Volume containing 200 micromoles of a 0.8 M glucose solution?
Hoping someone can help me with this. I have a 0.8 M solution of glucose (C6H12O6) and need to work out the millilitre volume that will contain 200 micromoles of glucose. I am sure the answer I came up with (0.00025 mL) is incorrect. Please show me how to work this out as I'm not sure of all the steps in the formula(s) and I think I have missed something out :P
How to Calculate average Volume of a solution?
You want an answer but you do not give us any information. This does not help. I can guess that you are titrating a fixed and constant volume ( say 25ml) of a Ca 2+ containing solution. You have used a standard EDTA solution in your burette. You have done 3 test runs, and you have obtained the following results: Volume of EDTA solution used: Test 1 = 27.6ml Test 2 = 27.55ml Test 3 = 27.65ml Average volume of EDTA solution used = ( 27.6+27.55+27.65)/3 = 82.8/3 = 27.6ml average volume of EDTA solution used in titration. This is the value that you use in your calculations. However, beware, you cannot take some widely differing volumes for the EDTA solution, which you have otained as a result of poor laboratory methods, average these and hope to get a workable result for volume: For instance, if the volume results had been: 27.6, 27.55 and 24.3 - you cannot use the 24.3 value Or if the results had been: 22.5, 28.7 and 33.8, you cannot use any of these values. There is some statistical law which governs what values can be used and which cannot be used - but I am not a mathematician/ statistician, so I have to use my common sense and reject whatever seems unreasonable.
Working out volume of an enzyme used in an assay from initial velocity etc?
A 20mM solution of dopamine is diluted 1 in 8. The diluted dopamine solution was used for a tyrosinase assay that had a total volume of 1.5mL. 20μL of tyrosinase was used for the assay. The reaction was followed spectrophotometrically and a progress curve plotted from the spectrophotometric data. Using the progress curve, the initial velocity was calculated as 0.30 ΔA/min. The assay was repeated as above, with a different volume of tyrosinase. The initial velocity was 0.01 ΔA/s. What volume (in μL) of tyrosinase was used for the assay? (do not include units in the answer you type).
Work out the volume occupied by 100 g of sugar solution with a density of 1.100 g/L?
well Density = mass/volume so 100/ 1.1 = 90.9 L
Please show the working out again in thismath solution?
A metallic sheet is8m by 5m. Its thickness is 3 cm. If the metal weighs 3.6 per cm cubed, then its total weight is A. 4,32 kg B. 43.2kg C.432kg d.4 320kg e. 43200kg
If 3.78g of CuNO3 is dissolved in water to make a 0.680 M solution, what is the volume of the solution?
Molarity is moles per litre. First we work out how many moles is 3.78g of CuNO3. We need to know the atomic mass of CuNO3. Looking at the periodic table it is 63.546 (Cu) + 14.007 (N) + 3x15.999 (O3) = 125.55. Atomic mass is g/mol. So we have 3.78g / 125.55g/mol = 0.0301 mol . Now, as the solution is 0.680 mol/L, then the volume is 0.0301mol / 0.680mol/L = 0.044L . It helps to try to always put the units next to the numbers so then you can work out what units cancel each other out. Happy chemistry!