An object is placed 24.2 cm in front of a diverging lens of focal length 12.1 cm.?
a) Find the image distance. Answer in units of cm b) Find the magnification. c) Describe the image. 1. None of these 2. real, inverted, smaller 3. real, inverted, larger 4. virtual, upright, larger 5. virtual, upright, smaller 6. virtual, inverted, smaller 7. virtual, inverted, larger 8. real, upright, smaller 9. real, upright, larger
Diverging lens focal length = 20cm, Image distance? with object distance of 40cm?
An object is placed in front of a diverging lens with a focal length of 20.0 cm. a) Find the image distance for an object distance of 40.0 cm. Answer in units of cm. find magnification please??
A convex lens of focal length 10 cm is placed at a distance of 12 cm from wall . How far from the lens ...?
Lens formula is 1/v - 1/u = 1/f Sign convention is distance from the center of the lens to be positive in one direction and negative in the other. => 1/12 - 1/u = 1/10 => 1/u = 1/12 - 1/10 = - 1/60 => the object to be place on side opposite to that of the wall at a distance of 60 cm. from the lens.
A 5.00 cm high object is located 39 cm in front of a convex lens of focal length 20.0 cm.?
A 5.00 cm high object is located 39 cm in front of a convex lens of focal length 20.0 cm.? I will do the first one and you get the idea and attempt the rest yourself. However I give you my EXCEL file with the answers see first LINK. If you get stuck EMAIL me, though the last time I said that I got 10 points deducted, never found out why but I still say it anyway. Basic Lens equation (All things MUST be in the same units eq cm) 1/f = 1u + 1/v f is the focal length of the lens put NEGATIVE for a CONCAVE (diverging) lens u is distance from lens to the object on the left hand side of the lens (put negeative if on the right). v is distance from lens to the image on the right hand side of the lens. (will be negative if image on the left of the lens) Mag = -v/u (negative because image is upside down) So in our case we have 1/20 = 1/39 + 1/v 1/v 1/20 – 1/39 v = 41.052 cm to 2 dp to RIGHT of lens using calculator. keep number for mag calculation As V is positive this means the image is REAL Mag = -41.052 / 39 = -1.053x to 2 dp keep number for image size calculation Image Size = 5*Mag = -5*1.053 = -5.263 cm As this is negative this means the image is upside down (INVERTED)