Write the equation of the line with given slope and y-intercept. Then graph each line using?
In order to determine the equation of the line with slope m = -3/4 and passing through P(0, 8), use the point-slope formula: y = mx + b P(0, 8) ==> x: 0; y = 8 m = -3/4 Substitute the given values to the formula y = mx + b y = (-3/4)x + 8 y = -3x/4 + 8 ------>>>Slope-Intercept form <<< answer>>> To determine the Standard equation of the line, simplify the slope -Intercept form; y = -3x/4 + 8 y = (-3x + 32)/4 4y = - 3x + 32 3x + 4y - 32 = 0 ------>>> Standard Equation <
Write the equation of the line given the slope and the y-intercept.?
first link (below) discusses, describes and provides examples for Straight-Line Equations: Slope-Intercept Form I think the most useful form of straight-line equations is the "slope-intercept" form: y = mx + b This is called the slope-intercept form because "m" is the slope and "b" gives the y-intercept. (For a review of how this equation is used for graphing, look at slope and graphing.) I like slope-intercept form the best. It is in the form "y=", which makes it easiest to plug into, either for graphing or doing word problems. Just plug in your x-value; the equation is already solved for y. Also, this is the only format you can plug into your (nowadays obligatory) graphing calculator; you have to have a "y=" format to use a graphing utility. But the best part about the slope-intercept form is that you can read off the slope and the intercept right from the equation. This is great for graphing, and can be quite useful for word problems. Copyright © Elizabeth Stapel 2000-2011 All as a last resort, enter the criteria at the web second page Find the Equation of a Line Given That You Know Its Slope and Y-Intercept
How to write an equation of a line parallel to the graph 9x +3y=6 through (5,3)?
I prefer using the slope/intercept method. 9x+3y=6 divide by 3 3x+y=2 subtract 3x from both sides y=-3x+2 this gives you an equation with a slope of -3. Every line parallel to this one has the same slope. y=-3x+b rewrite the equation with an unknown displacement (b) 3=-3(5)+b replace x and y with the x- and y-coordinates of the point it goes through 3=-15+b simplify and then solve for b 18 = b put b into your new equation y=-3x+18
Graph the line with slope -1 passing through the points (3,-3)?
o.O; Just make a graph with y-axis vertically, x-axis horizontally, center is 0. Then go 3 units to the right, then 3 units down, and mark (3,-3). Then draw the line with a slope of -1 through it, which means that the line will go up 1 and to the left 1 diagonally, or down 1 and to the right 1 diagonally. Basically, it's just the line y = -x, which is a diagonal line from top left to bottom right passing through the origin.
Write the equation of a line perpendicular to the graph 2x-5y=0 that passes through the point (-2,3)?
Put the given line in slope intercept form y = mx + b, where m is slope and b is y-intercept: 2x - 5y = 0 5y = 2x y = 2x/5 So, slope is 2/5. The slope of a perpendicular line will be the opposite reciprocal: -5/2 Now, use point-slope form y - y1 = m(x - x1) where m is the slope and (x1, y1) is a point it goes through: y - 3 = -5/2(x + 2)<====ANSWER (point-slope form) Perfectly acceptable form, but here it is in slope-intercept and standard forms: y - 3 = -5x/2 - 5 y = -5x/2 - 2<====ANSWER(slope-intercept form) 2y = -5x - 4 2y + 5x + 4 = 0<====ANSWER(standard form)
What are the steps to graphing the linear equation 12x-6y+3=0?
There are 2 ways to approach this the first is to find the x and y intercepts. To find the x intercept subtract 3 from both sides of the equation.12x -6y=-3Substitute a zero for the x.12(0) -6y=-3Simplify-6y = -3Solve for y by dividing both sides by -6-6y÷-6 = -3÷-6Simplifyy = 1/2So when x = 0 y = 1/2 as a point it is (0, 1/2). Graph this point. Now repeat the process only use zero for y.12x -6(0)=-312x = -3x= -3/12 Or -1/4Coordinate pair for the point is (-1/4, 0). Graph this point. Now use a straight edge and connect the two points.Most preferred way change the equation from standard form to slope-intercept form. We do this by solving the equation for all y values.Subtract the constant term to get12x -6y=-3Subtract the term with x variable.-6y = -12x -3Now divide everything by -6 the coefficient of y.Finally simplify.-12÷-6 =2 and -3 ÷-6 = 1/2y=2x +1/2
Write an equation in slope-intercept form for each line described.?
slope-intercept form: y = mx + b a) Points are (1,0) and (0, -4) slope = = (y2 - y1) / (x2 - x1) = -4/ -1 = 4 y - y2 = m(x - x2) y - 0 = 4(x - 1) y = 4x - 4 b) y = -1 c) y = 0
Which equation represents the equation of a line with a slope of 0 at all points on the graph?
Which of the following mathematical expressions represents the equation of a straight line with a slope of zero at all points on a graph with Y on the vertical axis and X on the horizontal axis? a. Y= a + X b. X = bY c. X = a d. Y = a