What is the consequence of using a lower wattage power adapter with a laptop?
Let’s start by saying that I have done this. And… I’ve done it on more than one occasion, and I’ve done it on purpose to know what will happen.I ran a Toshiba Satellite A75 on a 90 watt adapter for a couple of months, while it required a 120 Watt adapter. Here is what happened. Under normal usage conditions… checking email, surfing the web… light tasks, the battery would get hot, but otherwise the laptop would perform normally. If I played any games, the laptop would turn off within 60 seconds of starting the game. If I did any CPU intensive tasks while not gaming, whether or not the laptop would turn off, depended on how long I ran the tasks for. If I removed the battery, the unit would not turn itself off when doing CPU intensive tasks outside of gaming, but gaming would still bring the laptop to shutdown… albeit just more like 20 minutes into it, instead of 45 seconds.I’ve tested laptops that required 90 watt adapters with 65 watt adapters.Is it dangerous? No. The laptop isn’t going to explode. The power adapter isn’t going to explode. The battery isn’t going to explode. What *will* happen then? All depends. Nothing might happen. Or… the laptop might turn off because it is trying to draw more power than is available.But it won’t explode. It won’t rise up and attack you either because you are starving it of power.
How long will a 12v/20 amp battery run a 35 watt TV?
Assuming the 20 Amp is 20Ah (amp-hours). First of all the tv is powered with AC voltage. Your power source is 12V 20Ah DC battery, so you will need an inverter to convert dc into AC. If your country uses 220V then you will need 12VDC to 220VAC 50Hz inverter, if 110V, then you will need 12VDC to 110VAC 60Hz inverter. Those inverters have an efficiency rating let’s say x (for ex: 0.8 or %80) so that the total power consumption with respect to battery is 35 / X, in our example 35 / 0.8 = 43.75 W, So the battery has 20Ah x 12V = 240 VAh (Wh). Since the usable amount of capacity in a lead-acid battery is 85% let’s say, so that 240Wh x 0.85 =~ 200Wh, By dividing 200Wh / 43.75W =~ 4.5 hours. This is a theoretical approach but the real result would be close to that one, to generalize the formula:h = (200 * x) / 35 = 5.71 * xx: efficiency of inverterh: the result