time bulk verification's. The others allow a number of monthly requests.For instance, Hunter (.io) lets you do 100 requests each month. And you don’t get to download the results in a .csv. Expect to do a bit of the manual work with this method.Also, email verification tools generally employ a three-step process to verify emails. You can try the free ones, but the most robust ones are usually paid.Here is another option that you can try that can save you time and efforts: purchase only verified emails from a trusted database.Doing this gives you access to a large number of emails quickly and without going through the hassle of building your own list. You are also sure that you’re only getting high-quality leads that won’t impact your deliverability or your sender reputation.One such tool is UpLead.UpLead lets you unlock lead information using a certain criteria that you have. This allows you to search for leads that are highly relevant to your user persona. Once you have set the search options, you are given a list that is composed of only verified email addresses.You can also directly export the list to your CRM.See how it saves you time?Lead prospecting tools are investments that will pay for themselves.If you’re curious to give these tools a try instead of verifying your list using free tools, you can refer to our guide of 20 Sales Prospecting Tools to Close More Deals in 2019.
How do I delete thousands of emails from my AOL account without going through each one individually?
In your Mailbox window, press and hold the Shift key on your keyboard, and then click the first email that you wish to delete.2. Now, hold the Shift key down, and click the last email in the list. This will select all the emails between the first email and the last email that you have selected.3. Click Delete.
A 10 box slides 4.0 down the frictionless ramp shown in the figure , then collides with a spring whose sprin?
call down the plane the positive direction we will do the first part via energy conservation the box will slide 4 m down the ramp, hit the spring, and move the plane a little more before starting we will find the vertical distance it moves, and that will tell us the PE it converts to compressional PE; if the box compresses the spring a distance x, the total distance it moves down the plane is 4+x since the plane is inclined at 30deg, the vertical drop the box makes is given by sin30 = vertical drop/(4+X) or vertical drop = (4+x)sin 30 = 0.5(4+x) this must equal the gain in elastic PE, which is 1/2 k x^2, so we have 1/2 k x^2 = m g (0.5(4+x)) or 1/2 k x^2 = 2 m g + m g x/2 this is the quadratic: 1/2 k x^2 - m g x/2 - 2 m g=0 solve this quadratic for x; I get x=1.54m 2) realize that gravity will accelerate the box down the plane with an acceleration g sin30 = 4.9m/s/s once the box hits the spring, the spring will exert a force up the plane the maximum velocity will occur when the total force on the box is zero; once the box compresses the spring enough so that the total force acts up the plane, the box will start slowing down therefore, we want to find the value of x such that k x = m g sin(theta) k = mg sin30/k = 10 kg x 9.8m/s/s sin 30/230N/m = 0.21m
A 20.0 kg box rests on a table. (a) What is the weight of the box and the normal force acting on it? (b) A 10.?
A 20.0 kg box rests on a table. (a) What is the weight of the box and the normal force acting on it? (b) A 10.0 kg box is placed on top of the 20.0 kg box. Determine the normal force that the table exerts on the 20.0 kg box and the normal force that the 20.0 kg box exerts on the 10.0 kg box.
Can the BCC recipients, in a mail, see the other BCC recipients?
This is an important topic. Too many people don't understand how to use BCC. As others have said, the answer is no.However there are still millions of people who, for one reason or another, don't use the BCC feature in their email client.I usually teach people to address an email, meant for a group, to their own email address so they will get a copy and then use BCC for distribution to any others or more than a few.Too often, people just continue copying and replying to everyone on distribution lists when they only need to be addressed or replied to a single individual within the list.Others send out tens or hundreds of email addresses to groups inappropriately. Many people are highly offended when their email addresses are included in unprotected distributions like that. There is always an unscrupulous spammer somewhere in that list who will add those email addresses to their spam lists. It is most often just that we don't think before we act.Another common reason that this happens is because newcomers don't even know that there is a BCC option in their email client or email program. Many programs require you to click on CC, or to configure your email system to show BCC. In these cases, the user has to do a special action to even see that their email program offers the feature.Sorry if my answer is too long but I consider this simple question an important one to address with a wider audience. Thanks for asking.
High-speed stroboscopic photographs show that the head of a 210-g golf club is traveling at 53 m/s just before?
High-speed stroboscopic photographs show that the head of a 210-g golf club is traveling at 53 m/s just before it strikes a 46-g golf ball at rest on a tee. After the collision, the club head travels (in the same direction) at 40 m/s. Find the speed of the golf ball just after impact.
A boxcar of mass 200 tons at rest becomes uncoupled on a 2.5 degree grade. If the track is considered to be fr?
The slope is very small, therefor most of the force of gravity will be directed into the tack, but a small portion of it (9.8 m/s^2 times sin(2.5)) will force the boxcar down the track. You're answer will be [acceleration of gravity]*sin(2.5)*[time], or 9.8*sin(2.5)*10=4.275m/s When dealing with a slope, the acceleration directly on the track is the cos(accel of gravity), and the acceleration parallel to the track is sin(accel of gravity).
A 500-g block is released from rest and slides down a frictionless track that begins 2.70 m above the horizont?
A 500-g block is released from rest and slides down a frictionless track that begins 2.70 m above the horizontal, as shown in the figure below. At the bottom of the track, where the surface is horizontal, the block strikes and sticks to a light spring with a spring constant of 10.0 N/m. Find the maximum distance the spring is compressed.