Hard Math Question. Can you figure out the answer?
Besides what smci has explained: N = N^2 1 = 1 2 = 4 3 = 9 4 = 16 5 = 25 6 = 36 7 = 49 8 = 64 9 = 81 1) Possible answer can not have 5 with any of the even digits 2) If the number have all digits >=4 then multiplication of squares will result in a number greater than the original number (e.g. 44 < 16*16 = 256), so the possible answer has to have "balanced combination" of numbers {1,2,3} with {4,5,6,7,8,9} BTW I tried to find such numbers using program but No such number exists within 10^7, However I have noticed that there are numbers with following property a^2 x b^2 x c^2 = abc + 1 (They are also rare!!!) One of them as you have already mentioned is 143 Others are 323,11663 On analysis of above numbers my eyes remained wide open!!! Just Imagine, these numbers are product of two TWIN PRIMES (with difference 2)!!!! 143 = 11 * 13 323 = 17 * 19 11663 = 107 * 109 Now I am searching for both type of numbers Addendum: I have finished searching till 1382529243, I have searched for both types of numbers, with no success, so largest twin composite number which I have found for other type is 11663
I need help with hard maths questions?
My maths teacher gave me a few hard questions. I couldn't do two questions. Please show me how you did the question with working out. Q1. We say a number is ascending if its digits are strictly increasing. For example, 189 and 3468 are ascending while 142 and 466 are not. For which ascending 3 digit number n ( between 100 and 999) is 6n also ascending? Q2. A magician deposits the same number of rabbits (at least one) at each of five houses. To get to the first house he crosses a magic river once and to get to any house from another he also crosses a magic river once. Each time he crosses a magic river, the number of rabbits he has doubles. He has no rabbits left when he leaves the fifth house. What is the minimum number of rabbits he could have at the start?
Two very hard questions on Variation (maths)...?
1. y = kx 10 = kx x = 10/k (1) when x is halved y = k * (x/2) (2) substitute (1) into (2) y = k * (10/2k) y = 5 2. p = k/q when q = 11 p = k/11 (1) when p is halved p/2 = k/q (2) substitute eqn (1) into (2) (k/11)/2 = k/q k/11 = 2k/q qk/11 = 2k qk = 22k q = 22
Hard eight grade math question?
1.You are a salesperson for Worldwide Widgets. Each week you earn $200 dollars plus two ninths of your sales. What dollar amount of sales do you need this week to earn $500? 2.The trek club plans to hike 20 miles today. The hikers have convered 6 miles so far. If they travel an average speed of 2 1/2 mph, how many hours will it take to complete the hike?
Pretty Hard Math Questions...some Algebraic?
1.) use a = apples, o = oranges and p= pears now 3a + 7o + 11p= 6.04 2a+5o+ 8p=4.31 now you have to solve for each variable so lets get rid of a. multiply.... -2 (3a + 7o + 11p)=-2( 6.04) and 3(2a+5o+ 8p)=3(4.31) then the two equations you will have are -6a-14o-22p= -12.08 6a+15o+24p= 12.93 the a variables will cancel out when you add the equations so you have o+2p=0.85 isolate o so o=0.85-2p then you use this in 2a+5o+ 8p=4.31 2a+5(0.85-2p)+8p=4.31 2a+4.25-10p+8p=4.31 2a-2p=0.06<-- use this as your FIRST equation now plug o=0.85-2p into a different equation 3a + 7o + 11p= 6.04 3a+ 7(0.85-2p ) +11p= 6.04 3a+5.95-14p+11p= 6.04 3a-3p=0.09<-- this is your second equation now your first equation 2a-2p=0.06 and 3a-3p=0.09 now get rid of p so 3(2a-2p)=3(0.06) 2(3a-3p)=2(0.09) then you multiply and get the p's to cancel out and then you hav the equations 6a=.18 6a=.18 or 12a=.36 so solve for a hten you get a + .03 so apples cost 3 cents then plug in to solve for the other variables.
How do I finish math CBSE board question paper in 2 hours and 40 minutes?
