Rate these four girls from 1 to 10?
1. http://www.flickr.com/photos/rvg43/5105859844/ 2.http://www.flickr.com/photos/rvg43/5105860300/ left 3. http://www.flickr.com/photos/rvg43/5105860300/ right 4. http://www.flickr.com/photos/rvg43/5105265681/ rgiht http://www.flickr.com/photos/rvg43/5040045854/ http://www.flickr.com/photos/rvg43/5039419477/ http://www.flickr.com/photos/rvg43/5105859880/ http://www.flickr.com/photos/rvg43/5105266079/ some more pics of them
What are your thoughts on the name Lavinia?
Love it! Most other people don't seem to care for it (from what I've heard) but I think it's adorable! It's light and airy, and makes me think of a cute little princess (probably because it was the name of the princess on "Jane and the Dragon" when I was younger, haha). And it's decidedly medieval without being as hard and clunky as a lot of others. Lavinia Charlotte is great. Since Lavinia is so out-there, it would probably be best to pair it with a more well-known middle name. For a nickname, I would likely go with Vinnie. But I doubt I would call her anything but Lavinia, since it's so pretty and I just love saying it! :) ɛïɜ Tнαℓια'ა Mυაε
If you had four girls what would you name them?
Angelica Bridgette Skyla Nicoline Vespera Hermione Rowena Giselle
There are these four girls who try to make me feel more relaxed in my environment. I have crippling shyness so I always feel uneasy. I learned that all of them like me but I have no experience with girls. I like them but I’m too shy, what can I do?
There are many reasons for shyness but the main one is the idea that people will not like me if they knew the real me. That is complete BS. There is a group of friends for everyone on earth. If someone who purports to be your friend does not accept all of you they are not your friend.Here is a little advice;Get over the fact they are girlsThey are people first and girls second. It is not all about sexual interaction. Sometimes people of different genders just like to hang out together. They see something in you that you don’t see yourself. Go with that. Talk to them. They may even see you as the shy brother. That is not all bad.You are you first and foremost.Act like what you think is right. It may not be but you will learn how to get along. One of my favorite sayings is “A real friend is someone who you can be a complete fool in front of and the shame is not permanent”.You will foul up.I am not perfect and I don’t expect everyone else to be perfect. I will make mistakes and so will you. You need to be able to forgive yourself as you forgive others.Stop calling yourself “shy”.The human brain is very powerful. It wants to be right all the time. Say “I am shy” often enough and your brain will agree and you will be shy. Some people like to go to the affirmations like “I am bold” to counter the “I am shy”. For me, that is to fast. I prefer a slower approach like “I am usually shy but this time I will be bold”. It recognizes past behaviors and pushes toward change. You might get to “I am bold” but it may take a few steps.Intellectualise.Ask yourself why you feel that way. Are you reliving past poor experiences? Are you fearful they will happen again? Are you fearful you will do the wrong thing again? Think about what is going on. Make a plan. You can not fix the past but you can do better now. Eventually, you will succeed.I hope this helps.
Find the number of ways in which four boys and four girls can be seated in a row?
(a) If boys and girls alternate, then the pattern must be either B G B G B G B G or G B G B G B G B where B represents a boy and G a girl. So there's a choice of 2 patterns. The four boys can be placed in the seats designated B in 4! different permutations. The four girls similarly can be seated in 4! different permutations. [If you need any help with basic permutation formulas like this, see the source listed below. It's an excellent online explanation of them.] Thus, the total number of ways they can be seated is 2 * 4! * 4! = 2 * 24 * 24 = 1,152 (b) Whichever of the 2 alternate-seating patterns we choose, there are 7 possible pairs of adjacent seats in which the designated boy and girl can sit together. If we choose one of these pairs of seats, then the remaining boys can be seated in the remaining seats designated for boys in 3! permutations, and the remaining girls can occupy the remaining seats in 3! permutations. So there are a total of 2 * 7 * 3! * 3! = 2 * 7 * 6 * 6 = 504 ways to seat them with these constraints. (c) Here, we need to pick the most convenient order in which to make our seat selections so that the calculations don't get too complicated. (The order doesn't affect the final result, but it does affect the complexity of the cases.) Again, start with the choice between 2 alternations (boy first or girl first). Now, pick two seats for the boy and girl who must not sit together. Having already assigned which seats are for boys and which for girls, we know that we pick one seat from each group of four: 4 * 4 = 16 combinations but then we have to exclude the 7 combinations which would put them in adjacent seats: 16 - 7 = 9 Now, we merely have to place the other boys in their seats (3! permutations) and the other girls in theirs (again, 3! permutations). Our total is 2 * 9 * 3! * 3! = 2 * 9 * 6 * 6 = 648 ways.
