A perfect gas at 27°C is heated at constant pressure till its volume is doubled. What will be its final temperature?
According to ideal gas equation PV=nRTP=pressure of gas,V=volume of gas=volume of container,T=temperaturueV1 =INITIAL VOLUME ,V2 =FINAL VOLUMET1 =INITIAL TEMPERATURE =27+273=300T2 =FINAL TEMPERATUREAccording to question,V2 =2 x V1Therefore,V1/V2 = T1/T2V1/2V1=300/T2T2 =FINAL TEMPERATURE=600KVidyanchal Academythank you
A metallic bar is heated from 0°C to 100°C. The coefficient of linear expansion is 10^-5k^-1. What will be the percentage increase in length?
linear expansion is given by :=10^-5 * 100=10^-3=0.001=0.1%
A rod of length 2m at 0°C and having expansion coefficient alpha= (3x+2) *10^-6 where X is the distance in cm from one end of the rod. What will the length of the rod at 20°C be?
Coefficient of linear expansion [math]\alpha[/math] is defined as the fractional change in length per unit change in temperature.Consider an element dx of the rod of length [math]L[/math] at a distance [math]x[/math] from one of its end. We are interested to find what change in length (shown by [math]\delta[/math] in the figure) of this element will take place due to change in temperature [math]\Delta T[/math].By definition of temperature coefficient of linear expansion, we have for this element,[math]\alpha = \frac {\delta}{dx \,\Delta T} [/math]Or, [math]\delta = \Delta T \alpha dx[/math]The total change in length [math](\Delta L)[/math] in the rod can then be found by integrating this with proper limits[math]\Delta L = \int_0^L{\Delta T \alpha dx}[/math]If [math]\alpha = (ax + b)[/math] then[math]\Delta L = \int_0^L{\Delta T (ax + b) dx} = L\Delta T(\frac{aL}2 + b)[/math]You can plug in your values to find [math]\Delta L[/math]. Add this to original length to get the final length.
A barometer reads 75 cm on a steel scale. The room temperature is 30° C. The scale is correctly graduated for 0° C. What is the correct atmospheric pressure?
Scale is calibrated for 0 degrees that means there must be certain expansion at 30 degrees.Assuming it to be an iron scale coefficient of linear expansion of iron is a= 10^-5/ degrees.(Source: WikiPedia)Now total expansion is: Ladtwhere L is the lengtha is coefficient of linear expansiondt is change in temperature(30–0)hence total expansion is L(10^-6)30=3LX10^-5mHence error in measurement is :dL= 3LX10^-5mActual length of mercury rise: L+dl: L(1+3X10^-5)L=0.75m hence total length is 0.75(1+0.00003)or 0.750025 m.Now 760 mm Hg corresponds to 1.103X10^5 N/m^2hence 750.025 mm Hg corresponds to 99 970.4375 N/m^2.Hence this is the actual pressure of the surrounding under those conditions.Thanks!
Can a gas diffuse in a gas?how about a gas in a liquid?give example?
diffusion is the movement of paricle from a region of higher conc. to a region of lower conc. therefore a gas can diffuse in a gas if either one is conc. in one point and the same goes for gas in liquid example: u can smell the fart of someone else even though he's sitting at the other end. that's because his fart diffused into the air you breathe in.
If a material has a Poisson ratio of 0.50, and if a uniform rod of it suffers a longitudinal strain of 2, then what is the % change in volume?
If the poisson ratio is 0.5 then % change in volume will be zero.How?I hope you know the relation,E=3K(1–2u) where u=poisson ratioPutting u=0.5 we get bulk modulus of elasticity K infinity that means ∆V =0 in equationK= -∆P/(∆V/V)Hence change in volume is zero that is it is incompressible.