Suppose U={1,2,3,4,5,6,7,8} is the universal set and P={2,4,6,8}. What is P ?
Hello U is the numbers from 1 to 8 inclusive. P is the Even numbers from 1 to 8 inclusive Andy C
Suppose U= {1,2,3,4,5} is the universal set and A= {1,5}. What is A?
You must mean U\A so the answer is 2 i.e. {2,3,4}
Suppose U={1,2,3,4,5,6,7,8,9,10}, A={2,4,6,8}, B={3,6,9}, C={1,5,10}.?
(a) A - B = {2, 4, 8} (b) B - A = {3, 9} (c) C - A = {1, 5, 10} (d) A - U = 0 (empty set) (e) A^c = U - A = {1, 3, 5, 7, 9, 10} (f) C^c = U - C = {2, 3, 4, 6, 7, 8, 9}
Suppose U = {1, 2, 3, 4, 5, 6, 7, 8} and B = {2, 4, 6, 8,}. What is B’?
Take a breath, this is actually pretty easy. U = {1,2,3,4,5,6,7,8} is a set. Anything between the { } is a set, it could be numbers, or words. B = {2,4,6,8} is a subset of U. That is because all of the numbers in B are also in U, but B is smaller. The apostrophe after the B' means anything that is not B. Plain english, B' = any numbers that are part of a set not already listed in B. In this case, B' = {1,3,5,7} Another problem: U = {orange, bannana, apple, pear} B = {bannana, apple} B' = {orange, pear} Mathmatically, its expressed as B + B' = U
If A is a subset of S, then for any element i in S, we have either that i is in A or i is not in A. To specify a subset, we have to say, for each of the n elements of S, whether or not it is in the set. That is, we must make n choices, each of which has two possible outcomes.Hence, the number of possible subsets is the number of possible outcomes of these n choices, which is 2*2*...*2 = 2^n.
Given set isA = {1,2,3,4} andB = {4,5,6}We have to find A-B ?Let's start to solve this question…Apply the basic set rules,A- B = {1,2,3,4} - {4,5,6} = {1,2,3}Correct answer is :- {1,2,3}Trick to solve this type of questions:- let you have given two set A and B, if you want to find A-B then there is a simple trick to solve this very easily. Follow the following step…1.Look elements of both set A and B carefully2. Cancel all the elements which is found similar in both set.3. After cancellation of similar elements of both sets, write down the uncancelled elements of set A.4. Now Your answer is remaining elements of set A.
For questions 4 and 5, suppose {1,2,3,4,5,6,7,8}, A=(1,3,5,7), and B= {4,5,6}. Tell whether each statement....?
A subset means that all the elements in set A is also represented in the set B. (A is a subset in B) so to answer your question: 1. A (1,3,5,7) is not a subset in B (4,5,6) because all the elements in A are not represented i B. False 2 Here you can see that all the elements in B, is also represented in your universal set. so B is a subset of U True! hope it helped
Let the sample space be S = {1,2,3,4,5,6,7,8,9,10}. Suppose the outcomes are equally likely.?
So you've got 10 options right? (1,2,3,4...etc). If each outcome is equally likely, then all the outcomes have a 1/10 probability of occurring (like let's say you have each number on a sheet of paper and are pulling them out of a hat. The probability that you will pick the number 4 is 1/10 because there is only one number "4" and there are 10 numbers in all). The probability of picking a 3 is 1/10. As is the probability of picking a 5,9, or 10. If you add these probabilities together you get 4/10. So there is a 4/10 probability that when you pull out numbers from the hat that you will get either a 3,5,9 or 10. (:
What is the complement of set T? (Algebra)?
The compliment of a set is basically everything that is in the defined universe that is not in that set. So, in the universe represented by U = {–10, –6, –2, 0, 3, 5} everything that is not in the subset T = {–10, –6, 0} is the set {-2, 3, 5}.
The question has already been answered correctly. Let me try a different take on this.Being sure of whats what can help you figure this solution easily...:)n(AUB) means the the number of elements in both A & B. And that includes the ones in common too.n(A∩B) means the ones that in common.n(A-B) refers to the elements that belong to A alone. That means the elements in A excluding the common elements.n(B) is the number of elements that belong to B and that includes the common ones too.Now coming to your question.The total number of elements that can fit in both the sets is 36.While the number of common elements is 16.And also given that n(A-B)=15.Now according to the definitions above....n(A) should include the ones that belong exclusively to A alone and also the ones in common.So,n(A)=n(A-B)+n(A∩B) =15+16 =31Therefore, n(A) is 31.Now when n(AUB) is 36 and n(A) is 31, it is clear that the elements exclusive to B alone is 5, i.e.36-31. Now n(B)=n(A∩B)+n(B-A)Therefore, n(B) is 16+5 = 21.n(B)=21.