Would naming four girls piper, paige, perri, and phoebe get them teased?
I reckon the show would be forgotten by then. Well, at least by young people, who are the ones who would be doing the teasing. The parents might remember, so snobby mums might talk behind backs, but it doesn't seem like their thing to me. And Charmed fans don't seem like they would be so petty. Perri would probably get teased though. Kids would probably say "Hey Perri! Can I get some Peri Peri sauce with my Nandos?" Or they'd tease her for having a boys' name. :) What do you think of the name Phoebe Elizabeth Tara? http://answers.yahoo.com/question/index?... Could you please vote on my fave baby names: http://www.babynames.com/Names/namelist_... And these are my guilty pleasure names: http://www.babynames.com/namelist/977387...
In a group of 6 boys and 4 girls, four children are to be selected. In how many different ways can they be selected so that at least one boy should be selected?
Any permutation and combination question which consists of “at least” word can be answered in 2 ways:As the question asks about at least one boy should be selected, so from total no. of ways of selecting 4 children subtract none of the boys which gives us one boys + 2 boys + 3 boys + 4 boys, which is our required answer at least one boys. So the answer is C(10,4)-C(4,4)=209. C(10,4) is no. of ways of selecting 4 children's from 6 boys and 4 girls. C(4,4) is no. of ways of selecting 4 girls from 4 girls which is 1 way. So the answer is 209.In the second method let’s select 1 boy, 3 girls + 2 boys, 2 girls + 3 boys, 1 girl + 4 boys which is C(6,1)*C(4,3) + C(6,2)* C(4,2) + C(6,3)* C(4,1)+ C(6,4)= 209. In both ways answer is 209.
If five boys and four girls are to be seated in a row, how many ways can they be arranged so that they are seated alternately?
The sequence of boys and girls must be:[math](B,G,B,G,B,G,B,G,B)[/math]There are [math]5![/math] ways of arranging the five boys and [math]4![/math] ways of arranging the four girls.Total arrangements is [math]5!\times 4!=120\times 24=2880[/math].
What do you think of these four names for quadruplets?
I think Alex and Jen work fine. Porsha is ok but I might do something different like Lareina or Angelica or Marianela- something over-the-top, that sounds beautiful and dramatic! Porsha is just kind of harsh and whenever I try to picture thegirl I see a car instead :D As for Bridgette, it would work but it just sounds a little too sensible and normal for an annoying prep. What about Brittney or Trisha? I know those are little common but you get the idea ;) Good luck on your story!
In a class of students there are 4 girls and 6 boys. How many ways can they be seated in a row so that all four girls are not together?
Total number of arrangements all 4 girls not together = total arrangements - all girls togetherThere is 6 boys and 4 girls, i.e 6+4=10 persons.So total number of arrangements in a row of 10 persons = 10! = 3628800Now 4 girls are assumed to be together. So there are 6 boys + set of girls i.e 6+1=7 sets which can arrange themselves in 7! ways.7!=5040For each of these 5040 permutations, the set of girls ie 4 girls can arrange within themselves in 4! =24 ways.So total arrangements where 4 girls are together = 5040*24 = 120960So required number of arrangements = 3628800 - 120960 = 3507840