Solve This Problem. Choose The Answer In Lowest Terms.

If you choose an answer to this question at random, what is the chance you will be correct? (A) 25% (B) 50% (C) 60% (D) 25%

To find an answer, one first needs to identify what the question is. This is asking the probability of being correct. Correct about what? What does "correct" mean? Correct to what question?Are you correct about the probability of being correct about the ... etc. ?It's an infinite loop. It asks you what is the probability you have to randomly pick the right answer to what is the probability you have to randomly pick the right answer etc. ∞And the answers are self-referential, therefore an abnormal set, as they are both part of the set and yet defining the set at the same time.If you assume that one answer is correct, then your chances of being right would be 1 in 4, which gives a 25% chance. If the "correct" answer is 25%, since A and D are both 25%, you now have a 2 in 4 chance of getting the "correct" answer. So now you have a 2 in 4 chance of being correct, which gives you a 50% chance. As soon as that becomes true, the correct answer becomes B. But only 1 option is 50%, so, if that is the "correct" answer, there’s only a 25% chance of choosing it. So now you’re back to where you started with there being a 25% chance of getting the problem right.Scenario A and D: Wrong because 25% appears twice and there is a 50% chance of choosing it.Scenario B: Wrong because there is a 25% chance of selecting 50%.Scenario C: Wrong because there is a 25% chance of selecting 60%.So, now you evaluate what the chances are for selecting a correct answer out of these four: 0/4, or 0%.So, if we choose to interpret the meta-game ignoring the loop (there is no question), the problem could have a right answer: 0%. However, if 0% were one of the options, it would become a paradox, with no correct answer under any circumstance.

What will be the answer if a multiple choice test consisting of 10 questions with four choices each, and the student guesses the answer to each question? What is the probability that he gets 8 questions correctly?

For each question we have 4 choices. So if you have 10 on such questions, you ll have :4*4*4*4*4*4*4*4*4*4= 4^10 = 2048Getting 8 correct means=> 8 corrects and two wrongs3/4 is the probability if a question is answered wrong1/4 is the probability if a question is answered correctlyso we can consider this probability :P=(3/4)*(3/4)*(1/4)*(1/4)*(1/4)*(1/4)*(1/4)*(1/4)*(1/4)*(1/4)=> P=0.00000858306But as we can select any combination of 2 from 10 for being wrong, so we need to multiply P by (10,2)=10!/(2!*8!) =45so the answer is P*45 = 0.00038623809So not very lucky to answer randomly!By the way, is it a question from your home work assignment? ;) ;)

If I mark all answers 'C' in an MCQ (Multiple Choice Questions) exam, what is the probability of passing the exam?

This question touches on the over-all strategy of “testmanship,” which applies a generic answer strategy in addition to whatever knowledge of the subject matter you actually have.This assumes the MCQ you face is relevant to some course of study you are involved with, or some area of knowledge with which you have a working familiarity -but no special expertise.Here’s the over-all approach:Before you start answering, scan the whole test to get an indication of the questioning strategy. Do not assume you must answer the questions in order -unless that’s a test condition.Go ahead and answer the questions where you have a good degree of confidence that you know the answer. Those are your “gimmies.” Let us say that this gives you 25% of the test.Now scan the questions for choices which you know or strongly suspect to be wrong. The more questions with wrong answers, the better, because your actual odds of a correct answer will be between the “possible” answers. If you’ve narrowed it down to two, then your odds on a sheer guess or coin flip are 50–50. Let us suppose that such questions account for half of the test. If so, you pick up another 25% or thereabouts. But don’t guess randomly -make an effort to determine which choice is more probably correct. That give you a slight edge.That leaves 25% of the test which have few or no known wrong answers. In a 4 choice test, your odds on a guess are 25%. Again, use what you DO know to get an edge.Watch out for answers such as “neither A nor D” or “Both C and B.” Hit the BOTH answers first, for any question where you have ruled out at least one answer.Be aware that the wording of some questions may give you a strong clue as to the answer to a subsequent question.Ignore suspicious patterns to answers, such as “all the answers are “B.”In general, apply the above instructions in the order they are given. The idea is to grab the low-hanging fruit first, then work your way up the “tree,” to more difficult material.This website: General knowledge quizzes has many MCQ’s in various areas where you may practice. In a general knowledge test I just took, I scored 9 out of 10 correct, using the strategies above. There were 2 questions which included known wrong answers, improving my odds on a “guess.” There were 2 on which I was completely clueless.Bottom line: some knowledge of subject matter is essential, but knowing how to take the test can be critical.Hope that helps.

What is the probability of choosing a vowel from the alphabets?

You need a corpus of text. It usually gathers text from passages, chapters, or sections of a book. And you usually gather books in a genre, from a period, from certain authors, or a style of prose. Then you can put them into text. You may take from all volumes, separate on the book, or another dividing line. Then you collect the characters, i.e. vowels or consonants from the text, and remove any additional characters, i.e. symbols, punctuation, and then find the frequency. You find the frequency of vowels among vowels or consonants, or how you restrict letters. If you have both the frequency of vowels and the frequency of letters, then you can calculate the probability of vowels. And the sense is restricted to the corpus of text, usually gathered in a meaningful way.