I need to know the copper weight by pound per foot of the types of finished copper wire noted in the details:?
14-2 NM W/G Romex 12-2 NM W/G Romex 14-3 NM W/G Romex 10-2 NM W/G Romex 8-2 NM W/G Romex 6-2 NM W/G Romex 10-3 NM W/G Romex 8-3 NM W/G Romex 6-3 NM W/G Romex #4 Bare Copper Solid I am trying to obtain conversion factors so I can calculate how much actual copper is being purchased when a certain footage of finished wire is purchased. Thus, I need to get just the copper weight excluding plastic sheathing or any other items added in the manufacturing process. Thanks for your help.
How much does 500 feet of 8 gauge copper wire weigh?
Its cross-sectional area is 8.37 mm^2, so its volume per meter of length is (8.37 x 10^(-6) m^2)*(1 m) = 8.37 x 10^(-6) m^3. The 500 feet is 152.4 meters, so the total volume is 0.0012756 m^3. The density of copper is about 8920 kg/m^3, so the total mass should be 11.4 kg (about 25 pounds).
Weight of 4/0 copper wire per foot?
Size :(AWG/ kc mil) = 4/0 Stranding (No. x Mils) = Weight = 199 Weight (lbs/k ft) Weight = 0.199 Weight (lbs/foot)
How much does 100 meters of 0.5 mm diameter copper wire weigh?
we need volume and density to calculate mas of a substance. Density of copper wire is constant and is equal to 8.96 g/cm2volume of a cylinder (since a wire is considered as a cylinder)= Pi*R*R*LMass = density * volumeMass= 8.96g/cm2* Pi*0.05cm/2*0.05cm/2*100*100cmMas= 896*2.5*0.05/2 gMass= 896*2.5*0.025Mass= 56 grambut your question is weight which is dependent on gravityWeight = Mass*Gravity lets take gravity = 10Weight = 56*1o=560 NW=56o
A copper wire has a diameter of 0.5 mm and a specific resistance of 1.6× pe 10 power minus 8 ohms meters. What will the length of this wire be to make its resistance 10 ohms?
R=10 Ωρ=1.6 x 10^(-8) Ω⋅md=0.05 mm =0.05 x 10^(-3) m =5 x 10^(-5)mSo r = 2.5 x 10^(-5) ml=? mnow using, R=ρl/A,or R=ρl/π(r^2)10= {[1.6 x 10^(-8)] x l}/ π x [(2.5 x 10^(-5)) ^2]10= {[1.6 x 10^(-8)] x l}/[2 x 10^(-9)]now find the value of l
I have 3 rockford fosgate 12" P3 subwoofers how can i wire them to a monoblock audiobahn a1600v amp??
THESE ARE THE DETAILS OF THE SPEAKERS AND THE AMP p.s whats better 2 ohm speakers or 4 ohm speakers ?? i want more bass! Description Value of the speakers Size 12" Impedance 2-Ohm x 2 Power Handling 500 RMS 1000 Peak Sensitivity 87 dB Motor Size 102 oz. double stacked Voice Coil Diameter 2.5" aluminum Speaker Connector Dual 8 AWG compression Mounting Depth 6.375" Rec. Sealed Enclosure 0.75 cu. ft. 21.24 liters Rec. Vented Enclosure 1.75 cu. ft. 49.56 liters Tuning Frequency (vented) 37 Hz Shipping Weight 25.2 Lbs. (11.4 Kg.) Audiobahn A16000V A16000V Audiobahn Mono Block Amplifier Double Sided Glass Epoxy Circuit Board High Gloss Chrome Plated Finish Variable High/Low Pass Crossover Variable Low Pass Crossover: 50 - 120 Hz Variable Subsonic Filter: 20 - 50 Hz Bass Boost 0- +18dB Phase Shift Switch: 0 - 180 degrees 2 Ohm Mono Stable MOSFET Power Supply 1x 1600W RMS @ 2 Ohms 1x 800W RMS @ 4 Ohms Fuse Ratings: 40A x 2
What size wire is needed for a 50 amp breaker at a run of 145 feet?
We need to know what the intended load is. Different devices will have different requirements, that NEC and Local Codes notwithstanding, will help you determine the appropriate size.First, We need to know if the wire will be handling a high steady current like an HVAC unit, incandescent or HID lighting, spa / pool heater. For these types of items that are directly connected using a dual pole breaker to derive 220 VAC , one might be advised to “up-rate” the NEUTRAL wire to the next size larger than the LINE wires, in order to avoid any overheating of the NEUTRAL during heavy, sustained use.If this is a Water Heater, my charts say a #6 is acceptable, but this particular source is a few years old and there have been updates to the NEC.If this is supplying a SUB-PANEL where BRANCH CIRCUITS will be controlled, the “up-rated NEUTRAL” can help reduce deleterious effects of modern switching power supplies now prevalent in modern digital electronics called EDDY CURRENTS.This method will generally require the use of individual conductors contained with conduit, either PVC or metal, depending on the load(s)location and the number of other wires in the conduit will determine it’s required size to prevent overheating of the conductors.Again, NEC and local codes will determine this size.For these types of uses a #4 COPPER wire will generally be sufficient. A #2 would be the size for uprating the NEUTRAL , or for a higher degree of confidence overall in all conductor’s ability to allow a sustained high demand use profile.Aluminum (AL) wire may be available, however AL wire doesn’t handle as much current per square inch and will need to be increased in size for the same rating as copper. Weight of wire and end cost are the reasons for AL wire to be considered. AL wire also requires specialized installation methods (anti-oxidation paste / torquing) as well as regular, periodic maintenance at the breaker and load connections, as it tends to expand and contract more than copper, especially with high current use. This will loosen the connecting screws and can cause a dangerous overheating condition. There’s that potential for catastrophic failure again.I hope this information will be useful.
How can I calculate the weight of a mild steel bar from its length?
there are two thing you should know to calculate the weight of any bar is,Unit weight of barDiameter of barso, lets have a look How can we derive ‘UNIT WEIGHT OF STEEL’still not understood ???Derivation of UNIT WEIGHT OF STEEL FORMULA, Calculation of WEIGHT OF STEEL for varies diameter.(watch the video in the given link for better understanding)Now you you know the “Unit Weight of Steel Bar”Let’s say dia of bar is 20 mmW= (20^2)/162.2 = 2.466 kg/mSo, we need 2.466 kg of steel for 1 m length.Suppose length of bar = 6 mWeight (W) = 2.466 x 6 = 14.796 kgSubscribe to We Civil Engineers To learn a lot more stuff’s Related to CIVIL ENGINEERINGHope it helpsThank you _^_