How many electrons flow in a 1 ampere current?
When 1 Coulomb charge flow through a wire in 1 second then the current through the wire is 1 AMPERE.I=Q/t1 Ampere = 1 Coulomb /1 SecondCharge on 1 electron = 1.6 x 10^-19 CoulombBy unitary method,If 1.6 x 10^-19 Coulomb / Second (Ampere) = Current by 1 electronthen, 1( Coulomb / Second) or (Ampere) = 1 / (1.6 x 10^-19) electronsi.e, 6.25 x 10^18 electrons.
What is unit of electric current?
The standard SI unit of electric current is the ampere, or more commonly amp for short. This unit is named after [André-Marie Ampère](André-Marie Ampère - Wikipedia), one of the early pioneers of electromagnetic theory.The easiest way to understand the ampere is to look at its units: coulomb per second [math]C/s[/math]. A coulomb is a measure of amount of charge —actually a number of charges: [math]6.242\times 10^{18}[/math](a coulomb is a number in the same way as a pair, dozen, or score). So an ampere is a measure of the “flow rate” of charge.To make things more complicated, there is a bit of a circle here. This is because the coulomb is actually defined in terms of the ampere. The institute of international standards defines the amp as the amount of current that produces a force of [math]2 \times 10^{-7} N/s[/math]. Thus a coulomb is the number of elementary charges flowing per second to generate the necessary current.
What is the magnitude of the current in amperes?
If there is nothing but hydrogen (H2) and water vapor in the gas collected,first we must find out how much water vapor is in the gas. At 25.5°C (298.5°K) the vapor pressure of water is 24.5 torr, so the partial pressure of H2 in the gas is 752-24.5 or 727.5 torr. At STP the volume of H2 would be 13.8 * (727.5/760) * (273/298.5) or 12.08 ml. Since 1 mole of gas occupies 22.414 liters at STP, we have 0.5389 millimole, or 5.389 * 10**-4 mole of H2. One mole of H2 contains 6.023 * 10**23 molecules, and we have 5.389 * 10**-4 mole, or 3.245 * 10**20 molecules of hydrogen, and each molecule requires two electrons to form. So we have a total of 6.49 * 10**20 electrons that have flowed during these 2.3 minutes (2 minutes and 18 seconds, or 138 seconds). One ampere is defined as a flow rate of one coulomb of electrons per second, and one coulomb equals 6.28 * 10**18 electrons. A total of 6.49 * 10**20 electrons, or 103.3 coulombs, flowed over a time of 138 seconds, so the flow rate in amperes was 103.3/138, or 0.748 ampere (748 milliamperes).
How is watt or joules related to electric current?
Current is measured in Amps which is movement of charge per unit of time. Watt is measurement of Power, and Joules is measurement of energy - power applied for length of time (units seconds).Power = (Voltage)x(Current) — this is units of WATTSEnergy = (Power in WATTS ) x( time seconds how long the power is applied) — this is in Joules.
Electric current is one of the 7 fundamental physical quantities thought it can be expressed as q/t why?
Le Système International d'Unites (SI or the modern metric system) employs seven base units from which all other SI units derive. length - meter (m) mass - kilogram (kg) time -second (s) electric current - ampere (A) thermodynamic temperature - kelvin (K) amount of substance - mole (mol) luminous intensity - candela (cd) The choice of electric current as the electromagnetic base unit does seem a bit odd since we commonly think of electricity as the flow of fundamental electric charges. The historical reason for using electric current as a base unit is that electric current is more easily measured than electric charge. All of the electromagnetic units are intimately interrelated. The electromagnetic base unit could as easily have been electric charge, voltage, conductance, resistance, capacitance, inductance, or magnetic flux. Electric charge can be defined as the time integral of electric current. See the Relationships of SI Units below. There is currently a proposal to redefine the ampere as exactly 6,241,509,479,607,717,888 elementary charges per second. This in turn would redefine the kilogram in electrical terms. This proposal has an advantage in that modern electrical measurements are far more accurate than measurement of mass.
Units is a derived unit?. In which unit do you express your measurement?
Which of the following units is a derived unit? a meter b second c ampere d density 2. You need to measure the brightness of a light bulb using the metric system. In which unit do you express your measurement? a meter b liter c kilogram d candela . The temperature of a liquid is 75°F. What is its temperature in °C? [°C = (°F- 32) x 5/9 and °F = °C x 9/5 + 32] a 75°C b 348°C c 24°C d 167°C
How we can express 'ohm' in terms of basic units?
If considering the SI units ( As explained here ), we'd find that there are seven basic units and they are:Meter for length, kilogram for mass, second for time, ampere for electric current, kelvin for temperature, candela for luminous intensity and mole for the amount of substanceSo we should reduce Resistance in terms of these basic units,We know ohms law as,[math]R = V/I[/math]Here I (current) has Ampere as its SI unit, but V (voltage) is not listed in basic SI units, so we further reduce it, From electrostatic we know,[math]V= E d [/math]Where 'd' is length having unit m (meter) but E (electric field) still is not in the list, so doing further, [math]E = \frac{1}{4*pi*ε} \frac{Q}{R^2}[/math]Q (charge) not in list,[math]Q= I t[/math]Finally !! 'I' is Ampere and 't' (time) Seconds,And now, SI unit of charge is '[math]A[/math] [math]s[/math]' ([math]Ampere[/math] [math]Second[/math])That of Electric field is [math]A[/math] [math]s[/math] [math]m^{-2}[/math] ([math]Ampere[/math] [math]Second[/math] [math]Meter^{-2}[/math])For Voltage its [math]A[/math] [math]s[/math] [math]m^{-1}[/math]So for Resistance it becomes [math]s[/math] [math]m^{-1}[/math] [math](Second[/math] [math]Meter^{-1}[/math])
How do I express charge in terms of two different SI base units?
There are 7 base units in SI:Meter for length—not relevant to electric charge;Kilogram for mass—not relevant to electric charge;Kelvin for temperature—not relevant to electric charge;Mole for amount of substance—not relevant to electric charge;Candela for luminous intensity—not relevant to electric charge;Ampere for electric current—oooh! That is the rate of flow of electric charge with respect to time, so this seems relevant;Second for time—oooh! We just said that time comes into play along with the ampere for electric charge.Thus the two relevant base units for electric charge are the ampere and the second, where 1 A = 1 C/s, so C = A · s, where C is the coulomb, the derived SI unit of electric charge.
In which smaller unit can we measure the small amount of current following in the circuit?
We measure current in ampere(A).for less current we prefer miliampere(mA).1mA=10^-3Afor less than mA we use microampere(uA).1uA=10^-6A.for less than microampere we can use unit picoampere(pA).1pA=10^-12A.