1)As 10X =110By dividing 10 in both side we get10X/10=110/10Hence we getX=11(OR)2) AS 10X=110SO, 10X-110=0and 10(X-11)=0or X-11=0hence X=11
To solve the given linear equation, 10x - 5x = 150, for the variable x, first collect like-terms on the left side as follows:10x - 5x = 150 (Given)(10 - 5)x = 150(5)x = 1505x = 150Now, divide both sides of the equation by 5 in order to isolate x on the left side, thus solving the equation for x as follows:(5x)/5 = 150/5(5/5)x = 150/5(1)x = 30x = 30CHECK (ALWAYS PERFORM THIS STEP, AND DO SO BACK IN THE ORIGINAL, GIVEN EQUATION!):10x - 5x = 150 10(30) - 5(30) = 150 300 - 150 = 150150 = 150Therefore, x = 30 is indeed the solution to the given equation.REMEMBER: For solving equations, WHATEVER YOU DO TO ONE SIDE OF THE EQUATION, YOU MUST DO TO THE OTHER SIDE.
19X + 10
10 percent of 150 is 15 and here's some proof.All you do here is do 150÷10, which equals to 15. So that is correct.X=15Now let's do 4(15), from here, we put a × between the 4 and 15, so it would look like this.4×154×15 equals 60.Now, let's answer your question. What is 20 percent of 6020 goes into 100 5 times, so we take that 5 and we do.60÷5=12Final answer, it's 12.
Math help? (: Thank you!?
The price P (in dollars) and the quantity x sold of a certain product obey the demand equation P=-1/10x+150. a) Express the revenue R as a function of x. b) What is the revenue if 100 unites are sold? c) What quantity x maximizes revenue? What is the maximum revenue? d) What price should the company charge to maximize revenue? Thank you so much! If you could explain or show work it would be SO helpful. (: Thanks!
Algebra 2 help me?!?!?!?
Solve 10x + 75 = 150. Round your answer to the nearest hundredth. x=7.5 1. A. x ≈ 1.63 B. x ≈ 1.56 C. x ≈ 1.75 D. x ≈ 1.88 4. The solution of the equation is approximately -2. A. true B. false 5. Solve log(-5x) = log(10 - 3x). B. x = -5 7. The solution of the equation x = log94 is approximately 0.63. B. false x=1.9731278535996986596279582941736936... 9. The solution of the equation x = log315 is approximately 4.56. B. false x=2.4983105537896005100885331703783737... 10. Solve x = log315. Round your answer to the nearest hundredth. A. x ≈ 2.56 B. x ≈ 3.12 C. x ≈ 2.46 D. x ≈ 3.67 ?? what function??11. What is the approximate value of the function at x = 0.5? 14. Solve the equation 5x = 6.2. Round your answer to the nearest hundredth. x=1.24 A. x ≈ 1.13 B. x ≈ 2.59 C. x ≈ 1.45 D. x ≈ 3.49 15. The solution of the equation 10x = 1.51 is approximately 0.18. x=0.151 B. false NOTE: Many discrepancies
Economics maximizing consumption bundle?
hello, i have no clue in figuring this problem out. John's utility function is U=10X^2Z, the price of x is Px=$10 and price of z is Pz=$5 and his income is 150. what is his optima consumption bundle? thanks for anyone that can help and if possible can anyone give an explanation of how to go about in solving this problem? im trying to understand how to compute this but the book doesnt give a great example of it. thank..
Let's confine ourselves to the arithmetic of multi-layered fractions.In your terms you have set yourself the proposition of expressing[math]\frac{\frac{A}{B}}{C}[/math]I'll show you the rule I committed to memory but which I can also prove when necessary.I'll generalize your problem slightly"[math]\frac{\frac{A}{B}}{\frac{C}{D}}[/math]This generalizes your case. For your case set D=1. The simple rule for fractions is to resolve them as multiplication by the reciprocal of the denominator:[math]\frac{\frac{A}{B}}{\frac{C}{D}}=\frac{A}{B} (\frac{C}{D})^{-1}=\frac{A}{B} \frac{D}{C} = \frac{A D} {B C} [/math]So the rule to remember is a four -layer fraction is resolved as the product of the extreme pair (AD) divided by the product of the middle pair. In the case of a three-layer fraction, make it a four-layer fraction by setting D=1 before applying the rule.If you compare this to your own computation, you'll find that you haven't correctly applied this rule.If you have a situation where the numerator is not a fraction but the denominator is, then we first generalize the situation to set B=1 (see above):[math]A/(C/D)=\frac{\frac{A}{1}}{\frac{C}{D}} = \frac{A D } {C} [/math]This should be enough to resolve the contradiction in your computations.
How do you solve x^2+5X=150?
First rearrange the problem. x^2 + 5x - 150 = 0 Then factor x^2 + 5x - 150 = (x - 10)(x + 15) = 0 So either: x - 10 = 0, and x = 10 or x + 15 = 0, and x = -15 If you're not very good at factoring, you can always use the quadratic equation: x = [-b +- sqrt(b^2 - 4ac)]/(2a) In this case, x = [-5 +- sqrt(5^2 - 4(-150))]/2 x = [-5 +- sqrt(625)]/2 x = [-5 +- 25]/2 x = 10 or x = -15
15 is 10% of what number?
There is a very easy way to work out 10% of anything - just move the decimal point one place to the left. So if you know that after doing that, the answer is 15, then just move the decimal point one place to the right ie add a zero. 15 is 10% of 150. So unbelievably simple, you should have known this already!