What happens ( products) pcl5 + h2so4 -> ?
Do you mean PCl5 ? And H2SO4? there are no chemicals with the forumulae you have given. Is the sulphuric acid pure or in solution? Please clarify the question as it makes a difference. As far as I'm aware, PCl5 doesn't react with 100% pure sulfuric acid.
PCl5(s) reacts with H2O(l) according to the equation: PCl5(s) + 4H2O(l) H3PO4(aq) + 5HCl(aq). What is ΔH˚?
PCl5(s) + 4H2O(l) H3PO4(aq) + 5HCl(aq) According to the balanced equation above, 1 mole of PCl5 reacts with 4 moles of H2O to produce 1 mole of H3PO4 and 5 moles of HCl. ∆Energy = Energy of products – Energy of reactants Energy = number of moles * Hf ˚ Energy of products = ∆Hf of H3PO4 + 5 * Hf of HCl = -1284.4 + 5 * -167.1 = -2119.9 kJ Energy of reactants = ∆Hf of PCl5 + 4 * Hf of H2O = -443.2 + 4 * -285.8 = -2058.6 kJ ∆Energy = -2119.9 – -2058.6 = -61.3 kJ When 1 mole of PCl5 reacts with 4 moles of H2O to produce 1 mole of H3PO4 and 5 moles of HCl, 61.3kJ of heat energy is released. ΔH˚ = -1 * the amount of heat energy released per mole of PCl5 ΔH˚ = -61.3 kJ/mole OR ΔH˚ = (ΔHf˚ of H3PO4 + 5 * ΔHf˚ of HCl) – (ΔHf˚ of PCl5 + 4 * ΔHf˚ of H2O) ΔH˚ = (-1284.4 + 5 * -167.1) – (-443.2 + 4 * -285.8) ΔH˚ = -2119.9 – -2058.6 = -61.3 kJ/mole
What kind of reaction is PCl5+H2O---H3PO4+HCl?
PCl5 + 4H2O --> H3PO4 + 5HCl This is a simple hydrolysis reaction, which is the addition of water to a molecule. The oxidation state of P (+5) does not change, so it is not a redox reaction.