In desperate need of physics help!?
An injured monkey sits perched on a tree branch 9.0 m above the ground, while a wildlife veterinarian is kneeling down in the bushes 88.0 m away attempting to subdue the monkey with a tranquilizer gun. The vet knows that the moment the gun fires the monkey will be frightened and fall down from the branch. What angle up from the ground must the veterinarian aim the gun so that the tranquilizer dart will hit the falling monkey? part b) Given the angle above, what is minimum speed the tranquilizer dart must leave the gun to still hit the monkey?
Physics help?!?! Desperate?!?
A block is hung by a string from the inside roof of a van. When the van goes straight ahead at a speed of 27 m/s, the block hangs vertically down. But when the van maintains this same speed around an unbanked curve (radius = 135 m), the block swings toward the outside of the curve. Then the string makes an angle θ with the vertical. Find θ.
DESPERATE NEED OF HELP IN physics!?
I will calculate the values required to plot the graph. Plotting part you have to do. (A) The initial velocity of the car = 0 m/s Acceleration = 3 m/s² Velocity after 1 sec = v = u + at = 0 + 3 x 1 = 3 m/s ........................2 sec....................= 0 + 3 x 2 = 6 m/s ........................3 sec ...................= 0 + 3 x 3 = 9 m/s ........................4 sec ...................= 0 + 3 x 4 = 12 m/s ........................5 sec ...................= 0 + 3 x 5 = 15 m/s To plot , take 'time' on the 'X' axis & 'Vel.' on the 'Y' axis. (B) The distance travelled at the above intervals, at the above rate, S = ut + ½ a t² Distance after 1 sec = ut + ½ a t² = 0x1 +½x3x1² = 1.5 m ..........................2 sec = ..................= 0x2 + ½x3x2² = 6.0 m ..........................3 sec = ..................= 0x3 + ½x3x3² = 13.5 m ..........................4 sec = ..................= 0x4 + ½x3x4² = 24.0 m ..........................5 sec = ..................= 0x5 + ½x3x5² = 37.5 m To plot, take 'time' on the 'X' axis & 'Dist.' on the 'Y' axis.
Desperate need of physics help!!?
What a joke. You desperately need help with TEN physics problems ( have you checked how this forum works before you posted?) I desperately need a new Mercedes on my driveway. Can anybody help???
In desperate need of help! Physics Homework!?
A peregrine falcon dives at a pigeon. The falcon starts downward from rest with the free-fall acceleration. If the pigeon is 76.0 m below the initial position of the falcon, how long does the falcon take to reach the pigeon? Assume that the pigeon remains at rest. I need help with this from my physics homework. If you could explain how you did it (or show the work instead of just giving an answer) that would be very helpful, since I have no idea how to do it since I don't have a very good teacher. Thank you!
Physics help...im desperate!!!?
energy works under condition. " in system that does not interact with the surrounding..." energy stays the same. in the case of nuclear reactor, ..it is pressurized. read along the sites it might give you some points. http://www.taftan.com/thermodynamics/FIRST.HTM http://www.phy6.org/stargaze/Senergy.htm http://americanhistory.si.edu/subs/operating/propulsion/reactor/index.html
In desperate need of help in modern physics?
This is a 3 part question each of the parts are very different Part A : A beam of 8.0-MeV α particles scatters from a thin gold foil. What is the ratio of the number of α particles scattered to angles greater than 1 degree to the number scattered to angles greater than 2 degrees. B: A hydrogen atom in an excited state emits a photon of wavelength 95 nm. What are the initial and final states of the hydrogen atom? C: Electromagnetic radiation of wavelength 100 nm is incident upon the ground-state hydrogen atom at rest. What is the highest state to which hydrogen can be excited?
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1-Does the width of the "curve" as measured by the estimated standard deviation depend on the number of times the measurement is repeated? 2-The simulated events were generated by a Monte Carlo technique, named after the casino. This algorithm does an excellent job of simulating what real data would look like. The true mean and standard deviation used in the Monte Carlo calculation are integers. What are their values? y 3-For a given number of repeated measurements, the values of the estimated standard deviation were unlikely to ever come out exactly equal to your answer to Question 2, but instead for a number of trials exhibit a spread of values. Qualitatively, how does the width of this spread of values depend on the number of repeated measurements? 4-Can you find any relationship between the two numbers that were your answer to Question 2 above? A correct answer to this question matches the relationship between the mean and standard deviation for real radioactive decays. 5-As of January 18, 2001 hockey player Mats Sundin of the Toronto Maple Leafs had scored 16 goals in the season. Some were "lucky" goals and at other times he had excellent scoring chances that failed to find the net. From your answer to Question 4, what is a reasonable guess of the statistical uncertainty in the number of goals he has scored. The values according to the no. of measurements are as below No. Estimated mean Estimated Std.Deviation 50 48.1176 6.90694 100 48.2475 6.o3391 500 48.7226 6.85834 1000 48.8292 6.8705 5000 49.1422 6.9297 1-It does. 2-T.he true mean and standard deviation according to this technique is 48 and 6 respectively 3-The standard deviations vary erratically.It is highest with 50 and lowest in 1000.Again it rises at 500 to almost the 50 level.It crashed in 1000 and recovers marginally in 5000. 4- The estimated mean is eight times that of estimated std.deviation. 5-He was indeed very unlucky. He could have attained hits in the same proportion. Bad luck. It is not necessary to consult any other authority. It is just simple calculation and yourself could have done it had you tried. I hope I have not messed up things. I have no mathematical or statistical background.
In desperate need of help for physics... PLEASE help!!?
Mass of the fullback, m1=89 kg Speed of the fullback, v1=8.2m/s Mass of the tackle, m2=129 kg Speed of the tackle, v2=? (a) Fullback's momentum before the collision=m1*v1 =(89*8.2) =729.8 kg m/s. (b) Change in fullback's momentum = (Final momentum) - (Initial momentum) =m1*0 - m1*v1 =(0-729.8)kg m/s = -729.8 kg m/s (c) From the Law of Conservation of Momentum, (momentum of the system before the collision)=(momentum of the system after the collision). That is, m1*v1 + m2*v2 = m1*0 + m2*0 i.e., 729.8 + 129*v2 =0+0 i.e., 129*v2=-729.8 i.e., v2=(-729.8 / 129) m/s Change in tackle's momentum = (Tackle's final momentum) - (Tackle's initial momentum) =m2*0 - m2*v2 =0 - 129*(-729.8 / 129) 729.8 kg m/s (d) Tackle's original momentum = m2*v2 =129*(-729.8 / 129) = -729.8 kg m/s (e) Tackle's original (initial) speed = v2 = (-729.8 / 129) m/s = 5.657 m/s Wishing you all the best in this wonderful Science of Physics. Best of luck !
In desperate need of help with this physics problem and it's due in just a few hours! eeek!?
For this hydrostatic pressure problem, the surface area of the lake (i.e. 8 km^2) has no bearing since pressure is only dependent on the depth of water. The formula for the static pressure is as follows: Equation 1: Hydrostatic pressure = (density of medium)(gravitational acceleration)(depth) In this case, density of water = 1,000 kg/m^3 gravitational acceleration = 9.8 m/s^2 depth = 14.0 m Gauge pressure = 137,200 Pa Note that Pa = N/m^2 and N = kg m/s^2 As for the second question, Equation 2: Absolute pressure = gauge pressure + atmospheric pressure where atmospheric pressure at sea level is approx. 101,325 Pa Using Equation 1, the static pressure 1.0 m below the surface is calculated as 9,800 Pa. Therefore, Absolute pressure = 101,325 + 9,800 = 111,125 Pa