What is the equation of a circle whose center is at the origin and whose radius is 9?
(x - h)² + (y - k)² = r² is the standard equation for a circle whose center is at the point (h, k) and whose radius is r.Since the center of the circle is at the origin, i.e., at the point (0, 0), and its radius is r = 9, then the equation for this circle in standard form is found by substitution as follows:(x - h)² + (y - k)² = r² (x - 0)² + (y - 0)² = 9²x² + y² = 81 is the equation of a circle in standard form whose center is at the origin and whose radius is 9.
X^2 + Y^2 = 169 find the center and the radius of the equation?! ???/?
Notice that the x^2 and y^2 coefficients are the same, so this equation's graph is a circle. Recall that the standard equation for a circle centered at (h, k) with a radius of r is: (x - h)^2 + (y - k)^2 = r^2. Since x = x - 0, y = y - 0, and 169 = 13^2, we can write the given equation as: (x - 0)^2 + (y - 0)^2 = 13^2, which fits the above standard form with h = k = 0 and r = 13. Therefore, the center of the circle is at (0, 0) (the origin) and its radius is 13. I hope this helps!
1. Write an equation for a circle with center (-2, 4) and radius 7.?
2. Which equation has the graph of a circle with the center as its origin and radius 2? A. x^2 + y^2 = 2 B. x + y = 4 C. x^2 + y^2 = 0 D. x^2 + y^2 = 4 3. Write the equation in standard form x^2 + y^2 - 4x - 14y + 29 = 0 4. What is the length of the major axis of 7(x + 2)^2 + 2(y -2)^2 = 49? 5. The graph of (x + 2)^2 + 5(y - 4)^2 = 25 is the graph of an ellipse with center (-2, 4) A. True B. False
A circle of radius 2 centered at the origin traces clockwise starting from point (-2,0) when t=0?
Center = (0, 0) Radius = 2 Phase = + Pi Parametrization: x = - 2 cos(Pi t) y = - 2 sin(Pi t) 0 =< t =< 2
Find a function whose graph is the top half of a circle, whose center is the origin, with radius 3?
y= |√(9-x^2 )|