Simplifying Exponential Expressions?
In simplifying, the idea is to get everything out from under the radical sign that you can. Therefore, 5 √x² = 5x because the square root and the square "undo" each other. 3 √(2x²y) = 3 * √x² * √(2y) Nothing can be done to pull the 2y out from under the radical or to simplify it, but again the square root and the square on the x allows it to be pulled out, giving a final answer of 3x √(2y) For the radical expressions, I assume that the fractions are supposed to be enclosed in parentheses so that problem 3 would be cubert (7²) = cubert (49) and number 4 would be 5th-rt (x²) In general, x^(1/n) = nth-rt (x) if n is an integer greater than 1 and x > 0. If n is 2, the 2 is almost always left off the radical sign. In the absence of a superscript number on the radical sign, this number is conventionally assumed to be 2. This saves writing because square roots appear far more often than other kinds of roots.
Simplifying Exponential Expression?
Assuming the problem is written properly, it looks correct to me except for not simplifying. The fraction in front has a common factor of 49, so you can rewrite it as (16/7).
Simplify Exponent Expressions!?
44 x^4 y^2 ----------------- 32 x^4 y^-4 44 divided by 32 can be reduced to 11/8 11 x^4 y^2 ---------------- 8 x^4 y^-4 The x^4 in the numerator and the x^4 in the denominator cancel 11 y^2 ---------- 8 y^-4 Move the y^-4 in the denominator to the top, which will make the exponent positive 11 y^2 y^4 --------------- .....8 Multiply y^2 and y^4 by adding the exponents, the answer is 11 y^6 --------- ...8
Simplify this exponential function?
I think you mean to solve for it and not just simplify... Let 3^x = y then your equation becomes: y^2 - 12 * y + 27 = 0 Factoring it gives the following (y - 3)(y - 9) = 0 which means that y = 3 or y =9. Since y = 3^x, that means 3^x = 3 or 3^x = 9 Since 9 = 3^2 and 3 = 3^1 your solutions are x= 1 or 2. Hope that helped, -JPB
Simplify Exponential expression (Barometric Formula)?
You need to have something on the left side of the equation in order to solve this.
How would I further simplify this exponential function?
I'm trying to solve the exponential function: 3(5)^(2x-3) = 6 So far, these are the steps I've taken: 5^(2x - 3) = 2 log 5^(2x-3) = log 2 (2x-3)log 5 = log 2 (2x-3) = (log 2)/(log 5) 2x = (log 2)/(log 5) + 3 I wanted to know if I am solving it correctly and efficiently so far. I'm also a little unsure of how to continue. I know I have to divide by 2 to get x, but I'm not sure how to do that to the right side of the equation.
Simplifying exponential equations?
... (4xy^2)^4 (-y)^3 = 4^(4) * x^(4) * y^(2*4) * (-1)^(3) * y^(3) = (-1)^(3) * 4^(4) * x^(4) * y^(2*4+3) = (-1) * (256) * x^(4) * y^(11) = - 256 x^(4) y^(11)
How to simplify sqrt of this exponential function..?
im doing some calcIII and have come to a rather complicated algebraic simplification that i need to figure out to continue a very large derivative. the expression is; sqrt [ e^(-4t) + e^(4t) + t^(-1) ] im pretty sure the simplification has to do with creating a common denominator so that the top expression can be factored into something-squared (then the root can be taken of the top and bottom, thus leaving a much simpler expression..) [i tried using e^(4t) as the denominator, making the top expression: 1 + e^(8t) + t^(-1) but i cannot get it to factor into something-squared] im sure this is possible and there is a simpler way of writing this expression. if anyone can figure it out, i would much appreciate the help. I need the answer by tomorrow afternoon! Thanks..