Find the value of the variables.?
Hi, 1) Since the radius of a regular hexagon equals the length of the side, then x = 7. The regular hexagon can be split into 6 equilateral triangles which can then be split into 30°-60°-90° triangles by drawing the apothem. When the hypotenuse (radius) is 7, then the 30° side is 3.5 and the apothem or 60° side, which is "y", is 3.5√3. x = 7 and y = 3.5√3 <==ANSWER 2) With a radius of 8, the regular hexagon can be split into 6 equilateral triangles which can then be split into 30°-60°-90° triangles by drawing the apothem. That means angle "x" is 30°. When the hypotenuse (radius) is 8, then the 30° side is 4 and the apothem, which is "p", is 4√3. x = 30° and p = 4√3 <==ANSWER I hope that helps!! :-)
Find the values of the variables for the rectangle. Then find the lengths of the sides.?
Remember that the opposite sides are congruent to each other! 6x + 3 = 9y 10x = 12y + 10 4(6x - 9y = -3) -3(10x - 12y = 10) By elimination method, you should get... 24x - 36y = -12 -30x + 36y = -30 -6x = -42 x = 7, so y = 5! Hence, the answer is D.x = 7, y = 5; side lengths: 45, 45 Good luck!
Help please? Find the values of the variables. Then find the lengths of the sides.?
19) Since the figure is a kite: AB = BC and AD = CD therefore: 13 = x + 2 x = 11 units x + 12 = y - 6 23 = y - 6 y = 29 units so: AB = 13 units BC = 13 units AD = 23 units CD = 23 units 23) Rhombus by definition has all 4 sides of equal length. therefore: 15 = 3y = 5x = (4x + 3) 3y = 15 y = 15/3 = 5 units 5x = 15 x = 15/5 = 3 units check: 4x + 3 = 15 4x = 12 x = 12/4 = 3 units All side lengths are 15 units. - .--
Perimeter of Rectangle, Find side length help?
if two of the sides of the rectangle are 2y+3 and 3y, the the four sides of the rectangle have a total perimeter of: 2(2y+3)+2(3y) = 4y+6+6y=10y+6 and we know that the perimeter also equals 106, so we have: 10y+6=106 10y=100 y=10 and the sides are: 3y=30 2y+2=23 check that two sides of 30 and two sides of 23 sum to a perimeter of 106
Is there a way to find the other two sides of a right triangle with the hypotenuse?
You can use these trigonometric formulas according to picture, if you know angles, to find out sides:-Then you can apply Pythagoras theorem also.Hypo^2= base^2 + side^2.Hope it helps !!
How to find the value of X in an isosceles trapezoid?
I'm going to give you a link, in case I lose you in the explanation: http://www.mathwarehouse.com/geometry/quadrilaterals/isosceles-trapezoid.php For an isosceles trapezoid, the angles on top are congruent (equal) and the angles on the bottom are congruent. Also, the length of the two sides are equal. Normally, an angle is labeled with three letters, like ⊾ABC so I'm not exactly sure which of your angles are which. If angles AB and BC are the two angles on top of the trapezoid, then angle AB = angle BC, or 2x-2=x+1. I can't work this out for certain because I don't know which two angles are congruent in your trapezoid. So hopefully, that link I gave you will help you understand.
Help with 8th grade Linear Equations in 2 variables homework?
40. if x = 2 then y can be anything, so go to any point where x is 2 and draw a vertical line intersecting that point 41. same thing except draw a horizontal line where the y coordinate is -3 42. plug any number in to p, preferably an easy one like 0, and solve for s: for example if P=0 then 0=4s and s =0 so the ordered pair would be (0, 0); or if P=4 then 4 =4s and s=1 and the ordered pair is (4, 1); or if P=8 then 8=4s and s=2 and the ordered pair is (8, 2), so your answer could be (0,0), (4, 1), and (8, 2) 43. Graph the points and draw a line passing through all three of them 44. s is the length of the side and you can't have a negative length; for example -5 inches doesn't exist
If you can see the given triangle, what will be the value of x?
I wasn't going to answer this question. But other answers are blatantly wrong, so I had to jump in.Also … I looked at this question blankly for three minutes (I should be able to solve it! My maths skills, oh God! Man, what the…) and then it finally dawned over me.Yeah, kill me.And so the answer is…..Wait, I'm not gonna tell you so easily. I take it that you are new to algebra. Well, dear lad! This is high time for you to learn something very interesting.Hence, I'll advice you too follow as I say.Take a clean sheet of paper.I mean it.Go.I am waiting.Promise, this will be worth it.Good! Thanks! Now make a huge diagram. (Like Donald Trump ’yuge!)Try to calculate all the angles that you can mark. (Easy angle sum property. Sum of all angles of a triangle is 180°. Nothing fantastic, here)Give all of them some variable name.Look at it.Realize it.Laugh at it.You'll see that there are only 4 angles that you don't know about. You gotta have the same number of variables as you have equations. If you look carefully (and if you try), there would be no more than three equations. (Comments are open, if you couldn't find the three).That means? Every freaking real number is a solution to those variables! Just put any value in [math]y[/math] and your [math]abracadabra[/math] variable will help you to find a solution for [math]x[/math]. (Hence the name) It's that simple. Yay!The only way this question had an unique solution was if at least one other angle was given to us. Others assumed the angle opposite to [math]x[/math] as [math]90°[/math], but you can't just assume things if you want to. And if any book uses the same assumption, throw it away. Because the answer for your unknown angle is:[math]x \in \R [/math][math]\text{(meaning x can be any real number)} [/math]