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Why Does The Chemical Formula In A Skeleton Equation Have To Be Written Corrrectly Before I Can

Why is oxygen in chemical equations written as O2, when the element itself is just O? Consider alkane+O2→CO2+H2O+energy. Are other elements written this way in chemical equations?

The element, oxygen, can exist in several forms, as atomic oxygen (O), or as the dimer oxygen (O2), or as the trimer ozone (O3). These are three distinct molecules with different structures and reactivities. Each form has a different chemical reactivity. The dimer is by far the most common form since it is much less reactive than the other two. So there are two reasons to write it as O2: 1. O2 is almost always the form of oxygen in a reaction, and 2. One needs to specify the form to describe how it will react. Other elements that usually exist as diatomic molecules are written as the dimer for the same reasons. These elements include all of the halogens.

Can someone help me write the skeleton equations?

Can someone help me answer this question and tell me how they got the answer?

Write skeleton equations for these reactions.
1.) Heating copper (II) sulfide in the presence of diatomic oxygen produces pure copper and sulfur dioxide gas

2.) When heated, baking soda (sodium hydrogen carbonate) decomposes to form the products sodium carbonate, carbon dioxide, and water.

Write the word equation for the following skeleton equation?

I am not sure why you are calling it a "skeleton equation". It should, however, be balanced:

CuCl2(aq) + 2 NaOH(aq) → Cu(OH)2(s) + 2 NaCl(aq)

The "word equation" for the above reaction is:

copper (II) chloride + sodium hydroxide → copper (II) hydroxide + sodium chloride

What are skeleton equations and how are they used in chemistry?

Skeleton equations or unbalanced equations are mostly used in chemistry. In a skeleton equation you put chemical formulas in place of chemical names. A skeleton equation doesn’t show the relative and balanced amounts of reactants and products. It’s regarded as a step to writing a complete chemical equation.Examples:Continuing with the electrolysis of water, we have a skeleton equation, "[math]H2O−>H2+O2[/math]" The formula for water is H2O; the formula for hydrogen is H2; and the formula for oxygen is O2. A skeleton equation is just a way of using the formulas to indicate the chemicals that were involved in the chemical reaction."[math]Mg+O2−>MgO[/math]" This skeleton equation shows that magnesium reacts with oxygen to form magnesium oxide. It also shows that the formula for magnesium is Mg, for oxygen is O2, and for magnesium oxide is MgO.Hope this helps!

Why should chemical equations be balanced?

The most important thing for balancing chemical reactions is for the Conservation of Mass, because mass can neither be created nor be destroyed (not in the case of Nuclear Reactions where Einstein’s Mass-Energy Equivalence comes into action).Balancing Chemical equations gives us an idea about the quantity of chemical reactants that are needed for the reaction.Without balancing we just know what kind of products are obtained but with balancing chemical reactions we can also know the weight of substance produced.Getting more advanced,we can also know the entropy changes in the reaction in turn the thermodynamic factors like Gibbs Energy and so on.But in a simpler level, balancing chemical reactions helps us to know the quantity of reactants required and quantity of products obtained.

How to write a chemical equation for Aluminum and Copper 2 chloride?

2Al + 3CuCl2 ----> 3Cu + 2AlCl3

Basically in this equation you're just substituting the Aluminum ion for the Copper in CuCl2. The aluminum ion has a +3 charge, so you have 3 Cl to balance the charges, since Cl has a -1 charge.

What does the symbol "triangle" in a chemical equation mean?

1. The triangle is actually the Greek letter delta which signifies change. A chemical equation will often have a delta H value listed with it, indicating the change in enthalpy for the reaction.

2. When balancing an equation, its generally best to handle the lone species (Cr and Fe in this case) last as you can easily manipulate their values to suit the rest of the equation as necessary.
So you would first balance the nitrates by putting a 3 in front of the iron(II) nitrate and a 2 in front of the chromium(III) nitrate. This means you now need to account for the 2 moles of Cr in the product side by putting a 2 in front of the Cr. Likewise, as 3 moles of Fe were present in the reactant side, to balance the equation you would put a 3 in front of the Fe.
Therefore your answer would be 2, 3, 3, 2.

3. This type of reaction simply entails exchanging ions and balancing charges. Rb and OH have +1 and -1 charges, respectively. PO4 has a -3 charge. Depending on the relative concentrations of the reactants you may achieve complete neutralization or generate acid-salts. Assuming the reaction goes to completion, you would end up with H2O and Rb3(PO4).
As there are 3 moles of Rb present in the products, we would put a 3 in front of the RbOH on the reactant side to balance the Rb. Counting H's, we realize we have 6 on the reactant side but only 2 on the product side, so we also place a 3 in front of the H2O. The O's and the PO4 are now balanced, as well.
Hence the stoichiometric coefficients would be 3, 1, 3, 1.

4. A combustion reaction refers to a substance being burned in oxygen so that can be ruled out immediately. A single-replacement reaction, as the name suggests, would involve one substance replacing another, which clearly isn't happening here. A decomposition reaction, which is also fairly aptly named, involves a substance being decomposed. Which means broken down. Again this is clearly not the case.
Thus, by simple process of elimination, this is a combination reaction. A combination reaction typically involves, quite shockingly, combination of atoms.

Chemical equation for reaction of sulfur trioxide and water.?

Write a balanced chemical equation for the reaction of sulfur trioxide and water.

a.2 SO3(g) + 2 H2O(λ) → 2 H2SO3(aq) + O2(g)
b.2 SO3(g) + 2 H2O(λ) → H2SO4(aq) + H2S(g) + 2 O2(g)
c.SO3(g) + H2O(λ) → SO4(aq) + H2(g)
d.SO3(g) + H2O(λ) → SO42-(g) + H2(g)
e.SO3(g) + H2O(λ) → H2SO4(aq)

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