Factor completely: 24x²-28x-12?
4(6x² - 7x - 3) 4(2x - 3)(3x + 1)
4x^3 - 6x^2 - 28x factor completely!?!?
4x^3-6x^2-28x=2x(2x^2-3x-14)= =2x(2x^2+4x-7x-14)= =2x[2x(x+2)-7(x+2)]= =2x(x+2)(2x-7)
Factor completely 6x^2+8x-8?
6x^2 + 8x - 8 Reduce the numbers to lowest term by dividing by 2 2 ( 3x^2 + 4x - 4) Factor the (3x^2 + 4x - 4) 2(3x - 2) (x + 2) ------------------ Answer
Factor completely x^4+3x^3+6x^2+12x+8=0?
... x^4 + 3x^3 + 6x^2 + 12x + 8 = 0 or x^4 + (2x^3 + x^3) + (4x^2 + 2x^2) + (8x + 4x) + 8 = 0 or (x^4 + 2x^3 + 4x^2 + 8x) + (x^3 + 2x^2 + 4x + 8) = 0 or x (x^3 + 2x^2 + 4x + 8) + (x^3 + 2x^2 + 4x + 8) = 0 or (x+1) (x^3 + 2x^2 + 4x + 8) = 0 or (x+1) (x^3 + 4x + 2x^2 + 8) = 0 or (x+1) ( x (x^2 + 4) + 2 (x^2 + 4) ) = 0 or (x+1) (x+2) (x^2 + 4) = 0 or (x+1) (x+2) (x + 2i) (x - 2i) = 0
(Help!) Factor 8x^3+6x^2-12x-9 Completely.?
I've been struggling with this problem for quite a while and I really need help! Thank you! Step 1: In order to factor by grouping, put parentheses around the first two terms and the last two terms with an addition sign between the two sets of parentheses. 8x^3+6x^2-12x-9 Step 2: Rewrite the polynomial from step 1 below with parentheses in place. Factor out the greatest common factor out of each set of parentheses and write it outside of each set. Use the blanks provided. Show your work. (8x^3+6x^2)+(-12x-9) _____( )+ _______( ) Step 3: Rewrite the greatest common factor you identified in Step 2 as a sum inside parentheses, producing a binomial. ( ) Step 4: When you factored out the common factor in step 2, this produced the same binomial for each set of parentheses. Write the product of the binomial for Step 3 beside the identical binomial from step 2. This completes the factoring of the polynomial. ( ) ( )
Factor completely 12x^5 + 6x^3 + 8x^2. a) prime b) 2 (6x^5 + 3x^3 + 4x^2) c) 2x (6x^4 + 6x^2 + 4^x) d) 2x^2 (6x^3 + 3x + 4)?
We can look at each option separately.a) It’s obviously not prime because 12, 6 and 8 are all even numbers so we can at least pull a 2 out leading us to :b) 2(6x^5 + 3x^3 + 4x^2) This is correctly factorized but it’s not fully factorised and the question says factorise completely, leading to:c) 2x(6x^4 + 6x^2 + 4^x), this is incorrectly factorised and therefore the wrong answer. If we pull 2x out of 12x^5+6x^3+8x^2 we should have 2x(6x^4+3x^2+4x) however this too is not fully factorised because there is still an x in each of the terms in the brackets leading us to:d)2x^2(6x^3+3x+4) which is the correct answer.Hope this helps. BTW you might find this video useful which explains how to expand out brackets and factorise terms into brackets.
Factor completely: 6x2 - 28x + 16, x4 + 2x3 - 3x - 6?
6x^2 - 28x + 16 (6x-4)(x-4) x^4 + 2x^3 - 3x - 6 x^2(x^2 + 2x) - 3x - 6 x^2(x^2 - x - 6) x^2(x - 3)(x + 2)
Please factor 6x^2-28x-48?
First look for the GCF (greatest common factor). Since all the terms are even, the GCF is 2. Now you have the following: 2(3x^2 - 14x - 24) Forget about the 2 outside the parentheses for a while. You need two numbers that, when added, give you -14 (the middle number) and when multiplied give you -72 (the product of the first and last numbers). Several pairs of numbers multiply to be 72 (we'll deal with the negative sign momentarily): 1 & 72, 2 & 36, 3 & 24, 4 & 18, 6 & 12, and 8 & 9. Since 4 and 18 differ by 14, that is the correct choice. But, one term must be negative so the product is -72. It's either -4 & 18 or 4 & -18. Since the sum must be -14, the two numbers are 4 & -18. Now rewrite the middle term as + 4x - 18x. You now have the following: 3x^2 + 4x - 18x - 24 The first two terms have an x in common, and the last two terms have a 6 in common. Factor these out: x(3x + 4) - 6(3x + 4) Notice that I factored a -6 out of the last two terms. That made the 4 change to a positive. Since both factors have a (3x + 4), it can be factored out: (3x + 4)(x - 6) But don't forget about the 2! 2(3x + 4)(x - 6) Hope this helps!
Factor 6x^3-22x^2-8x?
6x^3 - 22x^2 - 8x = x * (6x^2 - 22x - 8) = 2x * (3x^2 - 11x - 4) Delta = 121 + 4 * 3 * 4 = 169 x1 = (11 - 13) / 6 = - 2/6 = - 1/3 x2 = (11 + 13) / 6 = 24/6 = 4 <=> 6x^3 - 22x^2 - 8x = 2x * 3 * (x - 4) * (x + 1/3) = 2x * (x - 4) * (3x + 1) *******