Simplifying Radicals [Algebra Homework] Help!?
Hello, I'm having a bit of trouble with a couple of problems on my algebra homework on simplifying radicals. If you could show the work on how you got the answer NOT just give me the answer, that would be great! So I can make sure I'm getting to the answer correctly. Here are the problems: 1. √144 2. 3√729 3. 5√162 4. 3√192 5. √289 THANKS FOR THE ANSWERS IN ADVANCED!!
MATH HELP!!!!!! simplifying radicals?
if 3/10 is all under the square root, then it radical 3 divided by radical 10. you can't have a radical in the denominator so multiply radical 10 by the denominator and the numerator. it equals the square root of 30 divided by 10.
Help with math homework! (simplifying radicals)?
my math homework is simplifying radicals and im having a difficult time. (i have to find the ''perfect square'' of the number inside of the radical) 5. 5√80 6. 6√30 7. 7√8 8. 8√18 9. 9√32 10. 10√12 11. 11√8 12. 12√108 13. 13√125 14. 14√50 15. 16√175 16. 16√28 17. 17√45 18. 18√72 19. 19√20 20. 20√150 the numbers that are missing and not included are the ones i did already. they were much simpiler. anyways as many answers will be great. thanks. (please show work)
Math help!!! simplifying radicals!!!?
just get factors of the radicand wherein one of which is a perfect square: example: sqrt(54) 54 = 6 * 9 sqrt(54) = sqrt(6*9) = 3sqrt(6) that's it... you can use prime factorizations to quickly get factors, if you're comfortable with that. for those numbers wherein there really aren't any factors that are perfect squares, just copy for example, sqrt(61) is just written as is.
Radicals [Math homework help]?
ANSWERS/EXPLANATIONS TO ANY OF THESE QUESTIONS WOULD BE GREAT...BEST ANSWER GETS 10 POINTS, THANKS! 1) Simplify: a. 5[radical 2] + 2[radical 2] b. 9[radical 2] - [radical 2] c. 8[radical 3x] - 3[radical 3] d. 5[radical 7] - 4[radical 7] e. 4[radical 3] + 2[radical 3] - 5[radical 3] f. [radical x] + 5[radical x] 2) Simplify: a. 7[radical 3] - 4[radical 12] b. 7[radical 3x] - [radical 12x] c. 7x[radical 5xy^2] - [radical 20x^3y^4] d. [radical 75] - [radical 27] / [radical 12] e. [radical 8y^3] - [radical 2y^3] 3) Simplify: a. 4[radical 3] + [radical 2] - 4[radical 2] b. [radical 22] / [radical 11] - [radical 66] 1) Find the sum of: a. [radical 2] + 3[radical 2] b. [radical 18] + 15[radical 2] 2) Simplify: a. [radical a] + 8[radical a] b. 5[radical 3] / [radical 12] c. [radical 72x^3] - [radical 18x^3] d. [radical 18] - 2[radical 2] e. 4[radical 5] / 7[radical 2] - 7[radical 5] f. [radical 50] / 3[radical 2] 3) Find the value of the expression: [radical 18] - [radical 2]
9th grade math simplifying radicals-help!?
I have pages and pages of math homework..but some radical questions I don't understand. Please help! 1. The square root of 18y over 36ycubed. 2. The square root of five over the square root of two 3.the square root of 12 over the square root of 15. 4.the square root of 72 over the square root of 40 5.the square root of 25b over the square root of 5bcubed 6.the square root of 24 over the square root of 3n 7. the square root of 8 over the square root of 30msquared 8.You are making a mosaic design on a square table top. You have already covered half of the table top with 150-1 inch square tile pieces. a.What are the dimensions of the table top? b.What is the measure of the diagonal from one corner to the opposite corner of the table top? 9.What are three radical expressions that simplify to 2xsquareroot3 PLEASE IF YOU KNOW ANY, ANSWER, I AM SO STUCK
Alegra help please Simplifying Radical Expressions?
square root 2/7 * square root of 7/3 is the square root of 14/21 which simplifies to the square root of 2/3, you cant have a radicand in the denominator so you multiply the square root of 2/3 by the square roots of 3/3 which is the square root of 6 over 3
What is the square root of 57 in simplified radical form?
[math]\sqrt{57} = \sqrt{49 + 8}[/math][math]\sqrt{57} = \sqrt{19 *3}[/math]You cannot simplify it because you cannot make it any simpler by arithmetic or factoring.We can make guesses, though.This is called "Hero's Method".[math]S[/math] is our number.[math]x[/math] is our guess for square root of [math]S[/math]. [math]e[/math] is our error. [math]e \ll x[/math][math] S = (x + e)^{2}[/math][math] S = (x + e)^{2} = x^{2} + 2ex + e^2[/math][math] S - x^{2} = 2ex + e^2[/math][math] S - x^{2} = e(2x + e)[/math][math] e = \dfrac{S -x^{2}}{2x+e}[/math][math]e[/math] is considered insignificant compared to [math]x[/math], so[math] \frac{S -x^{2}}{2x+e} \approx \frac{S -x^{2}}{2x} [/math][math]x + e \approx x + \frac{S - x^{2}}{2x}[/math][math] \approx \frac{2x^2}{2x} + \frac{S - x^{2}}{2x}[/math][math] \approx \frac{S + x^{2}}{2x}[/math][math] \approx \frac{\frac{S}{x} + x} {2}[/math][math]\dfrac{\frac{S}{x} + x} {2} [/math]is not the simplest form, but it is the easiest to use for the calculationswe need to make.So now we can take iterative approximations, getting closer each time, until we reach the level of precision we are aiming for.Take an educated guess:[math] \sqrt{49} < \sqrt{57} < \sqrt{64}[/math][math] 7 < x < 8 [/math]start approximating:[math] S = 57, x = 7 [/math][math] 1) x \approx \frac{\frac{57}{7} + 7}{2} = 7.5714[/math][math] 2) x \approx \frac{\frac{57}{7.5714} + 7.5714}{2} = 7.5499 [/math][math] 3) x \approx \frac{\frac{57}{7.5499} + 7.5499}{2} = 7.549834[/math][math] 4) x \approx \frac{\frac{57}{7.54983} + 7.54983}{2} = 7.549834[/math]I got the same answer twice, so I am satisfied with 6 decimal places.[math] \sqrt{57} = \langle 7.549834, -7.549834 \rangle [/math]How accurate is this method?calculator check:[math] \sqrt{57} = 7.549834[/math][math] (7.549834)^{2} = 56.9999934 \approx 57 [/math][math] 1 - ( \frac{56.9999934}{57}) = .00000011 = .00001\%[/math]Hero was a Greek mathematician in the first century AD.