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What Is The Calcium Concentration In A Water In Equilibrium With Calcite At A Pco2 Of 10^-2.5 Atm

I do agree with sonali raghunath's suggestions. She is well explained each and every reaction properly. Na2CO3 (sodium carbonate) + H2O => Na2O + H2CO3 (carbonic acid) => H2O +CO2 + 2NaOHKeep in mind that this reaction does not go all the way to completion, but that it is still a fairly strong base. The reaction of sodium bicarbonate (baking soda) is similar, but goes to completion even less, making it a weaker base.

What happens when calcium carbonate is made to react with hydrochloric acid? Give the equation of reaction.The carbonate radical breaks up into carbon dioxide and oxygen; the oxygen binds with the acid’s hydrogen ions to make water; and a solution of calcium chloride remains.The balanced reaction equation is CaCO₃ + 2HCl → CaCl₂ + CO₂ + H₂O.With the symbols denoting the states of the compounds, it’sCaCO₃(s) + 2HCl(aq) → CaCl₂(aq) + CO₂(g) + H₂O(l).

Nitric acid has the chemical formula HNO3, and Calcium Hydroxide has the chemical formula Ca(OH)2. When an acid and a base react with each other, the products that are formed is a salt (an ionic compound that is formed from a reaction between an acid and a base) and water.So, acid + base ---> salt + water Now, to balance the equation, we have to make sure there are the same number of atoms (or ions) on both sides of the equation. Also, we must list the state of each compound in the equation.HNO3 (aq) + Ca(OH)2 (aq) ---> Ca(NO3)2 (aq) + H2O (l)Number of atoms before the reaction:H = 3N = 1O = 5Ca = 1Number of atoms after the reaction:H = 2N = 2O = 7Ca = 1There are not the same number of atoms on both sides of the equation, so we must balance it. Remember to place the balancing numbers in front of the chemical formulas.2HNO3 (aq) + Ca(OH)2 (aq) ---> Ca(NO3)2 (aq) + 2H2O (l)Number of atoms before the reaction:H = 4N = 2O = 8Ca = 1Number of atoms after the reaction:H = 4N = 2O = 8Ca = 1There are now the same number of atoms on both sides of the equation, so that is the balanced chemical equation between nitric acid and calcium hydroxide.I hope that made it a bit easier :)

What happens when calcium carbonate is made to react with hydrochloric acid? Give the equation of reaction.The carbonate radical breaks up into carbon dioxide and oxygen; the oxygen binds with the acid’s hydrogen ions to make water; and a solution of calcium chloride remains.The balanced reaction equation is CaCO₃ + 2HCl → CaCl₂ + CO₂ + H₂O.With the symbols denoting the states of the compounds, it’sCaCO₃(s) + 2HCl(aq) → CaCl₂(aq) + CO₂(g) + H₂O(l).

Finding concentration when i know the solubility product?

1) Ksp = [Ca++] [CO3--]
When CaCO3 dissolves, [Ca++] = [CO3--], so substituting,
Ksp = [Ca++] [Ca++];
[Ca++] = √(Ksp) (the square root of Ksp).
According to the reference below, Ksp for CaCO3 is 3.36×10^-9 mole²/L², so [Ca++] = 5.8x10^-5 mole/L

2) The molecular weight of CO3 is 60 g/mole, so:
(0.003 g/L) / (60 g/mole) = 5.0x10^-5 mole/L. This is less than 5.8x10^-5 mole/L at saturation, so in this case all of the CaCO3 must have dissolved. Since [Ca++] = [CO3--], [Ca++] = 5.0x10^-5 mole/L

Calcium carbonate, CaCO3 has a solubility product Ksp = 8.7 x 10-9. What is the concentration of Ca2+ ions in?

write the solubility equation ... CaCO3 = > Ca2+ + CO32-

write the Ksp expression .. Ksp = [Ca2+] x [CO32-]

look at the concentrations ... if x mole of CaCO3 dissolves ,
x moles of Ca2+ and x moles of CO32- are formed

plug these values in the Ksp expression .. 8.7 x 10 ^-9 = x * ^2

x = 9.32 x 10 ^-5 moles per liter ...

the concentration of Ca2+ in a saturated solution of CaCO3

Chemistry Equilibrium?

At 900degrees C, Kp = 1.04 for the reaction
CaCO3 (s) --> CaO(s) + CO2(g)
At a low temperature, dryi ice (solid CO2), calcium oxide and calcium carbonate are introduced into a 50L reaction chamber. The temperature is raised to 900dgrees C, resulting in the dry ice converting to gaseous CO2. For the following mixtures, determine whether the system is at equilibrium. If the system is not at equilibrium determine the amount of each species when equilibrium is established
a) 655g CaCO3, 95.0g CaO, P(CO2) = 2.55atm
b) 780g CaCO3, 31.00 g CaO, P(CO2)= 0.104

You use the relative atomic mass of the atoms.Carbon has a relative atomic atomic mass of 12. Oxygen has a relative atomic mass of 16, so two of them is 32.Hence in whichever mass CO₂ you choose, there will be (12 ÷ (12 + 32)) × 100% = 27.3% to 3sf.

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