3/8 - 1/4x = 1/2x - 3/4 solve for x?
Assuming you mean: 3/8 - (1/4)x = (1/2)x - 3/4 3/8 + 3/4 = (1/2)x + (1/4)x Common Denominator 3/8 + 6/8 = (2/4)x + (1/4)x 9/8 = (3/4)x Multiply both sides by 4/3 3/2 = x Check 3/8 - (1/4)(3/2) = (1/2)(3/2) - 3/4 3/8 - (3/8) = (3/4) - 3/4 0 = 0 Answer Checks.
How do you solve 3 + x = -8?
x = -8–3x = - 11
How do you solve 2x + 3 = 8?
To solve this equation, you need to use inverse operations in the reverse order of operations.Phew, that was a lot of big words. Let me explain.Normally, when trying to simplify expressions, you follow the order of operations:ParenthesesExponentsMultiplication and DivisionAddition and SubtractionIn this scenario, where we are trying to find the value of a variable, we need to follow the order of operations in reverse:Addition and SubtractionMultiplication and DivisionExponentsParenthesesNot only this, but we also need to use inverse operations:To reverse addition, use subtraction, and vice versa.To reverse multiplication, use division, and vice versa.To find the value of [math]x[/math] in [math]2x+3=8[/math], we first need to subtract [math]3[/math] from both sides to cancel out the [math]+3[/math]. This leaves us with [math]2x=5[/math]. Now we need to cancel out the multiplication using division. Divide both sides by [math]2[/math].You are left with [math]x=2.5[/math]. This is your answer.
Solve x/2x+2 = -2x/4x+4 + 2x-3/x+1?
assuming x/(2x+2) = -2x/(4x+4) + (2x-3)/(x+1) then: x=-2x(2x+2)/(4x+4) + (2x-3)(2x+2)/(x+1) x=-2x*2(x+1)/4(x+1) + (2x-3)*2(x+1)/(x+1) x=-4x/4+2*(2x-3) x=-x+4x-6=3x-6 x-3x=-6 -2x=-6 x=3
How to solve (2^2x-3)-5(2^x)+32?
Your presentation of the question is wrong. It should have been as follows.-- How to solve [ 2 ² ͯ⁻³ - 5 ( 2 ͯ) + 32 = 0 ∎ you didnt type = 0 here. Solution -- => [ (2 ² ͯ)/ 2³ - 5 ( 2 ͯ) + 32 = 0 [ ( 2 ͯ)² / 8 ] - 5 ( 2 ͯ) + 32 = 0 Put 2 ͯ = A, then our equation becomes -- => (A² / 8) - 5 A + 32 = 0 Multiply the equation by 8 -- => A² - 40 A + 256 = 0 => A² - 32 A - 8 A + 256 = 0 => A ( A - 32 ) - 8 ( A - 32 ) = 0 => ( A - 32 ) ( A - 8 ) = 0 => A = 32 OR A = 8 --------------------------------------... => when A = 32 --------------------------------------... => 2 ͯ = 32 ..... => 2 ͯ = 2^5......... => x = 5 ......... Answer --------------------------------------... When A = 8 --------------------------------------... => 2 ͯ = 8 = 2^3 => x = 3 ....................... Answer Answer --------------------------------------... ANSWER => x = 5 and 3 --------------------------------------... .........................................
How do you solve 3x + 3 = 8?
3x + 3 = 8First of all, you’ll shift 3 to the other side of the equation due to which the sign of 3 will change so it becomes:3x = 8 - 33x = 5Now to find x you can shift the 3 on the other side but remember that since it’s multiplying on the left side of equation, you will divide when you shift it to the right side so it now becomes:x = 5/3
How do you solve [math]3(x-2) =x-8[/math]?
3(x-2)=x-8.Let’s think about what 3(x-2) means. It means (x-2) + (x-2) + (x-2) which is 3x-6. Write 3(x-2) as 3x-63x-6 = x-8. Subtract x from the expression 3x-6 and subtract x from x-8. If you subtract the same number from the expression on the left and the expression on the right you will be able to write an equivalent expression that will be true if there is a value for x that will make 3(x-2)=x-8 true.3x -6 -x = x-8-x. Doing the subtraction for both expersions you can write2x -6 = -8. Add 6 to both both the expression 2x-6 and -8 because if you have a true equivalent relationship the you can any the same number to both sides and obtain a new true equivalent relationship.2x-6+6=-8+6 Doing the addition to both2x=-2. Divide the expression 2x and the expression -2 with 2 because if you divide both sides of an equivalent relationship with a number other than zero you wil find a new relationship that will be true if the original equation 3(x=2) = x-8 had a solutionX=-1The answer is x is -1 if the original equation had a solution. We need to see if -1 will make a correct statement for the original equation.3(x-2)=x-83(-1–2)= -1–83(-3) = -9-9 = -9So yes all the work is correct because the original equation of 3(x-2)=x-8 does have the solution x=-1
How do you solve the equation 3(x-1) =8?
3(x-1)=8By opening the brackets we have,3x-3=8Adding 3 on both the sides3x-3+3=8+33x=11Dividing 3 on both the sides3x/3=11/3x=11/3VerificationBy putting the value of x in the equation we have,3(11/3-1)=8By opening the brackets we have33/3-3=811-3=8 (since 33/3=11)8=8Thus the value of x =11/3THANKYOU
How do I solve the linear equation (-8/3) x = (7/2)?
Given (-8/3) x = (7/2)x = (7/2)/(-8/3)x = 7/2*(-3/8)x = -21/16Math Homework Help