How do I calculate the area of a pipe?
Depends what area you’re referring to…Surface Area of the outside of the pipe would be:A = L * W (Area = Length * Width)L = length of pipeW = circumference of pipe (Likely you are looking for the surface area of the outside of the pipe, so you would use the circumference at the outside diameter.)so,W = 2 π rso,A = L * 2 * π * r (Surface Area = Lenght of Pipe * 2 * 3.1415… * radius of pipe)orA = L * π * D (Surface Area = Lenght of Pipe * 3.1415… * diameter of pipe)***If your looking for the surface area of the inside of the pipe, use the circumference at the inside radius or diameter***You could also be looking for the cross-sectional surface area, which is a bit easier.Area of a circle: A = πr^2Surface area of the cross-section of a pipe:A = π * r * r (3.1415… * radius of pipe * radius of pipe)
How do we calculate inch dia of pipe?
Inch -Dia is for evaluting welders work its general term to understand welders .Some welders getting paid on of joints x pipe diameter in inch per day (DIA-INCH)So its easier for supervisor to1.Load welders no if joints on site & production2.Calculate cost of welder per day’s3.Its useful for Estimation Engineer to quote rates for job4.Its useful for Planning Engineer to plan job completion target5.For supervisor to put correct number of welders to complete given number of joint for that inch Diameter pipe ,in planned time frame.For e.g.Welder welds 2″ pipe of 10 joints.2″ pipe one joint rate is 10$So his payment = 2″ pipe welding rate x no of joint (irrespective of pipe sch & thickness )So his work 2″Dia x 2 joint =4″Diafor 2″ =rate is 10 $Sofor 4″ =his rate 20$ ( welded 2″ pipe x 2 joint )for 6″ =his rate 30$ ( welded 2″ pipe x 3 joint )for 8″ =his rate 40$ ( welded 2″ pipe x 4 joint )
Why is the discharge pipe diameter of a centrifugal pump smaller than the suction pipe?
The suction pipe of a centrifugal pump is not necessarily a larger bore (diameter) than the discharge pipe. They can be the same size.However, the design philosophy differs slightly between the suction and discharge lines:Liquid lines are sized primarily on the basis of velocity. Typically, velocities are kept within the range 3 to 15 ft/s (approx. 1 to 5 m/s) as per API 14E.Suction lines are generally designed to keep friction losses to a minimum. This is in order to ensure sufficient available Net Positive Suction Head (NPSHa) to meet the NPSH required (NPSHr) by the pump. This is, in part, accomplished by using as large a diameter line as you can for the given service/conditions. (Other factors include minimising the number of bends and fittings, the use of long radius elbows, full bore valves, etc.)For discharge piping, sizing is determined by the available head and economic considerations.This often means that in practice the discharge line is one or two standard pipe sizes smaller than the suction line (but not necessarily).Edited to Add:Other standards that cover line sizing, such as NORSOK P-001, for example, specify different recommended maximum pressure drops for centrifugal pump suction and discharge lines.For a sub-cooled liquid P-001 recommends a maximum pressure drop of 0.25 bar / 100 m in the suction piping, but up to 0.9 bar / 100 m in the discharge piping. Depending on the exact configuration, this could allow for the discharge piping to be a smaller bore than the suction piping and still comply with the standard.