The vertical major axis is length 18, and the minor axis of length 10?
Since it is vertical the a^2 lies under y and b^2 under x. The answer is d.
Find the standard form of the equation of the ellipse with given Foci: (0,0) & (4,0) and Major Axis Length of 18?
The center is at (2,0). The minor axis is sqrt(9^2 - 2^2) = sqrt(77). (x - 2)^2 / 81 + y^2 / 77 = 1.
Find the center, vertices, and foci of the ellipse with equation 3x^2 + 6y^2 = 18?
convert to standard form x^2 /6 + y^2 /3 = 1. so it is in the x direction. a =distance to vertex b =distance to minor axis endpoint c = distance to focus a^2 = 6, b ^2 = 3 a = +-sqrt6 c^2 = a^2 - b^2 c^2 =3, c = +-sqrt3 so your second answer is correct.
Find the equation of an ellipse X^2/M =Y^2/N=1. M, N>0 center is at orignin,major axis is 18 minor axis is 6
the way i learned it the standard form of an equation of an ellipse is x^2/a^2 + Y^2/b^2=1 Since x^2 is before y^2 in this problem, the ellipse is horizontal, meaning the major axis is going horizontally. One of the rules of ellipses states that the length of the major axis is 2a units, and the length of the minor axis is 2b units. therefore, a=9, and b=3 so the equation is x^2/9^2 + y^2/3^2 =1
Standard form of two equations. Hyperbolas?
This is an ellipse, but the process for putting it in standard form is the same: 25X^2 + 9Y^2 - 150X + 36Y + 36 = 0 25x^2 - 150x + 9y^2 + 36y = -36 25(x^2 - 6x) + 9(y^2 + 4y) = -36 25(x^2 - 6x + 9) + 9(y^2 + 4y + 4) = -36 + 225 + 36 25(x - 3)^2 + 9(y + 2)^2 = 225 [25(x - 3)^2]/225 + [9(y + 2)^2]/225 = 225/225 [(x - 3)^2]/9 + [(y + 2)^2]/25 = 1 The center is (3, -2) The minor axis is 6 units long and horizontal The major axis is 10 units long and vertical
Minor axis endpoints(+or-3,0),major axis length 18?
I am assuming that you are finding the equation for an ellipse. Therefore, you have minor axis which is horizontal. (Plot the points (3,0) and (-3,0) if you don't see it). Your major axis length is 18, therefore the major radius is 9. So, from the center (0,0), you would have 4 points. If you plot (+-3,0) and (0,+-9) you would have your outline of the ellipse. To find the equation you have to remember that the general form of an ellipse centered at the origin is x^2/(horizontal radius) + y^2/(vertical radius) = 1. From the points we found by interpreting the info in the problem the horizontal radius is 3 and the vertical radius is 9. Thus, the equation is x^2/9 + y^2/81 = 1. Answer is "D".