How do you calculate p-value by hand?
I have the BA II Plus, which was one of the allowable calculators for the CFA exams. I wish it allowed me to do the P-Value, but it doesn't have that function. P-Value calculations usually will give you a table to reference off of your T-score, with a different column for single tailed and double tailed. Alas, your trusty BA II Plus does IRRs, Cash Flows and NPVs beautifully (second row of buttons), bonds (third row of buttons), algebraic (e.g. cosine, sine etc) in the fourth and fifth rows, factorials along the far right hand column and the rest being other stuff that is non- P-Score, Z, T or any other statistical stuff.
How do I calculate the z-score from the p-value and vice versa without using a chart?
This question has a very interesting answer. Asking how to calculate the p-value from the z-score and vice versa is equivalent to asking the question “what is integral of the standard normal distribution from negative infinity to z?” and “what value of z will yield an area under the standard normal distribution from negative infinity to z that is equal to my p-value?”Unfortunately, no one knows the answer to this question for non-trivial z-scores and p-values. The integral of the normal distribution is called the error function, and it is non-elementary:Elementary functions can be written as combinations of functions that you would have encountered in high school (exponentials, trigonometric functions, powers of x, etc). However, it can be proven that the normal distribution’s integral cannot be exactly expressed as a combination of any of these functions.No one can give you an exact p-value from a z-score or an exact z-score from a p-value. However, people have developed incredibly accurate approximations due to the importance of the normal distribution. Those approximations are what is recorded in your table. Besides a table, you’ll want to use a calculator, because I doubt you would want to do any of the approximations by hand.
Calculate z and p value?
An article predicts that "spit," spam that is delivered via internet phone lines and cell phones, will be a growing problem as more people turn to web-based phone services. In a 2004 poll of 5500 cell phone users conducted by the Yankee Group, 35% indicated that they had received commercial messages and ads on their cell phones. Is there sufficient evidence that the proportion of cell phone users who have received commercial messages or ads in 2004 was greater than the proportion of 0.13 reported for the previous year? (For z give the answer to two decimal places. For P give the answer to four decimal places.) z = P = There is evidence to suggest that the proportion cell phone users who have received commercial messages or ads in 2004 is greater than the proportion of 0.13 reported for the previous year. i calculated the p value to be 0 but i cant get the z value. please help
For stats, how can you find Z scores on the TI-83 calculator?
Indeed there is a way to find z-scores using the TI-83 calculator. Let's say you want to find the z-score of percentile p, 0 ≤ p ≤ 1. You would do the following: 1: hit 2nd + DISTR (same as the VARS button) 2: doing so pulls up a menu. Choose the third item on that menu: invNorm( 3: Once you press enter over the third item (or press 3), you will see invNorm pasted onto the screen. Enter the value of p (your percentile), then ")", then enter. 4: the number that comes out is the z-score which produces that percentile some values to try: invNorm(0) = -10^99 (as low as the calculator goes) invNorm(0.025) = -1.96 invNorm(0.5) = 0 invNorm(0.975) = 1.96 invNorm(1) = 10^99 (as high as the calculator goes) Note: z-scores are available for the normal distribution, but not for student-t distributions.
How to calculate the p-value and z-score for the following problem?
The average height of 2-year-old children is 34 inches with a population standard deviation of σ = 1.75. A random sample of 35 2-year-olds in a large daycare franchise is collected and found to be 29.00 inches. Researchers are suspicious that the children at the daycares are not growing as quickly as they should be. (a) Calculate the test statistic for the problem. (Round your answer to two decimal places.) z = (b) Calculate the P-value. (Use a table or technology. Round your answer to four decimal places.)
Z-score and P-value help?
A basketball player took 35 free throws during the season. Her sequence of hits (H) and misses (M) is shown. At α = .01. H M M H H M H M M H H H H H M M H H M M H M H H H M H H H H M M M H H Calculate the expected number of runs. Calculate the z score and the p-value.
Find the value of the z-score?
Always start with a diagram of the situation A) P (Z > a) = 0.95 So the z score is to the left of the mean so need area 0.95 - 0.5 = 0.45 The z-score that corresponds to an area of 0.4495 to the left of the mean is -1.64 The z-score that corresponds to an area of 0.4505 to the left of the mean is -1.65 So the z-score that corresponds to an area of 0.45 to the left of the mean is -1.645 So a = 1.645 B) P (Z < b) = 0.95 this one is pretty much the same but b lies to the right of the mean and the area to the right of the mean is 0.45 so b = 1.645 For the third one you just have to find the z-score corresponding to an area of 0.5 - 0.42 = 0.08 to the right of the mean
How do you calculate p for a two sided t-test?
If you're limited to a t table, go to the row that corresponds to the number of degrees of freedom you have. Scan across that row until you find two t values that bracket your number. Then interpolate for your final answer. If you have access to Excel, you can use the TDIST function. For example, suppose your t value is 1.4 and you have 20 degrees of freedom. Then the p value for a 2-tailed test is TDIST(1.4,20,2) = 0.176835065