Ugh! can someone help with me with this question!!?
The perpendicular components of his final velocity just b4 landing are: v(fx) = 23.0 cos (360 - 43.0°) = 23.0 cos 317° v(fy) = 23.0 sin 317° Air resistance is neglected ... so the horizontal component of velocity remains constant so v(ix) = v(fx) = 23.0 cos 317° = 16.8 m/s (horizontally to the right) horizontal range = horizontal velocity x time of flight so 51.0 = 23.0 cos 317° t t = 3.03 s Now consider the vertical motion: v(fy) = v(iy) + at take up as the positive direction: 23.0 sin 317° = v(iy) - 9.8 * 3.03 ... [don't put a minus sign in front of the 23.0 sin 317° b/c the sine of the angle automatically makes it negative ... b/c sine is negative in the 4th quadrant] v(iy) = 14.0 m/s (vertically up) Now use the Pythagorean theorem to get the magnitude of the initial velocity: |v(i)| = √(16.8² + 14.0²) = 21.9 m/s direction = arctan (14.0 / 16.8) = 39.8° above the horizontal so the skier's initial velocity off the ramp is 21.9 m/s at an angle of 39.8° above the horizontal
Ugh chemistryy! Someone help ?
hi i'm sorry. i am not so knowledgeable about questions no 4 and 5 for no 1, the correct answer is 147.5 K (when writing temperature in Kelvin, i don't think that you need to write degree sign before it) the answer could be A (if your teacher allows you to round off your answers) or D (none of the above) the computation is the application Charle's Law. V1 m= 1500 mL V2 = 750 mL T1 = 22 C + 273 (to convert it to kelvin) = 295 K T2 = x (the one wer searching for) V1 V2 ___=____ T1 T2 or V1T2 = V2T1 1500mL 750mL _______ = ______ 295K x x = (750mL)(295K) / 1500mL x = 147.5 ______________________________________... for no.2 the reaction is oxidation or combustion of propane C3H8 +5O2 ----> 3CO2 + 4H2O answer : B. 1, 5, 3,4 ______________________________________... for no. 3 there is an error on the equation that you gave. AgNO3 + K2CRO8---->Ag2CRO4 + KNO3 take note of CrO8 and CrO4 on different sides of the equation that is impossible. :-) but then i assumed that it is just a typo error, and i assumed that it is CrO4, not CrO8 - because none of which exist. :-) so the answer is: A. 2, 1, 1, 2 2AgNO3 + K2CRO4---->Ag2CRO4 + 2KNO3 hope it helps thanks
Ugh, can someone help? i SUCK at factoring?
These problems are basically all structured upon one rule. a^2-b^2=(a+b)(a-b) Therefore, 1.16x^4-4y^2=4(4x^4-y^2)=4(2x^2+y)(2x^... 2.9x^2-8y^2=prime [though technically it's (3x+2sqrt2y)(3x-2sqrt2y), where sqrt=square root of] 3.4x^2-64y^2=4(x^2-16y^2)=4(x+4y)(x-4y... 4.4x^4-y^2=(2x^2+y)(2x^2-y) 5.x^2-16y^2=(x+4y)(x-4y)
How do I get over someone I’ve never had? How do I get over this heartbreak, this misplaced feeling of something that never belonged to me?
