Simplify : -5(m+2) +3m?
Well assuming this is just basic math, I would say distribute the -5 to the m and +2. So that would get you: -5m - 10 +3m. Simplify by combining like terms. The end simplification would be: -2m - 10. Which then goes to: -2(m+5) Hope this helps!
Simplify m^2-4m-21/(3m-6)(m+3)*(m-2)/(m...
Simplify the numerator of the first fraction m^2 -4m -21 = (m-7)*(m+3) Now m+3 can cancel out in the numerator and denominator and you're left with (m-7)/(3m-6) * (m-2)/(m-7) a 3 can factored out of (3m-6) to make 3(m-2) so now we have (m-7) / 3(m-2) * (m-2)/(m-7) When we multiply we can cancel out m-7 and m-2 from the numerator and denominator We are left with 1/3 Answer 1/3
Simplify 2(3m+2)(m-5)/(2m+3)(3m+5)(m-6)...
Law of distribution my friend
By the order of operations, we’ll begin simplifying the given algebraic expression by performing the indicated multiplication inside the grouping symbols (the brackets) using the Distributive Property as follows: 2[3 + 2(x – 6)] + 3[–2(x – 5) + 8] = 2[3 + 2x – 12] + 3[–2x + 10 + 8]Next, by the order of operations, we’ll perform any additions and subtractions from left to right inside the bracket grouping symbols after we slightly reorder of some of the terms: = 2[3 + 2x + (–12)] + 3[–2x + 10 + 8]Since addition is commutative, i.e., a + b = b + a, we have: = 2[3 + (– 12) + 2x] + 3[–2x + 10 + 8] = 2[– 9 + 2x] + 3[–2x + 18]Next, by the order of operations, we again take advantage of the Distributive Property of Multiplication over Addition from left to right as follows: = –18 + 4x – 6x + 54Now, collecting like-terms, we have: = 54 – 18 + 4x – 6x = 54 – 18 + (4 – 6)xPerforming the subtraction inside the parentheses: = 54 – 18 + (–2)x = 54 – 18 – 2xSimplifying further by performing the first subtraction from left to right, we finally have: = 36 – 2x or in factored form: = 2(18 – x)
Simplify completely. 2m^2 (-3m + 4m^2) - (3m)^3?
2m^2 (-3m +4m^2) -(3m)^3 = 2m^2 (-3m) +2m^2 (4m^2) -27m^3 = -6m^3 +8m^4 -27m^3 = 8m^4 -33m^3 = (m^3)(8m -33)
Simplify 2m + 3m - m (Homework Help)?
Well, for the first equation, we need to know the value of "m". The ASCII code for lowercase m is 109; or in binary 01101101. So, 2m+3m-m becomes 2(109)+3(109)-109 or 218+327-109. The answer is 436. The next problem is a little more complicated as it seems to involve a fixed point combinator. The "Y" combinator in the untyped lambda calculus is Haskell Curry's: Y = λf·(λx·f (x x)) (λx·f (x x)). The name of this combinator is sometimes incorrectly used to refer to any fixed point combinator. The untyped lambda calculus however, contains an infinitude of fixed point combinators. So to simplify.... 17 - y = 14 becomes 17 - [λf·(λx·f (x x)) (λx·f (x x))] = 14 The correct response for this equation would involve graphing a 3 dimensional Cartesian coordinate system. Due to limitations of the Yahoo answers interface, you will need to graph out these points on your own.
Simplify this please (2m^2/4m^5)*(8m/3m^3)?
(2m^2/4m^5)*(8m/3m^3) (2m^2*8m)/(4m^5*3m^3) (16m^(2+1))/(12m^(5+3)) (16m^3)/(12m^8) (4m^3)/(3m^8) 4/(3m^5) So (2m^2/4m^5)*(8m/3m^3) = 4/(3m^5)
(m-3)/(m+2)
SOLVE FOR M : m/5+3(m-1)/2=2(m-3)?
Okay, first of all, you're going to have to find the lowest common denominator of all of these fractions. You have m/5, 3(m-1)/2, and 2(m-3)/1. The three denominators are 5, 2, and 1. The least common multiple of these three numbers is 10. Now you set everything so that it's denominator is ten. You do this by multiplying the fractions by whatever number will make the denominator ten. Remember that you multiply both the numerator and denominator by this number. m/5 + 3(m-1)/2 = 2(m-3) 2(m)/2(5) + 5(3)(m-1)/5(2) = 10(2)(m-3)/10(1) 2m/10 + 15(m-1)/10 = 20(m-3)/10 Now you can just cross out all of the denominators. They're all the same so it doesn't really matter. It's like having 1 as your denominator, you can just ignore it. 2m/10 + 15(m-1)/10 = 20(m-3)/10 2m + 15(m-1) = 20(m-3) Now you simplify the equation to make it easier to solve. 2m + 15(m-1) = 20(m-3) 2m + 15m - 15 = 20m - 60 17m - 15 = 20m - 60 Then you just solve it! Move all the m's to one side and then just simple math. 17m - 15 = 20m - 60 45 = 3m m = 15 Then you can check your work and see for sure that it is 15. Good luck in the future. Feel free to message me if you have other problems.
Simplify 3m^-4 (4m^6-m^5)+(5m)^2 please show work?
Distribute, and use the property (ab)^x = a^x b^x: 12m^(-4)m^6 - 3m^(-4)m^5 + 5^2 m^2 Use a^x a^y = a^(x+y): 12m^2 - 3m + 25m^2 Combine like terms: 37m^2 - 3m