I BEG YOU help on 3 problems dealing with slope/distance formula?
Coordinates: A(4,6) B(6,-2) C(2,2) D(5,2) E(4,0) F(3,4) 17) Use the slope and the Distance Formula to verify that the Midsegment Theorem is true for /DF 18) Use the slope and the Distance Formula to verify that the Midsegment Theorem is true for /FE 19) Use the slope and the Distance Formula to verify that the Midsegment Theorem is true for /DE
Write an equation in point-slope form of the line through point J(4, 1) with slope –4.?
Use this formula: · Point – slope formula: y - y1 = m (x - x1) Your slope is -4 and your point is (x1 , y1)
Why/how does the b value appear in the point-slope formula?
okay. so basically, all the forms are derived from y=mx+b. b is the y intercept, where you begin. in point slope- (y-y)=m(x-x) you graph (x,y) and then go up and down according to slope. As soon as you hit a point that is (0,y) that's your b. idk if that's what you were looking for. sorry. I don't explain things well.
Regarding the slope of lines, can we simply define a horizontal slope to be the inverse of a vertical slope?
I very much agree with Curt that this is your show. Feel free to be creative, and then explore the logical consequences of what you want to try.Since the ordinary definition of slope works fine for horizontal lines, maybe define the slope of a vertical line as the reciprocal of the slope of a horizontal line? Then fewer things need their own special definition.Other perpendicular lines have slopes that are negative of the reciprocals of each other, so maybe say it that way? If a moving line approaches horizontal through positive slopes, for example, then its perpendicular lines have negative slopes approaching negative infinity.Mathematicians use the term “extended real numbers” (or the affine extended real numbers) when they want to adjoin positive and negative infinity to the reals. It’s useful for limits. There are still issues, though. 0 has two different reciprocals, positive and negative infinity. So maybe negative and positive 0’s?There is a whole field of mathematics called Non-Standard Analysis that explores infinitesimals and infinite nonstandard reals in a really cool (and logically completely consistent) way.
Write an equation in slope intercept form.?
The slope-intercept form for all linear equations is y=mx + b. "m" is the slope of the line (it's the coefficient of the x term, along with the sign), and b is where the line, when graphed, cuts the y-axis. This happens b units above or below the origin, and the coordinates of that intercept are (0,b). 1.) slope 0.25 ,passes through (0,4) Your equation is y=0.25x +4 You could have expressed the slope m as 1/4 if you so desired. y=(1/4)x +4 There is another way to find b as well. We shall see that way in your second question. 2.) passes through (-3,-1) parallel to the line that passes through (3,3) (0,6) Once again, your equation is y=mx +b. What we need to get are values for m and b. We know our desired line has the same slope as the line passing through (3,3)(0,6). And, we can find that line's slope. Slope is a measure of steepness. It's the vertical height change over a specific horizontal distance. You probably know this as RISE / RUN. For the points (3,3)(0,6) Rise is 6-3, RUN is 0-3 Therefore m= RISE / RUN = (6-3)/(0-3)=3/-3 = -1 Our sought-after line therefore also has a slope of -1 and our equation is now y=-1x+b Here is how we find b. We are told our line passes through (-3,-1). That means those values satisfy the equation y=-1x + b. I shall substitute -3 for x and -1 for y to get -1=-1(-3) +b b=-4 My equation is therefore y = -x-4, and we're done. Some extra tips to help you feel better about linear equations. Tip 1- If you are going to put, or use, the slope-intercept form of the line, it is y=mx +b. The y must ALWAYS be +1y, alone on the left side. Tip 2- A negative slope means that when graphed, the line leans to the left. Tip 3- Lines that are parallel to one another have the same slope. Tip 4- Lines that are perpendicular to one another have slopes that are the negative reciprocal of one another. If m of line 1= 3, the other line will have slope = -1/3 Good luck to you!
Write an equation in point-slope form of the line that passes through the given points?
y= (slope)x + b the slope = (y-y)/ (x-x)= (6-4)/ (17-9)= 0.25 I always solve for this first, so that I can check my answer in the formula. For the entire formula, use this formula using either of your points. y-y= (slope)(x-x) y-4= 0.25(x-9) y-4 = 0.25x - 2.25 y= 0.25 + 1.75 And our slope is correct!
What is the point and slope of the equation y+14=7(x-18)?
I will start by saying that an EQUATION does not have a slope, it defines a relationship! In this case it defines a relationship between the x and y coordinates of every point on the LINE with the given equation. Your question is better expressed as:What is the slope (or gradient) of the line which has the equation y+ 14 = 7(x - 18) and what are the coordinates of the point where it crosses the y axis?This question is easily dealt with if you already know that if the equation of a line is written in the form y = mx + c, then the gradient = m and it crosses the y axis at point ( 0, c).So, the first step is to rearrange the given equation so that it has the form y = mx + c.The given equation is y + 14 = 7(x - 18).Multiplying the content of the brackets by the multiplier 7, the equation becomes: y + 14 = 7x - 126.Now, by subtracting 14 from BOTH SIDES of this equation we find that y = 7x - 140.The original equation has now been transformed to the form y = mx + c.It can easily be seen that the gradient/slope, m = 7 and that c = - 140. So, the answer to the question is:The slope of the line is 7 and the line crosses the y axis at the point (0, - 140).
Check each correct statement of the Slope formula? Multiple choice.?
A)Slope= y1-y0/x1-x0 B)Slope= Run/Rise C)Slope= y-y0/ x1-x2 D) Slope=y1-x0/y1-x0 E)Slope= Rise/Run F) y1-y0/ x1+x0 Please this is a algebra 2 question I'll give Best answer & 5-30 points depending on Answers thank!
Write the equation of a line in slope-intercept form that is parallel to the line 2x-5y= -8 and containing po?
First you have to convert it to a slope-intercept form to do that you need to get the y by itself. Subtract the 2x first. 2x - 5y = - 8 - 2x -2x -5y = -2x -8 Then divide by -5 to get the y alone. -5y = -2x -8 -5/-5y = -2x - 8 / -5 y = - 2/5 x - -8/5 Answer: y = -2/5x + 8/5 Since you want the paralell slope you keep the same sign of the original slope. When you are trying to find the perpindecular you change it.