Can you help me with this Chemistry problem?
density = mass/ volumeGiven volume=1.35*10^18 m^3=1.35*10^18*1000 ltr =1.35*10^18*10^6 mLmass= vol * density=1.35*10^24 / 10^3=1.35*10^21 kg
Can someone please help me with my Chem 1b problem?
the question is "all the reagents in the reactions below are in aqueous form. The initial concentration of A is 4.5 x 10^-4 M. The initial concentration of B is 5.3 x 10^-3 M. At Equilibrium, the concentration of A is 1.2 x 10^-4. What is the value of Keq? Equation: A + 2B <--> C + 3D
Can someone help me with my chemistry problem?
how many problems do you want answered at one time? For the first one, use MaVa = MbVb Just plug and solve
Someone please help me on my chemistry problem?
One container with a volume of 1 L contains argon at a pressure of 1.77 atm, and a second container of 1.50 L volume contains argon at a pressure of 0.487 atm. they are then connected to each other so that the pressure can become equal in both containers. what is the equalized pressure? i guess we have to use dalton's law. but i dunno
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Let’s call the initial energy, [math]E_0[/math]You may be familiar with the relation,[math]E = hf = \frac{hc}{\lambda}[/math]where h is Planck's constant, f is the frequency, c is the speed of light, and [math]\lambda[/math] is the wavelength.50% of the initial energy is transferred so solving for lambda,[math]\lambda = \frac{hc}{\frac{1}{2}E_0}[/math]I haven’t got a calculator on me, so you’ll have to plug in the numbers yourself.
Can somebody help me answer this Chemistry problem?
1.35 x 10^18 m^3 x (100cm/m)^3 = 1.35 x 10^24 cm^31.35 x 10^24 cm^3 x 1 g/cm^3 x 1kg/1000g = 1.35 x 10^21kg
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Please God Help me with this AP Chem Problem?
well you have to first have the equation (HNO3) + (OH-) -> <- (H20) + (NO3-) since the equivalence point is the point where the acid and the base concentrations are the same, once you mix 25 ml NaOH with the nitrous acid, the only thing your gonna make is the NO3- and water. so from the initial concetrations, the amount of NO3- made is 3.75 mmol (or .00375 mol if u prefer). then divide that by the total volume and you will get a molarity of .075M So then you need the equation: (NO3-) + (H20) -> (HNO3) + (OH-). from that, you have the Kb expression of Kb= [HNO3] [OH-] / [NO3-] Kb = Kw/Ka : Kb = 1.0x10^-14/4.5x10^-4 = 2.2x10^-11 since you already have the value for NO3- (.075M) and Kb, you can complete the problem. 2.2 x 10^-11 = x²/.075-x x = [OH-] = 1.28 x 10^-6 -log(1.28x10^-6) = pOH = 5.89 PH = 14 - pOH : PH = 14 - 5.89 = 8.11
Can someone please help me with my chemistry homework?
1) How many moles are equal to 2.55x10^25 formula units of CaCo3 My answer: 4.23 x 10^ -1, WRONG but yuo have problem with math! 1 mol equal 6.023*10^23 formula units x moles equal to 2.55*10^25 formula units of CaCo3 x = 1 * 2.55*10^25 /(6.023*10^23) x = 42.337 = 4.23 * 10 2) How many grams are 9.45x10^23 formula units of KCl equal to? Answer: 1.17 x 10^ -2; NO, math problem again! M(KCl) = 39.1 + 35.5 = 74.6 g/mol 74.6 g KCl equal 6.022*10^23 formula units of KCl x g KCl equal to 9.45*10^23 formula units of KCl --------------------------------------... x = 74.6 * 9.45*10^23 /( 6.022*10^23 ) = 117.066 g KCl 3) How many moles is 3.11x10^19 formula units of Na3P Answer: 3.11 x 10^17; missed M(Na3P) = 3 * 22.99 + 30.97 = 99.94 g/mol 1 mol ... 6.022*10^23 x ................ 3.11*10^19 ----------------------------- x = 1 * 3.11*10^19 / ( 6.022*10^23 ) = 0.000051644 = 5.1644 * 10^(-5) mol 4) Convert 1.56 moles of Ne into atoms of Ne. Answer: 3.14 x 10^ -1; no Be crefull, neon is gas and don’t exist as monoatomic molecule but as twoatomic molecule Ne2. Check this question. 1 mol Ne2 is 2*6.022*10^23 atom Ne 1.56 moles Ne2 is x ---------------------------- x = 1.56 * 2*6.022*10^23 / 1 = 1.87886 * 10^24 atom Ne So, by my opinion, you have minor trobule with chemistry and little bit trouble with math. Repeat some lecture about proportions and scientific number representations: ... greater then 1, count right zeros 1000 = 10^3 100 = 10^2 10 = 10^1 1 = 10^0 0.1 = 1/10 = 10^(-1) 0.01 = 1/100 = 10^(-2) 0.001 = 1/1000 = 10^(-3) ... smaller then 1, count left zeros 10^5 / 10^3 = 10^(5-3) = 10^2 10^(-5) / 10^(-3) = 10^(-5) * 10^3 = 10^(-5+3) = 10^(-2) because 1/10^(-n) = 10^n