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Which Of The Following Values Displays The Ph Of An Acid A.3 B.8 C. 12

Calculating pH at the Equivalence Point?

Moles HBr = 0.096 L x 0.25 =0.024
Moles KOH = 0.0480 L x 0.50 =0.024
Moles strong acid = moles strong base => pH = 7

Moles ammonia = 0.0500 x 0.20 =0.0100
Moles HNO3 = 0.0500 x 0.20 = 0.100
NH3 + H+ >> NH4+
total volume = 0.100 L
[NH4+] = 0.0100 mol / 0.100 L =0.100 M
NH4+ + H2O <----> NH3 + H3O+
K = Kw/ Kb = 5.6 x 10^-10 = x^2 / 0.100-x
x = [H+] =7.5 x 10^-6 M
pH = 5.1

Moles acid = 0.030 L x 0.50 = 0.015
moles NaOH = 0.030 x 0.50 = 0.015
CH3COOH + OH- >> CH3COO- + H2O
total volume = 0.0600 L
[CH3COO-] = 0.015 / 0.0600 =0.25 M
CH3COO- + H2O <---> CH3COOH + OH-
K = Kw/ Ka = 5.6 x 10^-10 = x^2 / 0.25-x
x = [OH-] = 1.2 x 10^-5 M
pOH = 4.9
pH = 9.1

Which of the following acids is the weakest. The acid is followed by its Ka value. HELP PLEASE?

The strongest acid will have the largest Ka value. so the answer is E.

Ka is the "dissociation constant" of an acid and it is calculated by finding the product of the concentrations of the two ions that result from the dissociation of the acid and dividing that by the concentration of the un-dissociated acid that is left
For example, the equation for the Ka for C6H5CO2H looks like this

Ka=[H+][C6H5CO2-]/[C6H5CO2H]

A higher concentration of H+ means a lower pH (pH=-log[H+]) which means a stronger acid. As you can see from the equation, the bigger the [H+], the bigger the Ka.

And as some extra help:
The concentrations of the two ions will always be the same and the concentration of the un-dissociated acid will be the original concentration minus the concentration of the ions.

So for the generic acid dissociation HA --> H+ + A-

Lets say that 'x' represents the concentration of [H+] and [HA] is the acid concentration before dissociation.
The Ka equation will look like this:

Ka=(x^2)/(HA-x)

Which of the following values displays the pH of an acid? A.3 B.8 C. 12?

A. 3, the lower the number the more acidic.

Out of HF, HCl, HBr and HI, which has the lowest and highest boiling point and why?

Boiling point for the Acids mentioned is 19.5 °C HF, -85.05 °C HCL, -66 °C HBr and -34 °C for HI. The boiling point of a system depends upon the intermolecular interactions. Higher the strength of these interactions, higher is the value of boiling point.Now considering the above systems i.e HI, HBr, HCl dominant interactions would be van der Waals forces; as Hydrogen bonding in these systems is nearly impossible ( reason u can find in this link Which compound, HBr, HF, HCl, or HI, exhibits hydrogen bonding between its molecules? | Socratic ) Hence the boiling point of HI is highest because of it's big molecular size (the intermolecular van der Waals forces would be strongest between the large sized molecules in comparison to smaller ones- van der Waals forces ). This not the case with HF because the dominant forces are H-bondings, which are much more stronger intermolecular forces than van der Waal's forces. Hence the bp of HF is highest among the listed acids in contrast to the lowest molecular size among the listed molecules.

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Out of HF, HCl, HBr and HI, which has the lowest and highest boiling point and why?

Boiling point for the Acids mentioned is 19.5 °C HF, -85.05 °C HCL, -66 °C HBr and -34 °C for HI. The boiling point of a system depends upon the intermolecular interactions. Higher the strength of these interactions, higher is the value of boiling point.Now considering the above systems i.e HI, HBr, HCl dominant interactions would be van der Waals forces; as Hydrogen bonding in these systems is nearly impossible ( reason u can find in this link Which compound, HBr, HF, HCl, or HI, exhibits hydrogen bonding between its molecules? | Socratic ) Hence the boiling point of HI is highest because of it's big molecular size (the intermolecular van der Waals forces would be strongest between the large sized molecules in comparison to smaller ones- van der Waals forces ). This not the case with HF because the dominant forces are H-bondings, which are much more stronger intermolecular forces than van der Waal's forces. Hence the bp of HF is highest among the listed acids in contrast to the lowest molecular size among the listed molecules.

Calculate the pH of 0.10 M KNO2 (aq). Ka for HNO2 is 4.3 x 10 ^ -4?

KNO2 is a strong electrolyte

KNO2 >> K+ + NO2-

NO2- + H2O <> HNO2 + OH-
initial concentration
0.10 . . . . . . . . . . .0 . . . . .0

at equilibrium
0.10-x . . . . . . . . . . . x . . . . . x

For this equilibrium

K = Kw / Kb = 10^-14 / 4.3 10^-4 = (x)(x)/ 0.1-x =2.32 10^-11

x = 1.52 10^-6

pOH =5.82

pH=8.18

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