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Where Do I Add Parentheses In This Equation For It To Equal 10 Pls Help Me 1- 3 - 5- 7=10

Rewrite the expression with parentheses to equal the given value 3×4-1+2 value 11 and 5+3×2-6 value 10?

3×4-1+2=11
3x(4-1)+2=11

5+3×2-6=10
(5+3)×2-6=10

Pls help add dissimilar fractions:1/3+1/6,1/2+1/6,7/10...

You have to make the denominator the same to add or subtract a fraction.

1/3 + 1/6 <----------- You would multiply the top and bottom number of the first fraction by 2- this will make the bottom number the same for both fractions- you don't have to do anything to the second fraction.

1/3 x 2/2= 2/6. You multiply each number of the fraction by 2.

Now you can add the the 2 fractions.

2/6 + 1/6= 3/6 or simplified is 1/2

Do the same for each problem. Just find a common denominator.

Add parentheses to make this equation true...6x6+6x6-6=426?

all and sundry utilising PEMDAS and getting 9 look making a similar assumption that 6÷2(a million+2) == (6÷2) * (a million+2), while fairly you're able to be able to desire to get (6÷2)*a million÷(a million+2). could desire to you take care of it as a fragment PEMDAS will become beside the point and additionally you're able to be able to resolve it in any order you like. 6÷2(a million+2) ==6/ 2 * (a million+2) == 6 * a million / 2*(a million+2) == 6 * a million/2 * a million/ (a million+2) you could clean up this is any order you love once you have have been given lawsuits that there is fractions inflicting subjects, take them out of the brackets 1st 6 / 2*a million + 2*2 = 6 / 2 + 4 = 6 / 6 = a million or clean up the brackets 1st then clean up the denominator 6 / 2* (a million+2) = 6/ 2* (3) = 6 / 6 = a million in case you prefer to handle the 6 ÷ 2 separately high quality you basically could desire to remember that a / b * c = a * (b * c)^-a million = a * b^-a million * c^-a million subsequently (6 / 2) * (a million + 2)^-a million = 3 * (a million + 2)^-a million = 3 ÷ (a million + 2) = 3 ÷ 3 = a million you basically could desire to remember the question is calling what's a÷b the region a = 6 and b = 2(a million+2), and which you basically can not in any circumstances purely circulate the (a million+2) from the denominator to the numerator as this is fixing the question, 6(a million+2)÷2, it fairly is completely unique!

Pls. answer this! help me. math grade 7 question. immediately.. pls.. hellppp me!!?

here how it goes:
given 2 points, find the equation f each line. Write each equation in standard form:

17. L (1/2,0) & M (3, 2 1/2) <--it's a mixed number,, three and one half

2. H (1/3, 1) & P (2 2/3, 5)

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given the intercepts of a line, find its equation in standard form.

1..a= 2/3, b= -2
2.. a= 7/3 b= 1/2

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write the equation of the line in general form

1. the slope is 5 and the y-intercept is 3

2. the line crosses the y-axis at (0,10) and has a slope of 3

3. what is the equation of x and y axis?

4. if a line passes through the origin and a second point whose x and y coordinates are equal, what is an equation of a line?

5. the line that passes through the point (-1, 4) and has the same slope as the graph of 2x-y=8
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pls. take time in answering
this is not just only a homework but i have a lot of homework but this is the one which is very crooky. please help me.
thank you!


this a answer community, dont scold me la, im just asking u to help me.

sharing ur blessings!

thank u

Math hw pls help dont noe how 2 do hem thanks u.. show all work!!!!!!!1?

#1. You want to end up with 4n on one side of the equals sign and all the other numbers on the other side. To do this, subtract 11 from both sides. You now have 4n = -4. Once you have your unknown quantity all by itself, you can simplify the equation. Divide both sides by 4. The answer is n = -1.

#2. When there are parentheses in an equation, you want to get rid of them first. 6(y+2) is the same as 6y + 12. You multiply the number outside the parentheses by both items that were inside the parentheses and keep the same sign (+, -, etc.) between them. 2(y-1) is the same as 2y - 2. So now you have 6y + 12 + 2y - 2 = 6. Just do the addition and you get 8y + 10 = 6. Solve the same way as #1, by subtracting 10 from each side, then dividing each side by 8.

#3. Same as #2. Simplify each item in parentheses. Since (x-5) doesn't have a number in front of it, you can just remove the parentheses. They're not needed. -3(x-2) is a bit trickier, since both the terms have a minus sign. -3 times x = -3x, but -3 times -2 results in +6. When you multiply 2 negatives together, you get a positive. So, one side of your equation is x-5-3x+6. The other side, multiplied out, is 5x+5. Now, you want to get all the "x"s on the left and all the integers on the right. First, do all the addition and subtraction on the left. x -5 -3x + 6 equals -2x +1. Now your equation is -2x +1 = 5x + 5. Subtract 1 from each side to get -2x = 5x + 4. Subtract 5x from each side to get -7x = 4. Divide both sides by 7 to get your answer.

How do i do this equation;(4a+5)(3a-7)=0?

You have to use FOIL-ing, First Outer Inner Last.

So the first step is to multiply the First two in the parentheses:
(4a+5)(3a-7)=12a^2

Then you multiply the Outer two:
(4a+5)(3a-7)=12a^2+15a

Then you multiply the Inner two:
(4a+5)(3a-7)=12a^2+15a-28a

Then you multiply the Last two:
(4a+5)(3a-7)=12a^2+15a-28a-35

So now you have:
12a^2+15a-28a-35

Combine like terms to get:
12a^2-13a-35

10 POINTS How to solve this equation 2/x+8 - 6/x+7 = -5 ?

Put the LHS over a common denominator of (x+8)(x+7)

(8(x+7) - 6(x + 8)) / (x+7)(x+8) = -5

Multiply by the denominator

8(x+7) - 6(x + 8) = -5(x+7)(x+8)

Expand out and collect the terms

5 x^2 + 77x + 288 = 0

Factorize

(x+9) (5 x+32) = 0

x = -9 or -32/5

Check -9 in equation from equation

2/-1 - 6/-2 = -5

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