X X/6 = -5 How Do You Do It

If x^(x^4) = 4, what is the value of x^(x^2)+x^(x^6)?

Your question demands a chain like[math]x^{x^4} = 4[/math]So, what do we do?Well I drew the graph of [math]y = x^{x^4}[/math] on Desmos graph and checked the value of x at [math]y = 4[/math]So x is 1.4142 which apparently is [math]\sqrt {2}[/math]So the number is [math]\sqrt {2}^{\sqrt {2}^2} + \sqrt {2}^{\sqrt {2}^6}[/math][math]= (\sqrt {2}) ^ 2 + 2^3[/math][math]= 2 + 8 = 10[/math]

How do I solve the problem x+2-x=x+6-x+2?

x + 2 - x = x + 6 - x + 2Arrange variables on one side and numeric values on other sideX - x - x + x = 6 + 2 - 22x - 2x = 6Take x common from L. H. SX ( 2 - 2) = 6X = 6/(2 - 2)X = 6 / 0X = not defineAny no. Divide by zero is undefined..

How do I solve this equation: [math]x(x+2) =48[/math]?

First, subtract 48 from both sides:x(x+2)-48 = 0Now, use the FOIL method to distribute the x to the (x+2)x^2 + 2x - 48 = 0Now, factor this trinomial:(x+8)(x-6) = 0Double-check that the factoring was correct by using the FOIL method to expand it:x^2 - 6x + 8x - 48x^2 + 2x - 48Okay! So the factoring was correct:(x+8)(x-6) = 0In order for this to be a true statement you need to look for values of x such that one set of parentheses equals 0, and thus multiplies by the other set of parentheses with a resulting product of 0.In other words, you need a value for x that cancels out the other term in the parentheses.The first set of parentheses:(x+8)You need to add something to the +8 to make it equal to zero. In this case, you would add -8, and that is your first of the two values of x.The second set of parentheses:(x-6)Again, you need to add something to the -6 to make it equal to zero. In this case the value of x equals 6.So your two values of x are -8 and +6.To double-check that these solutions are correct simply substitute for x in the original equation:x(x+2) = 48x = -8-8(-8+2) = 48-8(-6) = 4848 = 48~~~~~~~x(x+2) = 48x = 66(6+2) = 486(8) = 4848 = 48So there are two solutions for x to the original equation, and the two solutions are -8 and +6.

What is the value of Lim x->0 (xsin (sinx)-sin^2(x)) /x^6?

This sum is invalid as u can't eliminate 1/x at last and ur ans is tending to infinity but still

How to hack intelliscreenX for ios 6.x.x?

The creators of this app are the ones who crack a lot of the other popular Cydia tweaks so they're good at finding vulnerabilities in their own apps they create which makes intelliscreenX extremely hard to crack.Since this app has been out a pretty long time and we still haven't seen a cracked version I doubt we'll ever see one.

How do MIT course numbers work in course 6?

6.0XX - Basic Undergraduate Subject6.SXXX - Special Subject in Electrical Engineering and Computer Science (typically either a class offered over IAP or an "experimental" class the department is testing out)6.1XX - Undergraduate Laboratory Subject 6.UXX - Senior Project6.2XX - Systems Science and Control Engineering6.3XX - Electronics, Computers, and Systems6.4XX - Probabilistic Systems and Communication 6.5XX - Bioelectrical Engineering6.6XX - Electrodynamics6.7XX - Solid-State Materials and Devices6.8XX - (Advanced Undergraduate and Graduate Level) Computer Science6.881-6.884 - Advanced Topics in Artificial Intelligence 6.885-6.888 - Advanced Topics in Computer Systems 6.889-6.893 - Advanced Topics in Theoretical Computer Science 6.894-6.896 - Advanced Topics in Graphics and Human-Computer Interfaces6.9XX - Miscellaneous 6.THG - Graduate Thesis 6.THM - Master of Engineering Program Thesis 6.UR - Undergraduate Research in Electrical Engineering and Computer Science

How do I use FaceTime?

There are a few ways to do this, and there are a few different types of FaceTime. It’s kind of confusing but it really is dead simple if you use the most popular route, call to video:Call to VideoLet’s assume you want to just do a “video chat”. That’s simple as can be. Call someone like normal (with their phone number). If they’re using an iPhone* you’ll see a FaceTime button on your screen. Tap it and boom, FaceTime. You’ll want to be sure your network signal is decent (wi-fi is best) but that’s about it.Video (No Call)Alternately you can open their contact (in the Phone or Contacts app) and tap on the video camera icon to initiate a FaceTime call without having to begin a phone call.Voice OnlyYou can tap the phone icon in someone’s profile and it’ll ask you if you want to dial the number over the phone or use FaceTime Audio (which is FaceTime without the video, weird name I know - ignore the “face” part). The difference in audio quality is like night and day when compared to a regular phone call. It’s also encrypted for an extra measure of security.*This only works with Apple devices (not Android). Both of you will need to be sure FaceTime is turned on in Settings > FaceTime. This is the default so it should just work.

How do I calculate lim (x,y) to (0,0) of (xsiny-ysinx)/(x^2+y^2)?

Since x and y both approach 0, we can take the sin(u)=u-u^3/6 approximation as close enough for small u. Then(x*sin(y)-y*sin(x))/(x^2+y^2)=(x*(y-y^3/6)-y*(x-x^3/6))/(x^2+y^2)=(x*y^3-x^3*y)/(6*(x^2+y^2))=x*y*(y^2-x^2)/(6*(x^2+y^2)) Now we can see how this behaves by noting the 3 cases y>>x, y<0x*y*(-x^2)/(6*x^2)=-x*y/6 which is 0 as x,y->0 andx*t*x*(t^2*x^2-x^2)/(6*(x^2+t^2*x^2))=x^2*t*(t^2–1)/(6*(t^2+1)) and not matter what real value t has, this is 0 as x (and hence y)->0The denominator is non-negative, so there is no path y=y(x) which could make the denom vanish, unlike the problemx*y/(x^2-y^2) which along the line y=m*x has a value m/(1-m^2) but along the curve y=x^2 we get x^3/(x^2-x^4)=x/(1-x^2) which goes to 0 as x->0.