What is the hybridisation of cr in [cr(h2o) 6] 2+?
2+
What is the hybridisation of [Cr(NH3)6]Cl2?
In this compound chromium has +2 Oxidation State.In this compound ammonia is acting as a strong field ligand so it causes pairing of electrons in the 3D orbitalThus the hybridization in [Cr(NH3)]Cl2 is d2sp3. As ammonia is a strong field ligand so it uses inner D orbitals. That's why the hybridisation is like this.
What is the hybridisation of (Co(h2o) 6) 2+?
[Co(H20)6]²+=Is outermost octahedral complex -SP³d².=Water being weak Field ligand can’t pair electrons.=Hence electrons prefer to remain unpaired & thereby give High spin Complex.=Mag.moment=(3(3+2))¹/².=complex is paramagnetic.
Wht is the hybridisation of [Ti(Cl)6]2- and [Cr(h2o)6]3+ ?
d2sp3 they are both octahedral
What is the hybridisation of [Fe(H2O) 6] 2+?
Hybridization is sp3d2.In [Fe(H2O)6]2+, central metal atom Fe has atomic no. 26Therefore, its electronic configuration is[Ar] 4s2 3d6And that of Fe2+ is 3d6 4s0.as H2O is a weak field ligand, no pairing of electrons takes place. To accomodate lone pairs from six H2O, one 4s, three 4p and two 4d orbitals hybridize to give six sp3d2 hybrid orbitals.Other facts about [Fe(H2O)6]2+ :–Magnetic behavior:- as it has four unpaired electrons, it is paramagnetic. ( H2O is a weak field ligand)Geometry:- sp3d2 corresponds to octahedral geometry.
What is the hybridisation of [Mn(h2o) 6] 2+?
Mn+2 in [Mn(H2O)6]+² has sp3d2 hybridisation and octahedral geometry using outer d orbital(4d).
What is the hybridisation of chromium in dichromate ion??
Dichromate ion is: Cr2072-. hybrid state is:sp3d. one lp on each Cr atom 4 pi bonds 2 0- so overall charge is 2- structure not possible to be shown here. Bye
What are the hybridization orbitals around O in H2O2 and around C and N in CH3CN?
In H2O2, the oxygens are both sp3 hybridized, because they are tetrahedrons, therefore comprising of four hybrid orbitals (3 p's, 1 s (sp3)). In CH3CN (acetonitrile), the methyl C (the C atom attached to the three H atoms) is sp3. The C holding the triple bond with the N is sp hybridized because it only has two different groups attached to it. The N is also sp hybridized then, for the same reason - that it's participating in a triple bond. Think of it this way: if it has a triple bond, it's basically sp; if it has a double bond, it is basically sp2. There could possibly be extremely rare cases where this does not apply, but I have yet to apply them and I am wayyyy passed hybridization.