In a population of 200 mice, 98 are homozygous dominant for brown coat, 84 are heterozygous and 18 ar?
A) What is the allele frequency for “B” allele? for “b” allele? p(B) = (196+84)/400 = 0.7 q(b) = (36+84)/400 = 0.3 B) What is the genotype frequency of BB, Bb, and bb p^2(BB) = 0.7^2 = 0.49 2pq(Bb) = 2 x 0.7 x 0.3 = 0.42 q^2(bb)= 0.3^2 = 0.09 C) What is the phenotype frequency of brown, white? Freq brown (B-) = p^2 + 2pq = 0.49 + 0.42 = 0.91 Freq white (bb) = q^2 = 0.09
Hardy Weinberg Help Please?
1) In a population of pea plants, green peas are the result of a homozygous recessive condition. If the frequency of the allele for this condition is 0.20, what percentage of the individuals in the next generation would be expected to be heterozygous? Is it 4%, 19%, 32% or 64%? 2)In a population of tree frogs, the allele that causes yellow eyes (Y) is dominant over the allele that causes orange eyes (y). If 85% of the frogs have yellow eyes, what is the frequency of the dominant allele? Is it .15, .39, .52 or .61? 3) The wing color of a certain species of moth is controlled by an allele at a certain locus. gray (G) is dominant to white (g). A scientist studied a large population of these moths, tracking the frequency of the G allele over time, as shown in the figure. Assuming that the population was in Hardy Weinberg equilibrium for this gene, what percentage of the moth population was homozygous recessive (gg) in 1960? Is it 4%, 32%, 50% or 64%? Figure: http://tinypic.com/r/34pgear/6
Allele frequency help?
That's nice > What is the recessive allele frequency for the population? 150 pigs have 300 allleles total. Let's assign q to be the frequency of blue eye alleles and p to be the frequency of, um, nonblue eye alleles. q = 180/300 = 0.6 (answer) > What is the expected number of pigs with the blue eyes within the population? To make this calculation, you have to assume that the population is in Hardy-Weinberg equilibrium. Let's make that assumption. Messrs Hardy and Weinberg give us this equation p^2 + 2pq + q^2 = 1 where, in the population, p^2 is the proportion of one of the homozygotes 2pq is the proportion of the heterozygotes q^2 is the proportion of the other of the homozygotes Looking for blue eyed pigs, q^2 * populationsize = 0.6 * 0.6 * 150 = 54 blue-eyed pigs (answer) What is the heterozygous frequency within the population? Note that p + q = 1 so p = 1 - q = 1 - 0.6 = 0.4 Looking for the frequency of heterozygote pigs, 2pq = 2 * 0.4 * 0.6 = 0.48 (answer)
Hardy weinberg- allele frequency help?
. In a hypothetical population of tree swallows, 18 individuals are homozygous for the c4 allele, 22 individuals are heterozygous for the allele, and 10 individuals lack the allele. What is the frequency of the c4 allele? a. 0.29 b. 0.36 c. 0.40 d. 0.58 e. 0.80
If a father has an O blood type and a mother has an AB blood type, what will be the child’s blood type?
It would be either A or B blood group.As the father has O blood group( recessive and is expressed only if present in homozygous condition) so possible alleles are O and O.The mother has AB blood group, which means the possible alleles would be A and B.Thus, the child may either have AO gene pair (2 alleles make one gene pair) or BO gene pair. This implies that either the child would have A or B blood group as I mentioned earlier too that O is recessive and is expressed only in homozygous condition. And here the resultant being heterozygous i.e., AO and BO, O would not be expressed.Thank you
Hardy-Weinberg problem?
It's not a Hardy-Weinberg problem. Instead, you're supposed to count the alleles. Let's say the gene is for yellowness with Y dominant and y recessive. Let's suppose that your population is 100 animals, which would be 200 total alleles. You have: 70 homozygous dominant = 70 Y alleles + 70 Y alleles 21 heterozygotes = 21 Y alleles + 21 y alleles 9 homozygous recessives = 9 y alleles + 9 y alleles You have: 70 + 70 + 21 Y alleles = 161 Y alleles 21 + 9 + 9 y alleles = 39 y alleles Frequency(Y) = 161 / 200 = 0.805 (answer) Frequency(y) = 39 / 200 = 0.195 (answer) You're done. == The next part of the problem will probably ask, "Is this population in Hardy-Weinberg equilibrium?" That would be when you check p^2 = 0.648 does not match the observed 70% 2pq = 0.314 does not match the observed 21% q^2 = 0.380 does not match the observed 9% Your population is NOT in Hardy-Weinberg equilibrium. (I'm eyeballing this; you're probably going to have to prove it with some statistical test.) Your homozygous recessives are dying off faster than the ones with the dominant phenotype.
Genetics Help! Phenotype probability?
In a cross between AaBbCcDD and AabbCCDd, what is the probability of an offspring with PHENOTYPE Dom A, rec b, Dom C, and Dom D? I'm taking molecular biology and we can either do the cross (tetrahybrid) or do the math calculations; for time sake I know how to do the cross but cannot figure out how to calculate the probability with just using the fractions. Help! Thanks.
How can I find the number of gametes through genotype?
Number of genotypes is equal to 2 to the power n. Here n stands for number of heterozygosity. In Aabb n is equal to 1 in AabbCc n is equal to 2, so you will have 4 genotypes. Now by branching system or fork system you can write down all the eight genotypes
BIOLOGY HOMEWORK! PLEASE HELP?
In a population there are 156 homozygous dominant individuals, 62 heterozygous individuals and 37 homozygous recessive individuals. What is the frequency of each genotype and each allele?