How do you solve this?
(1) 6/n - 1/2 = 9/2n put all the n's together then solve 6/n - 9/2n = 1/2 12/2n - 9/2n = 1/2 3/2n = 1/2 2n = 6 (2) 1/2 + 2x - 5/2x = 14/x - 1/3 hmmm, you need to use brackets in here is this 1/2 + (2x-5)/2x = 14/x - 1/3 or 1/2 + (2x) - 5/2x = 14/x - 1/3 and there are other combinations too ... 1/2 + (2x-5)/2x = 14/x - 1/3 x/2x + (2x+5)/2x = 42/3x - x/3x (3x+5)/2x = (42-x)/3x this is gonna get messy 9x^2 + 15x = 84x - 2x^2 7x^2 - 69x = 0 x(7x - 69) = 0 x = 0 or 69/7 but is it really the question you asked? (3) 5/2 - (3z-6)/3z = (z-8)/2z you need brackets here too you know ... just repost it with all the brackets so we know exactly what sums we are answering looking back you could be asking a totally different thing for (1) even (6/(n-1))/2 = 9/2n for instance - exceedingly messy, but possibly the sum you have described.
(3n - 2)/5 = 7/10 solve for N?
So that last question I posted? I meant to post this one *facepalm* Math saddens me :( Anyway: A n = 225 B n = 1.833 C no solution D n = -1/5 E n = 3.5 F true for all n I think the answer is C. Am I right?? Thanks in advance for any help.
Problem Solving: If 3+2=7, 5+4=23, 7+6=47 and 9+8=79 to what is 10+9 equal?
it's quite easy... most people are forgetting the hidden steps....Question3 2 = 75 4 = 237 6 = 479 8 = 7910 9 = ?as you can see, first numbers are continuous odd numbers ( 3, 5, 7 & 9) & second numbers are continuous even numbers (2, 4, 6 & 8) except the last line (tats the hint). So there are some lines are hiding inside. Check below for the solution.2 x 1 + 0 = 23 x 2 + 1 = 74 x 3 + 2 = 145 x 4 + 3 = 236 x 5 + 4 = 347 x 6 + 5 = 478 x 7 + 6 = 629 x 8 + 7 = 7910 x 9 + 8 = 9811 x 10 + 9 = 119 thats it.... 98 is the winnerYou guys can check with any steps, you will get the same ans.
If f(x) is a polynomial such that f(1) =1, f(2) =2, f(3) =3 and f(4) =16. Find the value of f(5)?
Let us assume : [math]f(x) = ax^3 + bx^2 + cx + d [/math]Then we get, [math]f(1) = a + b + c + d = 1 ... (1)[/math][math]f(2) = 8a + 4b + 2c + d = 2 ... (2)[/math][math]f(3) = 27a + 9b + 3c + d = 3 ...(3)[/math][math]f (4) = 64a + 16b + 4c + d = 16 ...(4)[/math]Solving (1) and (2), We get[math]7a + 3b + c = 1 ...(5)[/math]Solving (1) and (3), We get[math]26a + 8b + 2c = 2 ...(6)[/math]Solving (1) and (4), We get[math]63a + 15b + 3c = 15 ...(7)[/math]Solving (5) and (6)[math]6a + b = 0[/math]Solving (5) and (7)[math]7a + b = 2[/math]This gives, a = 2, b = -12And then, c = 23 and d = - 12Thus,[math] f(x) = 2x^3 - 12x^2 + 23x - 12[/math]And So, [math]f(5) = 2*(5)^3 - 12*(5)^2 + 23(5) - 12 = 53[/math]The required answer is f(5) = 53
What is the shortcut to solve the following problem: 1+2+3+4+5+6+7+8+9+10+11+12+...+49=?
There are many answers that look at it in terms of series of natural numbers, let us look at a way to solve it without any specific formula.Let us consider another number in the series and make it Sum =1+2+3+.....+49+50 Thus we have a total of 50 numbers,i.e 25 pairs of numbers . In the series we can see that : 1+50=51 2+49=513+48=51...25+26=51Therefore the total sum = 51 * 25 ( Since there are 25 such pairs) Sum =1275 But we had included an extra term 50 , thus subtracting 50 from the obtained sum we get ,1+2+3+4+5+.....+48+49 = 1275-50 =1225
Plz can you help me with school work?
1) a=-21/40 2)t=7 3)x=3/5 4)x=-1 5) subtract 3/10 6)subtract then multiply 7) subtract 1/8 8) 24 inches 9)n=1 2/3 10)multiply by 4
Algebra help. =( =( ='(?
1. Solve: −2(x − 3) = −6 -2x + 6 = -6 -2x = -12 x = 6 ---------- 2.Solve: 5x − 10 + 12 = 22 5x + 2 = 22 5x = 20 x = 4 ---------- 3. Solve: 5(x − 1) − (x + 5) = 2 5x - 5 - x + 5 = 2 4x = 2 x = 2 ---------- 4. Solve: −2(2x + 5) − 3 = −3(x − 1) -4x - 10 - 3 = -3x + 3 -4x - 13 = -3x + 3 -4x = -3x +16 -1x = 16 x = -16 ---------- 5. Solve: 4(x − 1) = 2(x + 2) + 6 4x - 4 = 2x + 4 + 6 4x - 4 = 2x + 10 4x = 2x + 14 2x = 14 x=7 ---------- 6. Which equation could be used to find two consecutive odd integers whose sum is 32? 15 + 17 = 32 n + n = 32 ---------- There are two number 6. 6. The sum of two consecutive odd integers is 236. What is the smaller integer? 117+119 = 236 117 ---------- 7. Solve for x: 2 over 5 (x − 2) = 4x. (2/5)(x - 2) = 4x (2x - 4)/5 = 4x (2x - 4) = 20x 2x - 4 = 20x -4 = 18x x = (-4/18) simplify x = (-2/9) ------------- 8. Solve for H: A = L • W • H A = LWH divide both sides by LW (A/LW) = H H equals A over L times W ------------- 9. The formula for degrees Celsius is: C = 9 over 5 (F – 32), where F stands for degrees Fahrenheit. Part 1: Solve the formula for F. Show all steps. C = (9/5)(F-32) C = (9F - 288)/5 5C = 9F - 288 5C + 288 = 9F (5C + 288)/9 = F F = (5C + 288)/9 Part 2: Determine how many degrees Fahrenheit 6 degrees Celsius is. F = [5(6) + 288]/9 F = (30 + 288)/9 F = 318/9 F = 35.34 or 35.3 repeating