I am really desperate for help on this question!?
you have these two possible reactions... (swapping the anions and cations) .. Mg(NO3)2 + 2 AgNO3 ---> Mg(NO3)2 + 2 AgNO3.... i.e.. NO REACTION .. MgCl2 + 2 AgNO3 ---> Mg(NO3)2 + 2 AgCl(s) the key to this is... .. Mg(NO3)2 .. AgNO3 .. MgCl2 are all soluble in water while.. ... AgCl is NOT water soluble and precipitates out as a solid ******** next... converting the AgCl(s) to mass MgCl2 from the coefficients of the balanced equation.. (and using dimensional analysis) 0.641g AgCl x (1 mol AgCl / 143.32g AgCl) x (1 mol MgCl2 / 2 mol AgCl) x (95.21g MgCl2 / mol MgCl2) = 0.213g MgCl2 and then... .. mass % MgCl2 = 0.213g MgCl2 / 1.50g mix x 100% = 14.2% and finally... .. 0.213g MgCl2 x (1 mol MgCl2 / 95.21g MgCl2) x (2 mol AgNO3 / 1 mol MgCl2) x (1 L AgNO3 / 0.500 mol AgNO3) x (1000mL / 1L) = 8.95mL ******* ******* how much of that did you follow? ******* and yes.. you could use Steve's method and convert the mass AgCl to moles AgCl to moles AgNO3 to L AgNO3. both have the same number of unit factors. His is probably better since the 0.213g MgCl2 is a calculated value based on the measured value of AgCl(s). It's better for precision and errors to start with the 0.641g AgCl like he did.
I'm really desperate for sex, please help?
I been dating this girl for 10 years, and for the past year we haven't had sex, she always promises she will, but always has something to do. I am pretty dedicated to her, but I am becoming real desperate. I watch porn and I am starting to crave most of my female friends. I am to the part where I get anxiety of how bad I want it. I don't know what to do? Am I an ***?
Help, I'm really desperate for sex?
I'm a 19 year old guy and I've never been physically intimate at all with a girl. Lately my body has been craving sex like you wouldn't believe it, and masturbation just doesn't do the job anymore I feel like I could stick my penis in anything. I just want to have sex so badly. But unfortunately, that's not an option for me. I don't go to parties or anything, I spend most of my time alone, and girls never even pay attention to me. I just can't stand the fact that there are so many girls willing to slut themselves out these days, yet I can't have sex with just ONE of them! What can I do?
Really desperate!plz help?
my neice was born with a large hernia but she was told that it was fine she is now 2/3 and is really struggling to go to the toilet. she is really fussy when eating and it is a struggle trying to get fibre/ bran into her diet. she has been to the doctors about 4/5 times and she has been giving perserries and 3 types of medcines but nothing seems to be working. she is having very bad stomach pains and is really really constipated. she sits on the chair out the way of people and holds on to the arms and strains like mad. she done this today and it hurt that much she started crying! please help i need answers!!
Please help me with physics. really desperate?
To operate a given flash lamp requires a charge of 27 µC. What capacitance is needed to store this much charge in a capacitor with a potential difference between its plates of 3.2 V?
Really desperate!! Chemistry Help!!!?
Can some one tell how or show how to do this, instead of giving me the answer? 1) There are ____ mol of carbon atoms of 4 mol of (C2H6SO) 2) There are ____ Sulfur atoms in 25 molecules ofC4H4S2 3) 2.25g sample of magnesium nitrate, Mg(No3)2 contains ____ mol of this compound
Let's say that this is a really desperate cry for help. Can anyone give advice to someone who isn't sure if they have real mental problem or not, but cannot function properly in life for years now?
As one who has suffered with clinical depression for a long time, there is help. Look in the special sections of your phone book, there are usually community services available there. I know its hard to do, but you asked for help here, now make a phone call to someone who is right there in your area and can help you.
HOW DO I GROW TALLER? HELP PLEASE! I'm really desperate!?
Now that I think about it, I did stop drinking milk when I started high school because I'm always in the rush in the morning. I don't get too sleep that much anymore because of stupid AP testing -___- But I also noticed that the summer after my growth spurt that I started swimming and nothing really happened after that. I gained a good amount of muscle. However, I also heard that once you gain a good amount of muscle, that's when you begin to grow even slower or stop growing at all. And I just do some push ups and other stuff at home. Nothing big. Btw, short girls are sooo cute. Love them! But most of the go for the taller guys so they can feel protected. I know this because I'm good friends with a couple of them. Most girls want taller guys because of the protection factor.
I am desperate, and really need HELP with this question?
First of all, I notice that all the scores are 2-digit numbers, so it's meaningless to give the mean value with 5 digits, and standard deviation with 8 digits. Justin has a score of 82, this is 10.7 above the average. Z-score = 10.7 / 9.3 = 1.15. On a standard normal curve, a z-score of 1.15 is indeed at the 87.5% point. That means that 87.5% of the people would score lower, and 12.5% would score higher, IF THE CLASS WAS VERY LARGE AND IF THE SCORES WERE DISTRIBUTED NORMALLY. But ... this class is not very large (would need about 1000 for that), and the scores are NOT distributed normally. There were 36 people who scored lower than Justin; that is 90%. Justin is in the 90% - 92.5% percentile group, the midpoint of this is 91.2%. That is, 87.5% of the class "should" have a lower score, but actually 90% had a lower score. This is because this class is a bit weaker than the mean and standard deviation would suggest. (Or, you could say, one or two people are dragging the average down.)
Chemistry half life problem!!??? Really desperate in help i have a quiz tomorrow :'(((((((?
5.80 g / 46.4 g = 0.125 (this is the decimal amount remaining) 0.125 is evocative of thee half-lives, as in: 1 ---> 1/2 ---> 1/4 ---> 1/8 (1/8 = 0.125) 4.80 yr/half-life times 3 half-lives = 14.4 yr Here is a more general way to solve this type of problem: (1/2)^n = 0.125 n log 0.5 = log 0.125 n = 3 More half-life problems: http://www.chemteam.info/Radioactivity/R... Look under problem sets and videos