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What Is Sulfur Dioxide In Equation

What is the equations for: sulfur dioxide gas reacts with oxygen gas to form sulfur trioxide gas.?

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We know that the reaction after it being equal from the reactant and the product molecule we get : 2SO2(g)+O2(g) ->2 SO3(g) And the solution also give you information the give us information of quantity is 3dm3 of SO2,AND 2dm3 of O2..We can use mole concept that: 2SO2(g)+O2(g) ->2SO3 Initial: 3 dm3 2dm3 React:3dm3 1/2*3dm3 2/2*3dm3 Remain 0dm3 0.5dm3 3dm3 PS:To know which gas will completed reaction is use your each of initial volume of gases divided bequalisese coefficient and the smallest volume result will completed reacted.So why I say the SO2 is completed reaction because 3dm3/2(the coefficient of SO2) is 1.5 dm3 but 2dm3/ 1(with the coefficient of O2) is 2dm3 And we can get the volume of SO3 is 3dm3

What is the balanced equation for the synthesis of sulfur dioxide?

since the question is asking for the synthesis of sulphur dioxide, B) should be the answer because the final product is sulphur dioxide

One equation to produce sulfur dioxide is:S + O2(g) = SO2(g)Change in Free Energy: ΔG(200C) = -300.9kJ (negative, so the reaction runs)Change in Enthalpy: ΔH(200C) = -302.1kJ (negative, so the reaction is exothermic)But there are other ways to produce sulfur dioxide. This is just one of them.

How would you balance this equation: sulfur dioxide + water --> sulfurous acid ?

In a manner analogous to carbonic acid sulfurous acid decomposes H2SO3-------- SO2 + H2O carbonic H2CO3 ------ CO2 + H2O both CO2 and SO2 ( as well as SO3 ) are known as acid anhydrides in that they dissolve in water and react with the water to form an oxy acid.

How do you do this balancing equation? sulfur dioxide plus water gives sulfuric acid?

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2SO2 + O2 + 2H2O --> 2H2SO4 12.2 mol of SO2 will produce 12.2 mol of H2SO4 in theory since there is a 1:1 mol ratio 6.1 mol of O2 is needed because there is a 2:1 ratio of SO2 to O2

Oxygen is naturally diatomic, and the process by which it oxidizes sulfur leads to both oxygen atoms reacting. The fact that SO2 forms instead of SO is a result of thermodynamics favoring SO2 over SO.Sulfur can expand its octet, which means in SO2, it has 12 electrons 'around' it. This allows resonance to form where O- has a significant contribution to resonance, while S still has at least 8 electrons around it. In SO no such resonance forms exist, meaning the highly electronegative oxygen must share its electrons with with sulfur to avoid exposing a six-electron sulfur species. Hence SO2 forms, and should have a better (formal charge) structure than SO overall. These are the two resonance structures (courtesy from Wikipedia)The steps I usually take to draw these out, firstly, is:SUM of total Valence e- = x   2. SUM of total e- to be satisfied = y   3. Bonds = (x+y)/2Domain = (x/2)-3 (species around the central atom)

It's exact balance is2SO2 + 1/2O2 —— 2SO3Normally happened in sulphuric acid manufacturing

So2 is the formula of sulfur dioxide.

What is the unbalanced equation for the combination of sulfur dioxide, sulfur trioxide, and water?

I'm struggling a lot with this question in chemistry. The full text of the question is, "the burning high-sulfur fuel can lead to acid rain. When these fuels are burned, they produce sulfur dioxide and sulfur trioxide. The combination of these compounds in the presence of water leads to the production of sulfurous acid and sulfuric acid. Write the unbalanced equation for the combination of sulfur dioxide, sulfur trioxide, and water." if you can answer this, I'd really appreciate any explanation you have for how you got the answer as well!

SO2(g) + H2O(l) --> H2SO3(aq) .... The equation is balanced as written. Pretty simple, right?That's the equation you're expecting. SO2 is much like CO2. They both dissolve in water and they both form fictitious acids. And like the nonexistent H2CO3, there are no molecules of H2SO3, either.What we call "sulfurous acid" is actually a solution of dissolve sulfur dioxide in equilibrium with some H+ and HSO3- ions.SO2(aq) + H2O(l) <==> H+ + HSO3-

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