Write the slope-intercept inequality for the graph below. If necessary, use <= for <= or >= for >=?
its a simple algebra question, the slope from negative infinity to positive infinity goes from positive to negative, indicating a negative slope. The points given are (0,1) and (3,-1) using this, you can find the slope of the graph through rise/run. So: [1-(-1)]/(0-3) = 2/-3, which is the slope of the line Then, you know the y intercept is (0,1), so in the form y=mx+b, where m is slope and b is the y intercept, you have everything you need. The line is thus y=(-2/3)x+1 To find the correct sign for the inequality, simply sub a point within the shaded region to see if it is a true statement, a simple point would be (0,5) Sub in: 5=(-2/3)(0)+1 = 5=1 which would be a true statement if the equal sign was a greater than sign, so y>(-2/3)x+1 But the line is a solid line, indicating that its a greater than equal, so the correct answer is y>=(-2/3)x+1
Write the slope-intercept inequality for the graph below. If necessary, use <= for or >= for .?
y> 4/3 x + 4 I'm not sure, it's been a while since I've taken algebra. I looked at the shaded part to get the inequality, but I'm not sure if that's the wrong part to go by :/
Write the slope-intercept inequality for the graph below. If necessary, use <= for or >= for .?
Given two points (x₁,y₁) and (x₂,y₂), the line passing through them has slope m = (y₂-y₁)/(x₂-x₁) y-intercept b = y₁-mx₁ = y₂-mx₂ (x₁,y₁)=(1,2) and (x₂,y₂)=(3, -2) m = (y₂-y₁)/(x₂-x₁) = (-2-2)/(3-1) = -2 b = y₁-mx₁ = 2-(-2)1 = 4 y < mx+b y < -2x+4
Write the slope-intercept inequality for the graph below. If necessary, use <= or >=?
Find the dashed line first. Slope = (y1 - y2)/(x2 - x1) where the two points are (x1, y1) and (x2, y2). slope = (-3 - -1)/(-3 - 3) = -2/-6 = 1/3 Likewise, slope = (-1 - -3)/(3 - -3) = 2/6 = 1/3 Substitute either of the points for (x1, y1) and slope for m in y - y1 = m(x - x1) y - -1 = 1/3(x - 3) y + 1 = x/3 - 1 y = x/3 - 2 Test a point off the line to determine which inequality to use. (0, 0) is off the line and should be easy. 0 ? 0/3 - 2 0 ? -2 0 > -2 Therefore, the inequality is y > x/3 - 2
Write the slope-intercept inequality for the graph below. If necessary, use <= for or =>?
(-1 , -2) and (0 , 2) m = (2 - -2) / (0 - -1) m = (2 + 2) / (0 + 1) m = 4 y = 4x + b ---> (0 , 2) y = 4x + 2 y ≤ 4x + 2 ---> testing (10 , 0) 0 ≤ 4 * 10 + 2 0 ≤ 42 <--- true ======= free to e-mail if have a question
Help: Write the slope-intercept inequality for the graph below. If necessary, use <= for or >= for .?
http://media.apexlearning.com/Images/200706/18/d880a94e-a274-4ba0-a100-cc87097df54d.gif If necessary, use <= for or >= for . I've been stuck on this for a long time, please help. Thanks.
HELP CONFUSED! Write the slope-intercept inequality for (0,4) (-3,0)?
Write the slope-intercept inequality for the graph below. If necessary, use <= or >= the line is like this ---> / and shaded up HERE ARE THE POINTS (0,4) (-3,0) PLEASE HELP ASAP!
(Help) Write an inequality, in slope-intercept form, for the graph below. If necessary, use "<="?
I can write a slope intercept form equation, but not an inequality. I would need a picture of the graph to write an inequality. First find slope: (y2 - y1)/(x2 - x1) Slope is 3 Choose a point then use point slope form y - y1 = m(x - x1) It is y - 1 = 3(x - 1) Now simplify: y - 1 = 3(x - 1) y - 1 = 3x - 3 y = 3x - 2 Done! y = 3x - 2
Slope-intercept inequality for coordinates (0,2) and (-1,-2) using < or > please help!?
It's not clear to me what exactly you're asking. The line through (0, 2) and (-1, -2) has slope m given by m = (-2 - 2) / (-1 - 0) = -4 / -1 = 4 The general slope-intercept form of the equation for a line is y = mx + b so your equation is y = 4x + b In order to determine b, plug either point into the equation and solve it for b. For example, if we use the point (0, 2) (which happens to be the y-intecept) 2 = 4(0) + b 2 = b Therefore, the slope-intercept of the equation for the line passing through (0, 2) and (-1, -2) is y = 4x + 2 This line divides the xy-plane into two regions. In the region above the line, we have y > 4x + 2; in the region below the line, we have y < 4x + 2.