I've just had the same experience, and getting over it is indeed difficult, took me about forty days to accept it and move on. The hardest part is this is a close friend of mine, and at some point I have been misled that what we had is really something special.. So here's how I did it:1. Acknowledge your feelings, no matter how deep it is. Dont do self denial, face the truth with head up high.2. Seek the counsel and enjoy the company of some friends. I am lucky enough to have friends who happened to served as 'witness' to our 'story'.. So they understood, they let me cry, shout, drink, party, then cry again..3. Do not over think! The tendency of unrequited love is that we tend to overthink every little sweet gesture and look for signs from the other person. One thing I have learned from this is to never assume, never expect unless you hear the other person say it and do the obvious.. I began to realize, as well, that if he really has feelings for me he would have told me early on, but no.. So there had been none.. 4. Save a distance from that person. Since he is a close friend and co worker, I tried never to pass by his cubicle, never linger in the pantry area if he is there, try to avoid any chance of contact, I deactivated Facebook where both of us has been active, and resist checking him out. Gladly he is working in a different division from us, so the distance is far easy..like the old cliche that goes, out of sight, out of mind..5. Keep yourself busy, especially when thoughts and memories of him keeps bothering your mind. Veer away from thinking of him and work work study and work and eat and sleep until you are too physically tired or pained to even think of him..6. Time heals. Let time do the work after you have done your part, and lastly,7. Pray and meditate and laugh again.. It makes going back to your old normal peaceful self much faster..I hope this helps. Another advice I have heard but I do not recommend is to find someone else, so, uhm is there anyone still available here to help me heal my broken heart in quora?? Hahaha.. Just kidding... This gives a lot more tendency for the new person to become your rebound, and it will be unfair for him/her. So do not resort to this step, unless you are sure your heart is open to let someone new in..Again, I am single... Lol
Can someone help me with 2 of my math problems?
Ugh, I've thought and thought and I just can't figure out how to do these two problems. =/ I can do the rest of my math HW, but not these two, =/ I have to write an equation for both of them. 1. A bottle and a cap together cost $1.10. The bottle costs $1 more than the cap. How much does each cost? 2. The perimeter of a rectangular garden is 40 ft. The width is 2 ft more than one half the length. Find the length and the width.
Ugh can someone please help me with chemistry? what's ppm and ppb?
ppm and ppb stands for parts per million/billion because atoms are just that small. 1g/ml = 100g/L sooo 13.7 micrograms (i believe micro is ten to the -6) so if you have a sweet calculator try 13.7x10 to the -6 over ..... wow.... just screw this chemistry sucks
If someone says ugh what does that mean?
Hi Zackary. When someone says 'ugh', it is generally an expression of disgust. It is something you would say if, for example, someone asked if you wanted a side order of worms with your spaghetti.
Have you ever tried to help or do something nice for someone only to have it look like you are fully creepy?
Well, the other day, I was at school and went to the nurse for other reasons. After I was done, I saw that my friend (I will call R) was there resting on the little couch. We said hi and talked a little bit. She looked drowsy. As I went to get out of the nurses' office, R asked me to tell her friend to get her stuff. So here I was out on a Naruto mission. It was lunchtime, and her friend and I shared the same lunch period, so I would see her in the cafeteria when I got in. I went to sit and decided to tell the friend to get R’s stuff after the lunch period ended. I didn’t want to walk into the loud kid’s territory and look weird standing there while everyone else is sitting. (;-;) So eventually, the bell rang thus ending the lunch period. I scurried over to the friend to tell her that R wanted her to get her stuff. Keep in mind that I have never talked to this girl before. And the cafeteria is REALLY LOUD.“Uh, hi, R is in the nurses’ office aand would like you to get her yyour stuff.” I said in my bravest voice. and repeated three times for some reason. I guess to make sure that she heard or something. ugh brain whyyyy.She looked at me weird and hurried away with some boy that she always talks to. like she RAN away. I didn’t even know if she heard me or not. double oof.Later that day, R walked up to me and we talked again. She had her stuff with her. I wondered if she got it herself because the friend at lunch didn’t hear me. So as I was mentally face slapping myself, I asked if R’s friend was the one who got her stuff. She said “yes”.whew.
Ugh someone please help me with one HOMEWORK Question!!!!!?
If you are a retailer in South Africa, Beget Holdings is the only source in the entire nation for Intellect Aero, a wireless all-in-one point- of-sale, mini-ATM and voucher device, which is able to carry out debit and credit card transactions faster than landlines or any other current communications methods. In other words the maker of Intellect Aero has decided to use _____ distribution. a. exclusive b. pioneering c. selective d. intensive e. direct Answer=