Headlight shortage? What's the cost?
If the lights are slightly weak it could be a faulty head-lite ground wire or a bad connection on that battery or starter or alternator or engine block ground posts or connectors.It would all depend on how long it takes them to trouble the circuit but it could be about 2 hrs or more in labour costs. Hope that helps and best of luck.By the way if you know someone handy with vehicles simply have them clean the contacts I've mentioned with a small wire brush and run new ground wires to the head-lites.
What does a shortage in a wire actually mean?
a shortage is different from a short. A shortage means "not enough for the needs" (I cannot finish the wiring because there is a shortage of wire; I don't have enough). A short means a "short-circuit" which refers to when two different wires touch and the current takes a short cut and never makes it to the place that it was supposed to go. (the basic idea is that there are two paths to the place being supplied; the wire going there and the wire coming back; a short circuit makes it so the current returns by jumping from the feed wire to the return wire before it ever makes it to the place it is supposed to be going). But it has also come to mean an interruption in the circuit, meaning that the wire doesn't connect all the way for some reason (maybe it is broken part way along). A short means that there is a wiring problem making it so the electricity doesn't make it to where it is supposed to go. Usually a short leads to an unrestricted flow and causes a fuse to blow or a circuit breaker to cut for safety reasons. In fact, you can usually tell whether it is a break or a true short-circuit by whether the fuse fries or breaker flips.
How much does it cost to fix electrical problems/bad wires and fuses in a car?
I just replaced my battery and my alternator, but my car still has electrical issues. Several weeks ago, the lights inside my car kept lighting up like Christmas tree lights, my radio kept fading in and out, and everything electrical was going crazy. When I checked to see if the alternator was working, it said that it wasn't doing anything, and the battery was in the process of completely dying. I replaced the alternator and the battery, plus while I was there I got my oil replaced, with new filters. So, my problem is now my car is still having electrical issues. The radio keeps completely disappearing, I was also driving at night when this happened and my lights totally turned off, which made driving in completely darkness very difficult. My car is still having electrical issues, and it can't be the alternator or the battery. How do I fix this, or get it fixed, and how much would it cost me? Also it's a 1999 Ford Traser, if that affects the price at all.
Which consumes more power thin wire or thick wire?
Let us take a simple example to understand the concept. Further let us try to find out on what factors does power loss depend.Case 1:Assume you have a thin wire of 5ohms resistance & 5A current through it.Hence, total loss=(I^2)*R=(5^2)*5=125WCase 2:Assume you have a stranded conductor made of 5 identical thin wires of resistance 5ohms. These wires are also identical to that of Case 1's wire. The 5A current is now divided into 1A through each wire.Hence, total loss= Summation of individual losses =5*(1^2)*5=25WSo what we observe? The stranded conductor consumes less power than a single thin conductor.Case 3:Now if we take a single thick conductor instead of a stranded conductor, let us see what we get.We choose its length and thickness in such a way that we get its resistance as 5ohms. The formula to calculate R of a wire is,r=resistivity*(length/area)where, resistivity depends on the material and the temperature.Now assume we got R=5ohms of that thick wire.Hence, power loss=(5^2)*5=125WNow we observe that it produces same power loss that of the thin wire! So where did we went wrong? Let us have a look at the above formula to calculate r. r is inversely proportional to area. Case 3's wire has a larger area than Case 1's. So to obtain r=5ohms, either resistivity has to be increased or the length. Assuming same working temperature and material, resistivity can't be changed. Hence, length has to be increased to get r=5ohms. Now if we cut down the length of wire so as to match it with Case 1's, r drops and hence power loss drops (which is obviously less than 125W as in Case 2).So what do we learn?1. The power loss depends directly on the length of wire but inversely with the Area of cross-section.2. The power loss depends on the material we use as a conductor.3. Increase in the temperature increases resistivity and hence the power loss increases. Now, a conductor heats up as current flows through it. Hence this increases the resistivity and ultimately leads to more power loss. So to avoid this kind of situation, we either use a fan or heat sinks to cool down the system.Hope this helps :)
What does it mean that the oil light flickers (not low on oil) when idling on my 94 Honda Accord?
That light signals improper oil pressure. Figure out what exactly is wrong or take it to someone to figure out what's wrong and fix it ASAP because low oil pressure = dead engine in the near future. My guess is either your oil pump is bad or your engine is clogged up with oil-sludge causing poor oil flow.