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Chemistry Question I Just Cant Get Right

Chemistry question? I just can't seem to get this right!! Help needed!!?

I think that you may have a typo. Do you mean Cu(NO3)2 and not CuNO3?

If so, here you go:

Molar mass of Cu(NO3)2=187.56 g/mol

Convert 8.54g to moles:

8.54g*(1 mole/187.56 g)=0.045532 moles of Cu(NO3)2

Molarity=moles/volume (L), so volume= moles/molarity

0.045532 moles of Cu(NO3)2/ 0.560 M of CU(NO3)2=0.0813L=81.3mL


Second question:

Total volume of diluted solution from first dilution is 208mL; the total volume from the second dilution is 293mL. You will need the volumes to solve for the final molarity.

Use the following relationship:

M1V1=M2V2

and

M2V2b=M3V3

Where

M1=1.40 M
V1=66mL
M2=?
V2=208mL
V2b=104mL
M3=?
V2=293mL

Solve for M3:

[M1*(V1/V2)]=M2

Plug into second relationship

[M1*(V1/V2)]*V2b=M3V3

Simplify:

[M1*(V1/V2)]*(V2b/V3)=M3

M3=[M1*(V1/V2)]*V2b/V3=M3

M3=1.40*(66.0mL/208mL)*(104mL/293mL)

M3=0.158 M <= 3 significant figures

Ahh i cant get this chemistry question right! any help would be great?

A sample of gaseous PCl5 was introduced into an evacuated flask so that the pressure of pure PCl5 would be 0.4800 atm at 525 K.
But, PCl5 decomposes to gaseous PCl3 and Cl2.
At equilibrium the TOTAL pressure in the flask was measured at 0.8064 atm. Calculate Kp at this temperature for the reaction

PCl5(g) = PCl3(g) + Cl2(g)

Base your calculations on the reaction as written above

Chemistry Question?

CaCl2
111 g/mol
.2 mol/L
.2 L final vol

.2L x .2 mol/L x 111g/mol

cross out Ls and mols to get 4.44 g

i believe so, anyway. it's been a couple of years since i took gen chem. i'm assuming you're talking about college chem or AP chem...so hopefully you'll know how i arrived at the converted units up at the top and why those units at the bottom cross out.

Help me please solve this chemistry question!!!! I just can't get the right answer!?

M = mol / L = 5.0 mol / 2.0 L = 2.5 M for NOCl initially

K = [NO]^2 [Cl2] / [NOCl]^2

Let 2s = amount of NOCl that dissociates.
Then, [NO] = 2s
[Cl2] = s

K = (2s)^2 (s) / (2.5 - 2s)^2
K (2.5 - 2s)^2 = 4s^3
K (6.26 - 10s + 4s^2) = 4s^3
6.26K - 10sK + 4s^2K = 4s^3
4s^3 - 4s^2K + 10sK + 6.26K = 0
4s^3 - (6.4 x 10^-5)s^2 + (1.6 x 10^-4)s + (1.00 x 10^-4)

Try the polynomial equation solver at the following website: http://cosinekitty.com/solver.html
One of the roots for s is 0.0144.
[NOCl]eq = 2.5 - 2s = 2.5 - 2(0.0144) = 2.4712 M (or still 2.5 M to two sig figs)
[NO] = 2s = 2(0.0144) = 0.0288 M (or 0.029 M to two sig figs)
[Cl2] = s = 0.0144 M (or 0.014 M to two sig figs)

I can't seem to get this Chemistry question right, please help!?

Balanced equation:
CrBr2(aq( + 2AgNO3(aq) → 2AgBr(s) + Cr(NO3)2(aq)

How many questions can I get wrong on the SAT II chem and still score a 800?

Here’s my SAT Chem story. So I was working through the problems and as I went through, leaving some questions blank that I wasn’t sure about to come back to later. Turns out that I have awful time management so right as I’m about to turn back and deliberate on the blank questions, time is called.This is bad. Really bad. At this moment, I’m thinking that I’m going to need to retake this one.July comes around, and somehow, miraculously, I got an 800. So there’s the answer to your question. Just relax and don’t overthink it and I’m sure you’ll do great!

How do I study inorganic chemistry for JEE? I don't want to know the books or study material, I just want to know the method (i.e how to do it).

Hey,For starters, it would be best if you are in a reputed coaching institute.i will be covering some of the points on how to study inorganic i)while completing syllabus ii)after syllabus completion.i)During preparation-Chemistry need not be stressed upon too greatly during this period. i would recommend Focusing More on Maths and Physics during the early days(this does not mean that you completely ignore chem)1)Always attend every class attentively- even though if it doesn’t interest you still listen to what the teacher is saying. Although you might not feel it but this helps tremendously during later stages.2)Don’t leave the understanding part for later- although the mugging up stuff need not be stressed upon too greatly this time, but you have to do the parts which involves concepts and logic.ii)after syllabus completion-This is the period when you give equal weightage to chem, maths and physics. at even Later ending stages most of your focus should be on chem.Short notes is the soul of prepartion in this stage.Take a new register, study chapter wise and frame your one-word short questions on one page then turn over on the next page write the answers.EG-QuestionsAnswers on the next pageOnce you are done will all the chapters,start framing on questions that you couldn’t remember/do in mock tests.I had 600 of theese short Q/A when the J-M test Series of Allen ended.Now while you are doing this ,You have to read through and try to answer theese questions without looking at the answers on the next page everyday before sleeping(or any other time slot).Initially this takes around 10–20 minutes but at the end it takes about 45 minutes to go through all 600.Now when you J-M is over, revise these and cross-out the questions that were in ONLY in the syllabus of J-M. Star the ones that are v.imp for ADV.Start a new section which will include new framed questions that you learn in the 2 month window b/2 mains and advanced and all the questions you cant do in test series.But Make sure you read the whole thing and try to memorise by heart everyday at least once.Sort of like a Q/A with yourself.i had 800 of these short Q/A by J-adv.This did the trick for me.i used to score on an average 40–70% in chem but after i Did this i rarely went below 85%. Also never Hesitate to add another point to these.Hope this helps.Peace.

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