Tl;dr: Solve as many previous year's paper as you can. Practice is the only way to crack this nut.Let's be realistic for a second. It is difficult to complete Maths CBSE board question paper within 2 hours and 40 minutes, but not impossible. You will need sheer amount of practice before you can do this. While in the exam hall:Use your reading time properly: Read each and every question properly. Make sure you don't misread some question. It's okay if you are confused it any question, mark it be solved at the end.Don't waste time: You should solve each and every question with the minimum amount of time required. This can be achieved only with lots of practice and having a very good clarity over the concepts.Accuracy: Maintain accuracy while you are solving quickly. Make sure you don't get confused between two different topics.Avoid silly mistakes: You should be totally focused on the day of your exam. Pay attention to sign conventions, subtraction, multiplication, copying a question from the question paper and copying one line on a new page from the last page. Keep your excitement in check: Don't get overexcited while studying or while solving the paper. Keep calm and write your paper without any hesitation.While studying (in these 10 days):Previous year question papers: Whatever I said above can be achieved only through practice. So this step is a must. You can find 2008-2013 question papers of all regions (with solution) in one pdf from this link: Xam idea · Learning Center. Solve atleast 6 last year's papers within 3 hours of time and then try to go through as many papers as you can .Cheers and all the best!
Need help with two of these advanced math question please?
Me and my son need help with these two questions. To no avail, we did not do very well on these. Thank you for your time and answers! Question 1: A science teacher gives a test with 15 questions. This teacher is a hard grader. The teacher assigns points in the following manner: a correct answer = +1 point, an incorrect answer = -1 point, no answer = 0 points. So scores on the test could range from +15 to -15. The teacher’s assistant calculates the standard deviation for scores on the test and reports SD = -2.3. What do we know? A.The standard deviation was calculated incorrectly. B.Most students received negative scores. C.Most students scored below the mean. D.There is an outlier that has a negative value close to -15. Question 2: Histogram A: https://oli.cmu.edu/repository/webcontent/65c2161c80020ca601c3920394e15386/m2_summarizing_data/topic_2_4/webcontent/checkpt_2.gif Histogram B: https://oli.cmu.edu/repository/webcontent/65c2161c80020ca601c3920394e15386/m2_summarizing_data/topic_2_4/webcontent/checkpt_3.gif Histogram C: https://oli.cmu.edu/repository/webcontent/65c2161c80020ca601c3920394e15386/m2_summarizing_data/topic_2_4/webcontent/checkpt_4.gif Rank the standard deviations of the above data sets in order from smallest to largest. Assume the scales on the horizontal axis are the same in each histogram. Smallest: Middle: Largest: That is it. Thank you for your time!
HW question very difficult math algebra 2?
this question is so easy yet hard, i know how to do it but it doest look right. you are taking part in a charity walk a thon where u can either walk or run. you walk at four kilometers per hour and run at 8 kilometers per hour. the walkathon last 3 hours. money is raised based on the total distance you t ravel in the three hours. ur sponsors donate 15 dollars for every kilometer u travel. write an expression that gives the total amount of money u raise. evaluate the expression if u walk for two hours and run for one OHH MYH AND!!
As an Indian, how hard is the Maths section in SAT for a student who is not that good in Maths?
Speaking about personal experience, I don't consider SAT tough. However, I will quote it as tricky. Most importantly SAT mathematics section requires speed and accuracy. It barely checks your knowledge level but the abundance of questions compounded by less time availability make it easier for you to miss points.To see what I mean take a look at the following question.Let the scene be like this : 1 minute remaining and you've gotta answer this question. Now even the dumbest mathematician (even at INDIA) knows how to calculate area of two rectangles and two triangles! I want y'all good people to solve this and comment the answer. Do not proceed without solving this. Be honest and just don't copy the answer I am going to write at the last.So you might have gotten some answer, and my guess is that the majority had the answer as 1852. Let's keep the answer for the last.Thus, my fear friend, SAT is easy as it goes. It has the formulae listed, no need to memorise them. It even has a calculator section, no need to be a whiz at mental maths. All you gotta do is embrace the trick and not fall for it, rather make it crumble and emerge victorious. What I mean to say is that, practice and develope the thinking capacity to conceive the concept related to the question. If you can do that, you won't really have to struggle much.Since, this question ain't about English I won't speak much. But I'd recommend you to do Khan Academy's material as it really is helpful.All the very best!!:-)One last question before we part. Find the area of a right angle triangle, whose length of hypotenuse is 10 and the altitude w.r.t. Hypotenuse from the opposite vertex is 6.If your answer is 30. You're wrong. Think about it, don't browse Google. ;-)UPDATE :THE SOLUTIONS OF THE QUESTION ARE AS FOLLOWED :question 1 :The trick starts*question 2 :Now you know that rushing in the SAT is injurious for health, jokes apart, focus on every possible aspect and then solve. I appreciate if you have reached this section after trying the questions yourself. Anyway, it ain't no test, just wanted to show you that how things might look and what the actual case can be.Hope I could help y'all. All the very best and ace the SAT!!!