What is the sum of 10 divided by a number and that number divided by 20?
Let's call "that number" or "a number" x. Then, 10 / x is "10 divided by a number." And, x / 20 is "that number divided by 20." I'm doing a little bit of interpretation here, because "that number" is unclear...does that mean x or does "that number" mean the 10 / x in the previous step. I'm going to assume the former: "that number" simply means x. The sum of these numbers, then, is... (10 / x) + (x / 20) = (20 / 20)(10 / x) + (x / x)(x / 20) = (200 / 20x) + (x^2 / 20x) = (x^2 + 200) / (20x)
How do I find a number which when divided by 2, 3, 4, 5, 6, 7, 8, 9, 10 individually gives a remainder of 1 and when divided by 11 gives a remainder 0?
you will have to find out the LCM of all the number given ie from 2 to 10. the LCM will be divisible by all the numbers 2 to 10. Because you will have to get a reminder of 1 add 1 to the LCM and check whether that number is divisible by 11, if not multiply the LCM by 2 and add 1 and check if it is divisible by 11, if not continue like this till LCM*n + 1 is divisible by 11The LCM of 2 to 10 is 2520 Add 1 to 2520 which will be 2521. 2521 is not divisible by 11Continuing like this 2520*2 + 1 = 5041 not divisible by 112520*3 + 1 = 7561 not divisible2520 * 4 = 5040 + 1 = 5041 not divisible2520 * 5 = 12600 + 1 = 12601 not divisible2520*6 = 15120 + 1 = 15121 not divisible2520 * 7 = 17640 + 1 = 17641 not divisible2520 * 8 = 20160 + 1 = 25161 not divisible2520 * 9 = 22680 + 1 = 22681 not divisible2520 * 10 - 25200 + 1 = 25201 Divisible by 11I have explained a similar question in a video
A two-digit number is divided by another 2-digit number and its quotient is 5.375. What is the sum of these numbers?
If the quotient is 5.375, it means the quotient is 5 and the remainder is 0.375 times the divisor.In decimal form the answer is 5.375 or 5 and 375/1000or 5 and 3/8 sothe irregular fraction is 43/8.So the number is (43*2)/(8*2) = 86/16.The two numbers are 86 and 16 and their sum is 102. Answer
Find the greatest five digit number which when divided by 9,8,7 leaves the remainders 6,5,4 respectively?
Since all the divisors and remainders have same difference [math]3[/math] ,any multiple of [math]L.C.M[/math] less [math]3[/math] will serve the purpose.[math]L.C.M.=9*8*7=504 [/math][math]\dfrac {10^6}{504}=198.4127[/math]Taking only the integral part [math]198*504[/math] gives [math]99792[/math] subtract [math]3[/math] to get [math]\boxed{ 99789 }[/math] as the required number.
A number when successively divided by 7 and 8 leaves the remainders 3 and 5 respectively. What is the remainder when the same number is divided by 56?
Successive Divison:Here we divide a number by the first divisor, then the quotient by the second divisor, then the 2nd quotient by 3rd divisor and so on.In this case as number was successively divided by 7 and 8 leaving remainders 3 & 5 respectively.If a number leaves remainder 3 when divided by 7, then it can be expressed as (7m+3). Now 'm' is the quotient after first division.When ‘m' is divided by 8, it leaves remainder 5. So, ‘m' can be expressed as (8k+5)Thus my number is: [7*(8k+5) + 3] = 56k + 38Now when the number is divided by 56, the remainder will be:R[(56k+38)/56]= R[(56k)/56] + R[38/56]= 0 + 38= 38 (Answer)