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How Many Atoms Are In 6.7 Mol Zn

How many O atoms are in 3.0 moles of CO2?

1 molecule of CO2 = 1 C atom + 2 O atom.1 mole of CO2 = 6.02 x 10*23 CO2 moleculesSo, 1 mole of CO2 contains (2 x 6.02 x 10*23) O atomsSo, 3 moles of CO2 contains (3 x 2 x 6.02 x 10*23) O atoms = 3.61 x 10*24 O atoms.

How many atoms are contained in one mole of Ca(OH)2?

How many atoms are contained in a mole of CA (OH)2?None, unless you get rid of the unnecessary space, the miscapitalized A and the misformatted 2, this isn’t a valid molecule. Details matter, especially in chemical formulas. CA is something different from Ca.So I’ll assume you’re talking about Ca(OH)[math]_2[/math].In order to figure this out, you first count the atoms in 1 molecule.Ca = 1 atom of calciumWithin the brackets: 1 atom of oxygen, 1 atom of hydrogen. The 2 outside the brackets means you have to take those twice. So 2x oxygen and 2x hydrogen.1 calcium, 2 oxygen and 2 hydrogen makes for a total of 5 atoms in 1 molecule.There are 6.022*10[math]^{23}[/math] particles in a mole. So 6.022*10[math]^{23}[/math] * 5 = 3.011 * 10 [math]^{24}[/math] (approximately, I rounded the number) That is over 3 septillion (0r 3 million billion billion if you prefer)

How many atoms are in 6.7 mol Zn?

There are 6.02 x 10^23 (10 to the 23rd power) of anything in a mole

Therefore there are 6.7 x ( 6.02 x 10^23) = 40.3 x 10 ^ 23 , more correctly, 4.03 X 10 ^24 atoms Zn

How many atoms of zinc and chloride are in ZnCl2?

1 Zn
2 Cl

What is the molarity of sulphuric acid with density 1.09 g/mL containing 13% mass of sulphuric acid?

Molarity = moles of solute in 1 litre of solution .Density of solution = 1.09g/mlThis means 1.09 g of solution is present in 0.001 L .1.09 in 0.001Lso 1.09 * 1000 in 1LMass of solution in its 1 L = 1.09 * 1000 gmass of sulphuric acid = 13% of mass of solutionthus, mass of sulphuric acid present in 1L of solution =0.13*1.09*1000= 13*10.9gmoles of sulphuric acid in 1L of solution= mass/molar mass = 13*10.9/98 = 1.446So, molarity = 1.446 M

How many chloride ions are in 2.0 moles of CaCl2.Someone please help me.?

What I like to do with stoichiometry is set up a grid, with all the unit conversions on the top and bottom of the grid. That way, things are laid out for easy cancellation. For your problem, the grid will look like this:

2.0 moles CaCl2 | 2 moles Cl- ions | 6.02*10^23 Cl- ions
---------------------+----------------...
...........................| 1 mole CaCl2 | 1 mole Cl- ions

The first "region" of the grid has the original amount, the 2.0 moles of CaCl2. The second "region" has the first conversion, moles of CaCl2 to moles of Cl-. We know that there are two Cl's in every CaCl2. The third "region" is moles to molecules. That one's easy.

So, notice all the units cancel from the top of one "region" and the bottom of another, except the units we want at the end, number of Cl- ions. Cancelling out all the units, we're left with just numbers:

2.0 | 2 | 6.02*10^23 Cl- ions
----+---+-------------------------
......| 1 | 1

This becomes:

2.0 * 2 * 6.02*10^23 / 1 / 1 = 2.408*10^24 Cl- ions

If you can understand this, this makes stoichiometry SO much easier. I still use this well into college.

Compositions - Atom Percent?

The atomic wt. of Zinc = 65.38
atomic wt. of copper = 63.54
Let the no. of atoms of zinc and copper be N1 and N2, and
their wt. be W1 and W2.
N1/N2 = (W1/W2)(63.54/65.38) = 0.6479
N1 + N2 = 100
N1 = 39.317 , N2 = 60.683
So 39.317% of zinc atoms and 60.683% of copper atoms are present

How many atoms are there in 7 gram atoms of nitrogen?

In 1 mole of nitrogen, we have 6.022*10^23 atoms of it.Now, if we find out how many moles of nitogen are there in 7 gm, we can calculate atoms easily.So, atomic weight of nitrogen is 14 u..We have formula,mole = given weight/atomic massx= 7/14x=0.5 molesNow, 1 mole of nitrogen =6.022*10^23 atoms0.5 moles of nitrogen =6.022*10^23/1*0.5=> 3.011*10^23 atoms….

How many molecules are present in one gram of hydrogen? How?

I assume that you are talking about hydrogen gas(H2) as you are talking about molecules.Hydrogen gas(H2) has a molar mass of 2 g. Molar mass of a substance is defined as the mass of 1 mole of that substance. And by 1 mole it is meant a collection of 6.022*10^23 particles of that substance.So number of moles of H2 are 0.5 in this case. And thus it means there are (6.022*10^23)*0.5 particles( here they are molecules) in 1g of H2.

Chemistry Homework Help?

These are the last questions i need to finish homework please help, step by step would be appreciated thanks for all the help.

1)2.4 mol Zn and 6.7 mol HCl react according
to the equation
Zn + 2 HCl --> ZnCl2 + H2 :
If the limiting reactant is Zn, determine
the amount of excess reactant that remains.
Answer in units of mol.

2)1.7 mol HCl and 3.2 mol NaOH react accord-
ing to the equation
HCl + NaOH ----> NaCl + H2O:
If the limiting reactant is HCl, calculate the
amount of NaCl formed. Answer in units of
mol.

Calculate the amount of H2O formed. Answer
in units of mol.

3)2.1 mol Zn and 6.7 mol HCl react according
to the equation
Zn + 2 HCl ----> ZnCl2 + H2 :
If the limiting reactant is Zn, calculate the
amount of ZnCl2 formed. Answer in units of
mol.

4)Calculate the amount of H2 formed. Answer
in units of mol.

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